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AP State Syllabus AP Board 7th Class English Textbook Solutions Chapter 3A Puru, the Brave Textbook Questions and Answers.

AP State Syllabus 7th Class English Solutions Chapter 3A Puru, the Brave

7th Class English Chapter 3A Puru, the Brave Textbook Questions and Answers

Look at the picture and answer the questions that follow.

Question 1.
Talk about what is happening in the picture.
Answer:
It is the scene of a fierce battle of ancient times. It appears to be completely an Indian battle. The soldiers of both the sides of the battle are using the old instruments of warfare – swords, daggers and spears. Battle is going on fiercely. The soldiers are slashing their swords with lightning speed. Though they are well armoured the soldiers of both sides are wounded seriously. Their heads are cut off. Some lost their limbs. The battle field must have become red with the bloodshed.

Question 2.
What do you think may be the cause of the war?
Answer:
The thirst of conquering the other’s kingdom.

Question 3.
Who is Puru? What do you know about him?
Answer:
Puru is a brave king. He fights bravely. He is patriotic and a man of self-respect.

I. Answer the following questions.

Question 1.
Who is Alexander?
Answer:
Alexander is the King of Macedonia.

Question 2.
Why did the generals and Alexander think that the battle of Jhelum would go down in the history of the world?
Answer:
They thought that it would go down in the history of the world because they had never fought such a battle before. Every Indian soldier fought like a hungry tiger. The Greeks had to fight hard until Puru was injured and captured.

Question 3.
What do you think is the reason for Indian soldiers’ defeat?
Answer:
Indian soldiers fought bravely like tigers. But the generals were not so skilful as the Greek generals. They followed the old methods of warfare. They depended more upon their elephants. So they were defeated.

Question 4.
Do you think that Indian generals were not as brave as the Greek generals?
Answer:
No, I don’t hink so. Our Indian generals were braver than the Greek generals. Even Alexander himself admitted this fact and said he had the highest respect for them.

Question 5.
Do you believe that Puru was really proud ? Give reasons. Do you justify his pride? How?
Answer:
No. Puru was not really proud. He was a man of self-respect. He showed how a king should behave with another king. He did not misbehave with Alexander. Moreover he greeted Alexander when he entered the court. Thus his pride was justifiable.

Question 6.
If you were Alexander, what would you do with Puru?
Answer:
If I were Alexander, I too would behave like Alexander. I mean that Alexander respected and honoured Puru in apt way 1 too would like to have friendship with Puru.

II. Tick (✓) the correct answers.

1. Alexander asked his soldiers to remove the chains of Puru because ( )
a) he was sympathetic to Puru.
b) he did not like a brave man like Puru in chains.
c) Puru requested Alexander to remove his chains.
d) Alexander did not dare see Puru in chains.
Answer:
b) he did not like a brave man like Puru in chains.

2. Puru did not accept Alexander’s proposal to be a vassal because ( )
a) he was very proud.
b) he was very brave and patriotic,
c) he was not very wise.
d) he did not have respect for Alexander.
Answer:
b) he was very brave and patriotic

3. Alexander made friends with Puru because, ( )
a) Puru accepted that Alexander was really great.
b) Alexander wanted to make use of Puru’s services.
c) Alexander liked Puru’s bravery and self-respect.
d) Alexander was very kind.
Answer:
c) Alexander liked Puru’s bravery and self-respect.

4. Alexander was really great because, ( )
a) he defeated Puru.
b) he made friends with a brave king like Puru. .
c) he defeated Puru, set him free, respected, and made friends with him.
d) he was the conqueror of the world.
Answer:
c) he defeated Puru, set him free, respected, and made friends with him.

I. Pick out the antonyms from the text for the words given below.

Answer:
1) defeat
2) brave
3) proud
4) reject
5) independent

II. Fill in the blanks in the following paragraph with the words given in the box.

I know that you are very ……………………… and ………………………. of the position you hold. But I am really ………………….. to know that you feel as though you have ……………… the world. These days nobody is being …………………. by the other. I would like to make a ……………………. so that you will ……………………. humble and ………………… I hope my words …………………. your imagination and you ………………….. me as your teacher.
Answer:
1) skilful
2) worthy
3) amazed
4) conquered
5) frightened
6) proposal
7) remain
8) lawful
9) capture
10) respect

III. Look at the following words from the text: 1. independent 2. difference

The word ‘precaution’ consists of two parts – ‘in-’ and ‘dependent’ (prefix+root).
The word ‘dangerous’ consists of two parts ‘differ’ and ‘-ence’ (root+suffix).
Add appropriate prefixes / suffixes to the following roots to make new words. The first one is done for you

Answer:

Fill in the blanks in the following sentences with suitable forms (after adding a prefix/suffix) of the words in brackets.
1. He was acting in a very ——– way. (child)
2. This word is very difficult to spell, and even worse, its ——–. (pronounce)
3. You shouldn’t have done that! It was very ——– of you. (think)
4. He didn’t pass his exam. He was ——– in the second attempt. (succeed)
5. Some of the Indian cities are dreadfully ——–.(crowd)
6. The team won the ——–. (champion)
7. There is a very high ——– that they will be late, (likely)
8. I couldn’t find any ——– in his theory, (weak)
9. There was a three-hour ——– because of the strike, (stop)
10. You need a ——– of motivation, organization and revision to learn English.(combine)
Answer:
1) childish
2) pronunication
3) ill thinking
4) successful
5) crowdy
6) championship
7) likelihood
8) weakness
9) stoppage
10) combination

Grammar

I. Let’s have a look at the following sentences from the text.

1. My kingdom should remain independent.
2. You should treat me as your equal.
3. I must say every Indian soldier fought like a tiger.
In sentence 1, should indicates obligation whereas in 2, it indicates condition.
In sentence 3, “must’ is used to indicate insistence on the part of the speaker / necessity.
It is also used when the speaker has authority over the listener.
It is important to understand how the modals ‘should’ and ‘must’ are used.
(People sometimes use should to indicate something that is desirable and must to indicate obligation. However, some people use them interchangeably.)

Now fill in the blanks in the following paragraph with ‘should or ‘must’.

I –(1)– say that you –(2)– come to school regularly because you cannot miss important lessons. You –(3)– attend extra classes in time tomorrow. Otherwise I will punish you. You –(4)– return my book which I gave you month ago. You –(5)– change your habits otherwise you will not come up in life.
Answer:
1) should
2) must
3) must
4) must
5) should

Now read the conversation between a doctor and a patient and fill in the blanks with should (should not) and must (must not).

Doctor: Mr. Rao, what exactly is your problem?
Patient: I’ve been suffering from gastric problem for a long time.
Doctor: Mr. Rao, I (1)………. say you (2)………. eat non-vegetarian or spicy food for sometime.
Patient: Can I eat boiled eggs or omelette, doctor?
Doctor: Isn’t an egg non-vegetarian ? You (3)………. eat any non-vegetarian food for quite some time. In fact, you (4)………. have stopped eating it long ago. You (5)……….. consult me in a week.
Patient: I am sorry, doctor. I won’t eat non-vegetarian food any longer. You are quite correct, doctor. I (6)………. take your advice and (7)………. avoid eating non-vegetarian and spicy food. Thank you very much, doctor.
Doctor: You are welcome. In think you (8)………. remember my advice.
Answer:
1) must
2) should not
3) must hot
4) should
5) must
6) must
7) must
8) should

II. Look at the following sentences from the text:

1. But their generals are not so good as ours.
2. The Indian generals are not so skillful as the Greek generals.
3. It has been a great battle – perhaps the greatest of my life.

In the above sentences 1&2, the Indian generals are compared with Greek generals. The third sentence means that it was the greatest or the best battle of all his (Alexander’s) battles. When we want to compare one thing with the other, we use degrees of comparison – positive, comparative and superlative forms of adjectives.

If we compare two things or two sets of things, we use positive or comparative forms of adjectives. If we compare more than two things or two sets of things, we use the superlative form of adjectives. We can transform positive, (comparative and superlative degrees) into comparative and superlative and vice versa.

Let us observe the sentences 1 and 2 above.
1. Their generals are not so good as ours.
2. Indian generals are not so skillful as the Greek generals.

The underlined words in the above sentences are adjectives. These are the positive forms of adjectives. The other forms of these adjectives are given below.
Positive              Comparative                   Superlative
good                     better                               best
skillful                 more skillful                   most skillful

The two sentences are said to be in the positive degree since the adjectives are in the positive degree.
They can be transformed into comparative degree by changing the adjectives into comparative degree and making certain other changes.
Sentences 1 and 2 can be changed into comparative forms as shown below:
1. Our generals are better than their generals.
2. The Greek generals are more skillful than Indian generals.

Now look at the third sentence.
It is the greatest battle of my life.
The above sentence can be turned into the comparative and positive degrees as shown below.
It is greater than any other battle of my life.
No other battle of my life is so great as this.

Now look at the following sentence in the superlative degree of comparison:
Puru is one of the bravest kings in the world.
This sentence means that there are a few kings in the world who are as brave as Puru. It also means that Puru is not the only bravest king in the world. Let’s see how the above sentence can be transformed into comparative and positive degrees of comparison.

Puru is braver than many other/ most of the other kings in the world (Comparative)
Very few kings in the world are as brave as Puru. (Positive Degree)

Observe the following forms of comparison of some adjectives.

Positive Degree	Comparative Degree	Superlative Degree
nice	nicer	nicest
short	shorter	shortest
big	bigger	biggest
great	greater	greatest
fast	faster	fastest
worthy	worthier	worthiest
frightened	more frightened	most frightened
lawfyl	more lawful	most lawful
brave	braver	bravest

Change the following sentences into other forms of comparison as indicated in brackets.

1. Rahul Dravid is one of the greatest batsmen in the world. (comparative degree)
Answer:
Rahul Dravid is greater than many other batsmen in the world.

2. Alexander was the greatest soldier in the world. (positive degree)
Answer:
No other soldier in the world was as great as Alexander.

3. India is one of the fastest developing countries in the world. (comparative degree)
Answer:
India is developing faster than many other countries in the world.

4. No other river in the world is so long as the Nile. (superlative degree)
Answer:
The Nile is the longest river in the world.

5. Hindi is one of the most popular languages in India. (positive degree)
Answer:
Very few languages in India are as popular as Hindi.

6. Lara is not so great as Tendulkar. (comparative degree)
Answer:
Tendulkar is greater than Lara.

7. Rekha is one of the most beautiful girls in the class. (positive degree)
Answer:
Very few girls in the class are as beautiful as Rekha.

8. Very few metals are as expensive as platinum. (comparative degree)
Answer:
Platinum is more expensive than many other metals.

9. Shimla is colder than all other hill stations in the Himachal Pradesh. (superlative degree)
Answer:
Shimla is the coldest hill station in Himachal Pradesh.

10. Delhi is one of the most crowded cities of India. (positive degree)
Answer:
Very few cities of India are as crowded as Delhi.

Writing

I. Given below are some jumbled sentences. Rearrange them in the right order and write a meaningful paragraph by using appropriate connectives.

1. Alexander asked Puru why he had rejected his offer.
2. Alexander defeated many kings besides Puru, became the world conqueror, and was called Alexander the Great.
3. Alexander was born in Greek and he was the disciple of the greatest Greek philosopher, Aristotle.
4. Puru lost the battle though his generals and soldiers fought very bravely.
5. Alexander asked his generals to remove the chains and bring Puru to him.
6. Puru killed more than one hundred soldiers but he was gravely injured and chained in the battle.
7. Puru lost the battle as he had used the oldest methods of warfare and elephants.
8. Puru said that he was the lawful owner of his kingdom.
9. Puru was a brave king and a great soldier of Northern India.
10. Alexander liked Puru’s bravery and self-respect , so he became his best friend.
11. There was a great battle between Alexander and Puru on the banks of Jhelum.
12. Alexander asked Puru to be his vassal but he refused.
Answer:
1. Alexander was born in Greek and he was the disciple of the greatest Greek philosopher, Aristotle. (3)
2. Puru was a brave king and a great soldier of Northern India. (9)
3. Alexander asked Puru to be his vassal but he refused. (12)
4. There was a great battle between Alexander and Puru on the banks of Jhelum. (11)
5. Puru killed more than one hundred soldiers but he was gravely injured and chained in the battle. (6)
6. Puru lost the battle though his generals and soldiers fought very bravely. (4)
7. Puru lost the battle as he had used the oldest methods of warfare and elephants. (7)
8. Alexander asked his generals to remove the chains and bring Puru to him. (5)
9. Alexander asked Puru why he had rejected his offer. (1)
10. Puru said that he was the lawful owner of his kingdom. (8)
11. Alexander liked Puru’s bravery and self-respect, so he became his best friend. (10)
12. Alexander defeated many kings besides Puru, became the world conqueror, and was called Alexander the Great. (2)

Forming a paragraph by placing the jumbled sentences in the right order:

Alexander was born in Greek and he was the disciple of the greatest Greek philosopher, Aristotle. Puru was a brave king and a great soldier of Northern India. Alexander asked Puru to be his vassal but refused. So there was a great battle between Alexander and Puru on the banks of Jhelum. Puru killed more than one hundred soldiers but he was gravely injured and chained in the battle. Puru lost the battle though his generals and soldiers fought very bravely. He lost the battle because he had used the oldest methods of warfare and elephants Alexander asked his generals to remove the chains and bring Puru to him. He asked Puru why he had rejected his offer. Puru said that he was the lawful owner of his kingdom. So he rejected the offer of being his vassal. Alexander liked Puru’s bravery and self respect, so he became his best friend Alexander defeated many Kings besides Puru, became the world conqueror, and was called Alexander the great.

II. Rewrite the playlet as a short story. You may follow the steps given below :
Read the drama script as many times as necessary.

Answer the questions that follow.

Question 1.
Identify the major events depicted in the drama.
Answer:
Alexander asked Puru to be his vassal – great battle between Puru and Alexander – Puru lost the battle – Puru refused to be a vassal – Puru greatly injured, captured – chained – Puru used the oldest methods of warfare – Puru’s generals and soldiers fought bravely – Puru was / brought before Alexander – Alexander liked Puru’s bravery and self-respect – made friends with Puru.

Question 2.
Take turns and share the major events in the order they occur.
Answer:

1. Alexander asked Puru to be his vassal.
2. Puru refused to be a vassal.
3. Great battle between Puru and Alexander.
4. Puru’s generals and his soldiers fought bravely.
5. Puru used the oldest methods of warfare.
6. Puru lost the battle.
7. Puru greatly injured, captured and chained.
8. Puru was brought before Alexander.
9. Alexander liked Puru’s bravery and self-respect.
10. Made friends with Puru.

Question 3.
Expand each event in terms of:
a) the location where it takes place
b) the characters involved
c) what they say / think / involved
Answer:
a) Expanding the events in terms of the location where its takes place:
3. There was a great battle between Puru and Alexander on the banks of the river Jhelum:
4. Puru’s generals and soldiers fought bravely in the battle field.
8. Puru was brought before Alexander where he was conducting his camp court.

b) Expanding the events in terms of the characters involved:
1. Alexander was the king of Macedonia. His aim was to conquer the whole world.
2. Puru was a king of Northern India.

c) Expanding the events in terms of the characters what they say / think / feel.
At the camp court of Alexander, Alexander and his generals were discussing how bravely Puru and his soldiers fought. Generals said that the battle of Jhelum went down in the history of the world. Alexander admitted that it was the greatest battle he had ever fought. Alexander thought Puru’s faulty battle plans, using old methods of warfare and depending too much on elephants were the causes for Puru’s defeat.

Meanwhile Puru was brought before Alexander. Alexander asked him why he had rejected his offer to be his vassal while all the other kings gladly agreed to do so. Then Puru told that none of them was Puru.
Alexander asked Puru how he’ should treat him. Puru aksed him to treat him as a king should treat another king. .

Question 4.
Write the first draft.
Answer:
Alexander was the king of Macedonia. His aim was to conquer the whole world. Puru was a king of Northern India. Alexander asked Puru to be his vassal. Puru refused Alexander’s offer.

1. There was a battle between Alexander and Puru on the banks of the river Jhelum. Puru and his generals fought bravely at the battle field. Puru was greatly injured.
2. He was captured and he was chained. He lost the battle. At the camp court of Alexander, Alexander and his generals were discussing how bravely Puru and his soldiers fought. The generals opined that the battle of Jhelum would go down in the history of the world. Alexander admitted that it was the greatest battle he had ever fought. He thought that Puru’s faulty battle plans, his using of other oldest methods of warfare and depending too much on elephants were the causes for Puru’s defeat.
3. Puru was brought before Alexander. Alexander asked his soldiers to remove his chains. He asked Puru why he had refused to be his vassal, while all other kings gladly agreed to so. Then Puru told that he was not a traitor like them. Alexander liked Puru’s bravery and self respect.
   He asked Puru how he should treat him. Puru asked him to treat him as a king should treat another king. Alexander asked him whether he would be a friend to him. Puru agreed to be his friend only when Alexander agreed to keep his kingdom independent.
4. Conclusion to be added.

Question 5.
Edit and refine the draft.
Answer:

1. So there was a great battle between Alexander and Puru on the banks of the river Jhelum.
2. Puru was greatly injured, captured and chained.
3. Meanwhile Puru was brought before Alexander after removing his chains.
4. Thus the battle of Jhelum really went down in the history of the world. And Puru was remembered for his bravery, and for his sense of patriotism and self-respect.

Final draft:
Alexander was the king of Macedonia. His aim was to conquer the whole world. Puru was a king of Northern India. Alexander asked Puru to be his vassal. Puru refused Alexander’s offer. So there was a great battle between Alexander and Puru on the banks of the river Jhelum. Puru and his generals fought bravely at the battle field.

Puru was greatly injured, captured and chained. He lost the battle. At the camp court of Alexander, Alexander and his generals were discussing how bravely Puru and his soldiers fought. The generals opined that the battle of Jhelum would go down in the history of the world. Alexander admitted that it was the greatest battle he had ever fought. He thought that Puru’s faulty battle plans, his using of the oldest methods of warfare and depending too much on elephants were the causes for Puru’s defeat.

Meanwhile Puru was brought before Alexander after removing his chains. He asked Puru why he had refused to be his vassal, while all other kings gladly agreed to do so. Then Puru told that he was not a traitor like them. Alexander liked Puru’s bravery and self-respect.

He asked Puru how he should treat him. Puru asked him to treat him as a king should treat another king. Alexander asked him whether he would be a friend of him. Puru agreed to be his friend only when Alexander agreed to keep his kingdom independent.

Thus the battle of Jhelum really went down in the history of the world and Puru was remembered for his bravery, and for his sense of patriotism and self-respect.

Study Skills

There are many words which can function as more than one part of speech. For instance ‘talk’ can be used as a verb as well as a noun.
She talks at length about her dress.
Her talk is boring.

I. Refer to the dictionary and say whether the following words can be used as different parts of speech like a noun, a verb, an adjective, etc. The first one is done for you.

Answer:

Usage:
1. battle (n): The battle of Waterloo took place in 1815.
battle (v): She is still battling with her knee injury.
battle (adj): He ran away from the battle field.
2. chain (n): She wore a heavy gold chain.
chain (v): She chained the dog and welcomed us in.
3. conquer (v): Ashoka conquered Kalinga.
4. fight (v): We must fight against corruption.
fight (n): He put up a fight when the police tried to arrest him.
5. like (n): We all have different likes and dislikes.
like (prep): She is wearing a dress like mine.
like (v): I like sweets.
like (adj): She responded in like manner.
like (adv): it’s really hard. Like I have no time for my own mork.
like (conj): It didnt turn out like I intended.
6. refuse (v): She refused to accept that there was aproblem.
refuse (n): Municipal authorities asked the people to keep their domestic refuse in the
bins provided by the Municipality.
7. reject (v): The proposa! was firmly rejected.
reject (n): Mother Teresa used to serve the family rejects and the society rejects.
8. respect (n): 1 have the greatest respect for your brother.
respect (v): She had always been honest with me and I respect her for that.
9. talk (v): She talks at length about her dress.
talk (n): Her talk is boring.
10. treat (v): My parents still treat me like a child.
treat (n): We took the kids to the zoo as a special treat.

Listening and Speaking

Your teacher will read the passage “Nepal and the Himalayas”. Listen carefully and answer the questions given below:

Nepal lies between India and Tibet, among the Himalayan mountains. It is a country of mountains and valleys. The tallest mountain in the world, Mount Everest, is in Nepal. And there are several other mountains nearly as high. When mountaineers try to climb Mount Everest, they take the help of the Sherpas, who live in these mountains, to carry heavy loads and to act as guides.

A long time ago, the Sherpas crossed over the mountains from Tibet and made their homes along the slopes of the Himalayas in Nepal. So, they are rather like the people of Tibet to look at. Here, life is hard, and the entire family, including the children, have to work to get enough to eat.

The Sherpas grow potatoes, barley, garlic, and other vegetables. They also graze their yaks on the higher mountain slopes in the summer and on the lower slopes in the winter. The Sherpas use them for almost everything they need. They ride them, plough with them, and use them to carry their goods. The hairy wool of these animals is made into cloth and their skins into leather boots and tents. The yaks also provide milk, fat and meat. Their dung is dried and used as a fuel instead of wood or coal.

There are hardly any roads in the Himalayas, and everything has to be carried either on animals like yaks and donkeys or on human backs. Even children learn to carry heavy loads in large baskets which are tied to them. The baskets are big enough to carry a person.

The highest mountain tops of the Himalayas are cold, cheerless and covered with snow, but lower down one can find flowers in the spring and summer, and fir trees too. There are colourful butterflies, kites and eagles in the skies, and black and red Himalayan bears hiding in the rocks.

Though the Sherpas lead a tough life in their beautiful country, these small, dark haired people are always cheerful, and like most Buddhist people, they are friendly and kind.

Choose the right answer from the choices given below:

1. The passage is about . . . . . . . . . . . . . . . . . . ( )
a) Nepal
b) the Himalayas
c) the Himalayas and the Sherpas
d) none of these
Answer:
c) the Himalayas and the Sherpas

2. The Sherpas came from . . . . . . . . . . . . . . . . . . ( )
a) Nepal
b) Tibet
c) China
d) none of these
Answer:
b) Tibet

3. Lower down the Himalayas we can see . . . . . . . . . . . . . . ( )
a) colourful butterflies
b) kites
c) eagles
d) all of these
Answer:
d) all of these

4. The most useful animals for Sherpas are . . . . . . . . . . . . . . . . ( )
a) cows
b) buffaloes
c) yaks
d) none of these
Answer:
c) yaks

II. Read the following sentences and say whether they are true or false.

1. Mount Everest is iri India. ( )
2. There are many roads in the Himalayas. ( )
3. Even the children of Sherpas carry heavy loads. ( )
4. One can find flowers on the tops of the Himalayas. ( )
Answer:
1) False
2) False
3) True
4) False

Work in groups. Ask and answer the following questions:

Question 1.
What are the modes of transport in the Himalayas?
Answer:
Animals like yaks and donkeys or on human backs.

Question 2.
Why do Sherpas look like the people of Tibet?
Answer:
A long time ago, the Sherpas crossed over the mountains from Tibet and made their homes along with the slopes of the Himalayas in Nepal. So they look the people of Tibet.

Question 3.
What interesting things would you find in the Himalayas?
Answer:
There are hardly any roads in the Himalayas. Everything has to be carried either on animals like yaks and donkeys or on human backs. The highest mountain tops of the Himalayas are a cold, cheerless and covered with snow, but lower down one can find colourful butterflies, kites and eagles in the skies.
Listen to the following conversation:
Teacher: Meghana! Have you ever been to the Himalayas?
Meghana: No, Sir. I have never been to the Himalayas.
Teacher: Do you have any idea about the Himalayas?
Meghana: Yes, I do.
Teacher: Tell me whatever you know about it.
Meghana: Sir, the Himalayas are the highest mountains in the world.
Teacher: Oh! Are they? Then tell me which is the highest peak among them?
Meghana: Mount Everest, Sir.
Teacher: What sort of help is available to the climbers in the Himalayas?
Meghana: Sir, there are plenty of Sherpas.
Teacher: Who are these Sherpas?
Meghana: Sir, they are helpers in the mountains.
They carry our luggage to earn their living.
Teacher: Good. Meghana.
Meghana: Thank you, sir.

Work in groups and share your experiences about the place you have visited. You may talk about the following:

• The hill station you visited
• How you travelled
• When was it? Where did you stay?
• Who went with you?
• The places you visited. The places you liked and disliked.
• Any memorable experience or anecdote.

Answer:
A: Let’s talk about the places we visited.
B: Yes. To start with, I visited Lakshmi Narasimha Swami temple in Antharvedhi.
C: I had been to Papikondalu.
D: We once went to Ooty.
A: Shall we talk about our mode of travel?
B: Yes, of course! We travelled by a taxi.
C: I went there partly by bus and partly by boat.
D: Our journey was by train and car.
A: May I ask you where you stayed?
B: We stayed in a hotel.
C: We didn’t stay overnight. Our visit was of a few hours.
D: We booked accommodation in a private guest house.
A: Who accompanied you?
B: We all went with the members of our family.
C: We all went with the members of our family.
D: We all went with the members of our family.
A: What places did you see there?
B: M the important.places like lakes, temples, etc. we covered
C: All the important places like lakes, temples, gardens, hill stations we covered …
D: All the important places like lakes, temples, gardens, hill stations we covered …

Puru, the Brave Summary in English

Alexander was the King of Macedon. He conquered Greece, Persia etc. He also made several Indian kings his vassals.
Puru was a king of northern India. He was a brave soldier and a true patriot.

Alexander wanted to make Puru his vassal. So he sent Puru an offer that he would not fight a battle with Puru if he agreed to be his vassal. But Puru rejected his offer. So a great battle occurred between Alexander’s army and Puru’s army. It was such a great battle that Alexander’s army had to sweat a lot and strive their best to defeat Puru’s army. Every Indian soldier fought like a tiger in the battle. The Indian soldiers and generals fought more bravely than the Greek soldiers and generals. Bu the Indian generals were less skilful than the Greek generals. They followed the old methods of warfare. They depended too much on their elephants. At last the Greek were able to defeat Puru’s army.

Puru continued to fight even when others had left the field. Puru killed at least a hundred Greek soldiers with his sword. But he was injured badly and so the Greek generals were able to capture him. Puru was chained and brought to the camp of Alexander, on the banks of the Jhelum.

Alexander in his camp was discussing with his Greek generals how the battle of Jhelum went on. Alexander and the generals admitted that the battle of Jhelum would go down not only in the history of their country but also in the history of the world. Everone praised the Indian army for their bravery and great fight but pitied them for their poor, old methods of warfare.

Meanwhile, a soldier came there and said that Puru had been brought to the camp, in chains. Then Alexander said that Puru was a king and a king should not be brought, in chains. So he ordered them to remove the chains and bring him there. Pure came.

Alexander asked Puru why he had rejected his offer. Puru replied that he was a lawful king and so he would never like to be a vassal. Puru said that a patriotic king ought to be proud of being a king otherwise he could not be a king. Alexander admired Puru’s bravery and self-respect. So he said that he wanted to make friends with Puru. Puru said that he would agree to be so provided his kingdom remained independent and Alexander treated him as his equal. Alexander gave him back his kingdom and made friends with Puru. Puru admired the personality of Alexander and called him, Alexander the Great.

Puru, the Brave Glossary

go down (phr.v): to be recorded

Your Highness (n): a title of respect used when talking to or about a member of the Royal family

warfare (n): the act of fighting a war

Your Majesty: the way of addressing Roya’ people

vassal (n): a man promising to fight for a king in return for the right to hold land

conquered (v): captured

battle (n): war

believe (v): think something is true

perhaps (adv): probably

brave (adj): courageous / bold / dare

faulty (adj): wrong

amazed (v): wondered / astonished

injured (v): hurt badly / wounded badly

besides (prep): in addition to

return (v): give back

softly (adv): gently

 

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 6 Basic Arithmetic InText Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 6th Lesson Basic Arithmetic InText Questions

Check Your Progress (Page No. 84)

Question 1.
Express the terms 45 and 70 by using ratio symbol.
Solution:
Given terms are 45 and 70
Ratio = 45 : 70
It can be read as 45 is to 70.

Question 2.
Write antecedent in the ratio 7:15.
Solution:
Given ratio 7 : 15
In the ratio first term is called antecedent.
In 7 : 15 antecedent is 7.

Question 3.
Write the consequent in the ratio 8 : 13.
Solution:
Given ratio 8 : 13
In the ratio second term is called consequent.
In 8 : 13 consequent is 13.

Question 4.
Express the ratio 35 : 55 in the simplest form.
Solution:
Given ratio 35 : 55 (or)
To write the ratio in the simplest form we have to divide by the common factor of two terms 35 and 55.
Common factor is 5.
Now divide by 5,
\(\frac{35}{55}=\frac{35 \div 5}{55 \div 5}=\frac{7}{11}\)
Simplest form of \(\) is \(\frac{7}{11}\)

Question 5.
In the given figure, find the ratio of
i) Shaded part to unshaded parts.
ii) Shaded part to total parts,
iii) Unshaded parts to total parts.

Solution:
i) In the given figur.e,
Number of shaded parts = 1
Number of unshaded parts = 3
Ratio = shaded parts : unshaded parts = 1:3

ii) Number of shaded parts = 1
Total parts = 4
Ratio = shaded parts : total parts = 1:4

iii) Number of unshaded parts = 3
Total parts = 4
Ratio = unshaded parts : total parts = 3:4

Question 6.
Express the following in the form of ratio.
a) The length of a rectangle is triple its breadth. ‘
b) In a school, the workload of teaching 19 sections has been assigned to 38 teachers.
Solution:
a) Let breadth of rectangle = x or one part = 1 part
length of rectangle = triple the breadth
= 3 x x = 3x = 3 parts
Ratio = l : b = x : 3x =\(\frac{1 x}{3 x}=\frac{1}{3}\) = 1:3

b) Given number of sections = 19
Number of teachers = 38
Ratio = 19 : 38 = \(\frac{19}{38}=\frac{1}{2}\) = 1 : 2

(Page No. 88)

Question 1.
Which ratio is larger in the following pairs ?
(a) 5 : 4 or 9 : 8
(b) 12 : 14 or 16 : 18
(c) 8: 20 or 12: 15
(d)4:7 or 7:11
Solution:
a) 5 : 4 or 9 : 8
Write the given ratios as fractions, we have 5 : 4 = \(\frac{5}{4}\) and 9 : 8 = \(\frac{9}{8}\)
Now find the LCM of the denominators of 4 and 8 is 8.
Make the denominator of the each fraction equal to 8.
We have \(\frac{5}{4} \times \frac{2}{2}=\frac{10}{8}\) and \(\frac{9}{8} \times \frac{1}{1}=\frac{9}{8}\)
Clearly we know that 10 > 9
∴ \(\frac{10}{8}>\frac{9}{8}\) (or) 10 : 8 > 9 : 8
10 : 8 is equal to 5 : 4
Therefore the larger ratio is 5 : 4.

b) 12 : 14 or 16:18
12 : 14 = \(\frac{12}{14}=\frac{6}{7}\) and 16 : 18 = \(\frac{16}{18}=\frac{8}{9}\)
Now find the LCM of the denominators of 7 and 9 is 63.
Make the denominator of the each fraction equal to 63.
we have \(\frac{6}{7} \times \frac{9}{9}=\frac{54}{63}\) and \(\frac{8}{9} \times \frac{7}{7}=\frac{56}{63}\)
Clearly, we know that 54 < 56
∴ \(\frac{54}{63}<\frac{56}{63}\) (or) 54:63 < 56:63
56 : 63 is equal to 16 : 18 (or) 8 : 9
∴ The larger ratio is 16 : 18.

c) 8 : 20 or 12 : 15
Write the given ratios as fractions we have
8:20 = \(\frac{8}{20}=\frac{2}{5}\) and 12:15 = \(\frac{12}{15}=\frac{4}{5}\)
\(\frac{2}{5}\) and \(\frac{4}{5}\)

Clearly \(\frac{2}{5}\) < \(\frac{4}{5}\)
i.e., 2:5 < 4 : 5 (or) 8: 20 < 12: 15
Therefore the larger ratio is 12 : 15.

d) 4: 7 or 7: 11
Write the given ratios as fractions, we have 4 7
4 : 7 = \(\frac{4}{7}\) and 7:11 = \(\frac{7}{11}\) .
Now find the LCM of the denominators of 7 and 11 is 77.
Make the denominators of the each fraction equal to 77.
We have \(\frac{4}{7} \times \frac{11}{11}=\frac{44}{77}\) and \(\frac{7}{11} \times \frac{7}{7}=\frac{49}{77}\)
\(\frac{44}{7}\) and \(\frac{49}{77}\)
Clearly we know that 44 < 49
∴ \(\frac{44}{77}<\frac{49}{77}\) (or) 44 : 77 < 49 : 77
i.e.,4: 7 < 7 : 11
Therefore the larger ratio is 7 : 11

Question 2.
Find three equivalent ratios of 12 : 16.
Solution:
Given ratio is 12 : 16
Write the given ratio as fraction we have 12:16= \(\frac{12}{16}=\frac{3}{4}\)
Now, write equivalent fractions of \(\frac{3}{4}\)

i. e., 6 : 8 = 9 : 12 = 12 : 16 = 15 : 20 = 18 : 24
∴ Equivalent ratios of 12 : 16 are 6 : 8, 9 : 12, 12 : 16, 15 : 20 and 18 : 24.

(Page No. 90)

Question 1.
Check whether the following terms are in proportion ?
1) 5,6,7,8
2) 3,5,6,10
3) 4,8,7,14
4) 2,12,3,18
Solution:
1) Given, 5, 6, 7, 8
If a, b, c, d are in proportion i.e., a : b :: c : d
If 5, 6, 7, 8 are in proportion i.e., 5 : 6 : : 7 : 8
We know that, product of extremes = Product of means [a x d : b x c]
5 x 8 = 6 x 7
40 ≠ 42
So, 5, 6, 7, 8 are not in proportion.

2) Given, 3, 5, 6, 10
If a, b, c, d are in proportion i.e., a : b :: c : d
If 3, 5, 6, 10 are in proportion i.e., 3 : 5 :: 6 : 10
We know that, product of extremes = Product of means a x d = b x c
3 x 10 = 5 x 6
30 = 30
So, 3, 5, 6, 10 are in proportion.

3) Given, 4, 8, 7, 14.
If a, b, c, d are in proportion i.e., a : b : : c : d
If 4, 8, 7, 14 are in proportion i.e., 4 : 8 : : 7 : 14
We know that, product of extremes = Product of means a x d = b x c
4 x 14 = 8 x 7
56 = 56
So, 4, 8, 7, 14 are in proportion.

4) Given, 2, 12, 3, 18
If a, b, c, d are in proportion i.e., a : b :: c : d
If 2, 12, 3, 18 are in proportion i.e., 2 : 12 : : 3 : 18
We know that, product of extremes = Product of means [ a x d = b x c ]
2 x 18 = 12 x 3
36 = 36
So, 2, 12, 3, 18 are in proportion.

Let’s Explore (Page No. 92)

Question 1.
Read the table and fill in the boxes.

Prepare two similar problems and ask your friend to solve them
Solution:

Weight	Cost of Tomato	Cost of Potato
5 kg	₹ 75	₹ 60
1 kg	₹15	₹ 12
3 kg	₹ 45	₹ 36

(Page. No. 94)

Question 1.
Represent the following in other forms.

Solution:

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 5 Fractions and Decimals InText Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 5th Lesson Fractions and Decimals InText Questions

(Page No. 63)

Question 1.
Is it true to say that 3 × \(\frac{1}{5}=\frac{1}{5}\) x 3?
Solution:
3 × \(\frac{1}{5}=\frac{1}{5}\) × 3. Yes, it is true.
By using commutative property over multiplication a × b = b × a
3 × \(\frac{1}{5}=\frac{1}{5}\) × 3 = \(\frac{3}{5}\)

Check Your Progress (Page No. 63)

Find :
i) \(5 \times 3 \frac{2}{7}\)
ii) \(2 \frac{5}{9} \times 3\)
iii) \(2 \frac{4}{7} \times 3\)
iv) \(3 \times 1 \frac{3}{4}\)
Solution:

Let’s Explore (Page No. 64)

Question 1.
Observe the products of fractions.
Have you observed the products of any two fractions is always lesser or greater than each of its fraction, write conclusion.
\(\frac{1}{5} \times \frac{2}{3}=\frac{2}{15}\) (Product of two proper fractions)
Solution:
Product of any two proper fractions is always less than each of its fraction.
i. e., \(\frac{2}{15}<\frac{1}{5} \text { and } \frac{2}{15}<\frac{2}{3}\)

ii) \(\frac{3}{2} \times \frac{5}{4}=\frac{15}{8}\) (Product of two improper fractions) •
Solution:
The product of any two improper fractions is always greater than each of its fraction.
i.e, \(\frac{3}{2}<\frac{15}{8} \text { and } \frac{5}{4}<\frac{15}{8}\)

iii) \(\frac{2}{3} \times \frac{5}{3}=\frac{10}{9}\) (Product of proper and improper fractions)
Solution:
The product of a proper fraction and an improper fraction is always greater than its proper fraction and less than its improper fraction.
i.e., \(\frac{2}{3}<\frac{10}{9} \text { and } \frac{5}{3}>\frac{10}{9}\)

(Pg. No. 66)

Question 1.
i) 4 ÷ \(\frac{1}{8}\)
ii) 9 ÷ \(\frac{3}{4}\)
iii) 7 ÷ \(\frac{2}{3}\)
iv) 35 ÷ \(\frac{7}{3}\)
v) 4 ÷ \(\frac{15}{8}\)
Solution:

(Pg. No. 67)

Question 1.
Observation these products and fill in the blanks.

Solution:

Check Your Progress (Page No. 68)

Question 1.
Write the reciprocal of fractions in the given table.

Solution:

(Reciprocal of a fraction \(\frac{\mathrm{a}}{\mathrm{b}}\) is \(\frac{\mathrm{b}}{\mathrm{a}}\))

(Page No. 69)

Question 1.
Find
i) \(\frac{7}{9}\) ÷ 4
ii) \(\frac{3}{4}\) ÷ 9
iii) 4\(\frac{1}{2}\) ÷ 6
iv) \(\frac{1}{5}\) ÷ 3
Solution:

Check Your Progress (Page No. 73, 74 & 75)

Question 1.
Fill in the blanks.

Fraction	Decimal Number	” Read as
\(\frac{6}{10}\)	0.6	Zero point six
\(\frac{37}{100}\)	0.37	Zero point three seven
	0.721	Zero point seven two one
		Seventeen point two

Solution:

Fraction	Decimal Number	Read as
\(\frac{6}{10}\)	0.6	Zero point six
\(\frac{37}{100}\)	0.37	Zero point three seven
\(\frac{721}{1000}\)	0.721	Zero point seven two one
\(\frac{172}{10}\)	17.2	Seventeen point two

Question 2.
Write the place value of the circled digits.

Solution:

Question 3.
a) 700 + 40 + 2 + \(\frac{1}{10}+\frac{3}{100}+\frac{6}{1000}\)
Solution:
700 + 40 + 2 + 0.1 + 0.03 + 0.006 = 742.136

b) 9000 + 800 + 3 + 0.2 + 0.05 + 0.007
Solution:
9000 + 800 + 3 + 0.2 + 0.05 + 0.007 = 983.257

c) 6000 + 400 + 20 + 1 + \(\frac{2}{10}+\frac{5}{100}+\frac{9}{1000}\)
Solution:
6000 + 400 + 20 + 1 + 0.2 + 0.05 + 0.009 = 6421. 259

d) 400 + 5+ \(\frac{1}{10}+\frac{8}{100}\)
Solution:
400 + 5 + 0.1 +0.08 = 405.18

Question 4.
Expand the following into decimals and fractional forms,
a) 164.238
b) 968.054
Solution:
a) 164.238 = 100 + 60 + 4 + 0.2 + 0.03 + 0.008
= 100 + 60 + 4 + \(\frac{2}{10}+\frac{3}{100}+\frac{8}{1000}\)

b) 968.054
Solution:
= 900 + 60 + 8 + 0.0 + 0.05 + 0.004
= 900 + 60 + 8 + 0 + \(\frac{5}{100}+\frac{4}{1000}\)
= 900 + 60 + 8 + \(\frac{5}{100}+\frac{4}{1000}\)

Question 5.
Write fractions as decimals.
1. \(\frac{23}{10}\) = ………..
2. \(\frac{6}{100}\) = ………..
3. \(\frac{3}{8}\) = ………..
4. \(\frac{2}{25}\) = ………..
Solution:
1. \(\frac{23}{10}\) = 2.3
2. \(\frac{6}{100}\) = 0.06
3. \(\frac{3}{8}\) = 0.375
4. \(\frac{2}{25}\) = 0.08

Question 6.
Write decimals as fractions in simplest form.
1. 0.2 = ……………
2. 0.38 = ……………
3. 1.62 = ……………
4. 8.1 = ……………
Solution:
1. 0.2 = \(\frac{2}{10}\)
2. 0.38 = \(\frac{38}{100}\)
3. 1.62 = \(\frac{162}{100}\)
4. 8.1 = \(\frac{81}{10}\)

AP State Syllabus AP Board 7th Class English Textbook Solutions Chapter 2C Susruta, an Ancient Plastic Surgeon Textbook Questions and Answers.

AP State Syllabus 7th Class English Solutions Chapter 2C Susruta, an Ancient Plastic Surgeon

7th Class English Chapter 2C Susruta, an Ancient Plastic Surgeon Textbook Questions and Answers

I. Answer the following questions.

Question 1.
Why did Susruta offer the traveller a mug of wine?
Answer:
Susruta offered the traveller a mug of wine because the wine would numb his senses.

Question 2.
Why was Susruta recognized as the father of plastic surgery, today?
Answer:
Susruta was recognized as the father of plastic surgery today because he was the first physician to advocate the caesarean operation. Besides, what he did is not greatly different from what a plastic surgeon would do today.

Question 3.
What made him the father of anaesthesia?
Answer:
His suggestion to give wine to patients about to be operated upon made him the father of anaesthesia.

Question 4.
Who could become a good physician according to Susruta?
Answer:
The person who knew both theory and practice could become a good physician, according to Susruta.

Question 5.
What was his advice to his pupils?
Answer:
Susruta advised his pupils to know both theory and practice so as to become good physicians.
He also advised them to use carcasses and models for practice before surgery.

Susruta, an Ancient Plastic Surgeon Summary in English

Susruta was an ancient plastic surgeon. He learnt surgery and medicine at the feet of Divodasa Dhanvantari in his hermitage at Varanasi. Later he became an authority in both surgery and the other branches of medicine.

Once a stranger came to him. He was bleeding from his disfigured nose. Susruta took him into his room. He washed his face with water and the juice of a medicinal plast. He offered him a mug of wine. Later he started his operation. He cut a strip of flesh from the stranger’s cheek. Later he bandaged the cut in the cheek. Later he inserted two pipes into his nostrils and transplanted the flesh to the disfigured nose. Next, he dusted the nose with powdered liquorice, red sandalwood and an extract of Indian barberry. He enveloped the nose in cotton, sprinkled some refined oil on it and finally put a bandage. Thus he completed the operation.

What Susruta did is not greatly different from what a plastic surgeon would do today So, today Susruta is recognised as the father of plastic surgery, all over the world. Susrata was born in the sixth century B.C. He was a descendant of sage, Viswamitra. He was the first physician to advocate the caesarian operation. He told his pupils that one could become a good physician only if one knew both theory and practice.

Susruta, an Ancient Plastic Surgeon Glossary

surgeon (n): the doctor who does operations

physician (n): the doctor who prescribes medicines for some illness, or a particular disease

tears (n): drops of water from eyes

stranger (n): unknown person

instruments (n): tools or things to do something

approaching (v): coming close to something / someone

advice (n): suggestion

AP State Syllabus AP Board 7th Class English Textbook Solutions Chapter 2B It’s Change…. Textbook Questions and Answers.

AP State Syllabus 7th Class English Solutions Chapter 2B It’s Change….

7th Class English Chapter 2B It’s Change…. Textbook Questions and Answers

I. Answer the following questions.

Question 1.
Who is the speaker of the poem? Guess her age? Support your answer.
Answer:
As shown in the picture in the book, the speaker is a girl. She is supposed to be 11+ years old – might be studying in VII Standard. It’s because she has a school bag on her shoulders.

Question 2.
What is the speaker’s complaint?
Answer:
She complains that though they are tiny kids, they are forced to study / learn too much and so she does not want to go to school.

Question 3.
How would you feel if a scientist cloned you?
Answer:
I would feel greatly annoyed if a scientist cloned me.

Question 4.
What is the speaker’s concern? Which line in the poem shows it?
Answer:
The speaker’s concern is learning too much for their age and strength as scientists are making rapid changes. The last line of the poem shows it.

Question 5.
Yes, scientists are causing me great concern’. How is this statement true in view of the speaker’s view ? What is your view?
Answer:
Scientists are cloning pigs and sheep. Biologists are making stem cells grow. Geologists are finding cracks in our earth. Archaeologists are digging up fossils and bones. They are all doing these activities saying that it’s change. So the speaker views that my view is the same as that of the speaker.

Question 6.
Pick out the word that describes the person who studies the life of plants and animals.
Answer:
The word is ‘Biologists’.

Question 7.
What does an archaeologist do?
Answer:
An archaeologist is the scientist who studies the cultures of the past. The archaeologist digs up fossils and bones.

II. Read the following lines from your poem and notice that the underlined words end with the same sound. Such words are called rhyming words.

Mum, I don’t want to go to school today.
‘Cause I fear our world is in decay.

Match the following words that rhyme. One is done for you. Add two more words to each pair that rhyme with them.

Project

I. Collect information about ten world famous Indian scientists and write it in your notebooks in the format given below :

Answer:

II. Now talk to other members of your group about one scientist whose discovery / invention has changed our life.

Dear friends, we must be proud of our own scientist Dr. Yellapragad Subba Rao. His discoveries in the field of science have greatly improved treatment of patients. His contribution proved to be very helpful to both doctors and patients. We must learn to follow the examples set by such great personalities.

It’s Change…. Summary in English

A little girl is afraid to go to school. She is worried that the teachers and scientists are all out to destroy this earth. They say cloning pigs and sheep is a big change. Biologists make stem cells grow. Geologists find cracks in rocks. Archaeologists discover bones of creatures who lived thousands of years ago. All these persons add to things we must learn. That is a big problem.

It’s Change…. Glossary

plot (n): a secret plan made to do something wrong

see through (phrasal v): understand

the rot (n): (here) the situation is getting worse

cloning (v): producing an exact copy of an animal

quantum leap (n): a sudden, great and important change.

stem cell (n): a basic type of cell from which all other cells develop

fossil (n): the remains of an animal or a plant which have become hard and turned into rock

concern (n): worry

feel (v): think / guess

cause (conj): because

change (n): fluctuation

great (adj): very much

kids (n): very young children

learn (v): (here) study

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 4 Integers InText Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 4th Lesson Integers InText Questions

Check Your Progress?(Page No. 47)

Question 1.
Write any five positive integers.
Solution:
1, 2, 3, 4, 5, 6, 7,

Question 2.
Write any five negative integers.
Solution:
-1, -2, -3, -4, -5, -6,

Question 3.
Which number is neither positive nor negative?
Solution:
0 (zero)

Question 4.
Represent the following situations with integers,
(i) A gain of ₹ 500 ( )
(ii) Temperature is below 5°C ( )
Solution:
i) + 7 500
ii) – 5° C

Question 5.
Represent the following using either positive or negative numbers.
a) A bird is flying at a height of 25 meters above the sea level and a fish at a depth of 2 meters.
b) A helicopter is flying at a height of 60m above the sea level and a submarine is at 400m below sea level.
Solution:
a) Height of the flying bird 25 meters from th$ sea level = + 25 meters
Depth of the fish 2 meters from the sea level = – 2 meters
b) Height of the flying helicopter 60 meters from the sea level = + 60 m
Depth of the submarine 400 m from the sea level = – 400 m

Check Your Progress (Page No. 49)

Question 1.
Draw a vertical number line and represent -5,4,0,-6, 2 and 1 on it.
Solution:

Question 2.
Represent opposite integers of – 200 and + 400 on integer number line.
Solution:
Opposite integers means, additive inverse.
∴ Opposite integer (additive inverse) of – 200 is 200.
Opposite integer (additive inverse) of +400 is – 400.

Let’s Think (Page No. 50)

Question 1.
For any two integers, say 3 and 4, we know that 3 < 4.
Is it true to say -3 < -4? Give reason.
Solution:
On the number line, the value of a number increases as we move to right and decreases as we move to the left. As -3 lies right to -4 on the number line.
So, -3 < -4 is not true.

(Pg. No. 52)

Question 1.
What is additive inverse of 7 ?
Solution:
Additive inverse of 7 is -7.

Question 2.
What is additive inverse of -8 ?
Solution:
Additive inverse of -8 is 8.

Let’s Explore (Page.No. 52)

Question 1.
Find the value of the following using a number line.
i) (-3) + 5 ii) (-5) + 3
Make two questions on your own and solve them using the number line.
Solution:
i) (-3) + 5

On the number line, we first move 3 steps to the left of 0 to reach -3.
Then, we move 5 steps to the right of -3 and reach +2. So, (-3) + 5 = 2

ii) (-5) + 3

On the number line, we first move 5 steps to the left of 0 to reach -5. Then, we move 3 steps to the right of -5 and reach -2. So, (-5) + 3 = – 2

iii)(+6) + (-3)

On the number line, we first move 6 steps to the right of 0 to reach +6.
Then, we move 3 steps to the left of 6 and reach +3. So, (+6) + (-3) = 3

iv) (-4) + (-3)

On the number line, we first move 4 steps to the left of 0 to reach -4. Then, we move 3 steps to the left of -4 and reach -7.
So (-4) + (-3) = -7.

Question 2.
Find the solution of the following:
i) (+5) + (-5) (ii) (+6) + (-7) (iii) (-8) + (+2)
Ask your friend five such questions and solve them.
Solution:
i) (+5) + (-5) = 0

On the number line, we first move 5 steps to the right of 0 to reach +5.
Then, we move 5 steps to the left of +5 and reach 0.

ii) (+6) + (-7) = -1

On the number line, we first move 6 steps to the right of 0 to reach +6.
Then, we move 7 steps to the left of +6 and reach -1.

(iii) (-8) + (+2)

On the number line, we first move 8 steps to the left of 0 to reach -8. Then, we move 2 steps to the right of -8 and reach -6.

iv)(-4) + (+8) = +4

On the number line, we first move 4 steps to the left of 0 to reach -4. Then, we move 8 steps to the right of -4 and reach +4.

v) (+3) + (-4) = -1

On the number line, we first move 3 steps to the right of 0 to reach +3. Then, we move 4 steps to the left of +3 and reach -1.

vi) (+5) + (-6) = -1

On the number line, we first move 5 steps to the right of 0 to reach +5. Then, we move 6 steps to the left of +5 and reach -1.

vii) (+4) + (-4) = 0

On the number line, we first move 4 steps to the right of 0 to reach +4. Then, we move 4 steps to the left of +4 and reach 0.

viii) (-6) +(+4) =-2

On the number line, we first move 6 steps to the left of 0 to reach -6. Then, we move 4 steps to the right of -6 and reach -2.
So, (-6) + (+4) = -2

Let’s Explore (Page No. 55)

Question 1.
Take any two integers a and b. Check whether a+b is also an integer.
Case (i) : Consider two integers 3 and -2 (Positive and negative)
Sum = 3 + (-2) = +1 + 2 – 2 = +1 + 0 = +1 is also an integer.
Case (ii) : Consider two ihtegers 5 and 6 (Both are positive)
Sum = 5 +6 = + 11 is also an integer
Case (iii) : Consider two integers -4 and -6 (Both are negative)
Sum = -4 + (-6) = -4 -6 = -10 is also an integer
Case (iv) : Consider two integers -5 and 4 (Negative and positive)
Sum = -5 + 4 = -1 -4 + 4 = -1 + 0 = -1 is also an integer.
So, if a and b are integers, then their sum a + b is also an integer. Integers are closed under addition.

Question 2.
Check the following Properties on integers, a, b, c are any integers.
i) Closure Property under subtraction ‘
ii) Commutative Property under addition and subtraction (a + b = b + a ?, a – b = b – a?)
iii) Associative Property under addition and subtractioji.
(a + b) + c = a + (b + c) ? (a – b).- c = a – (b – c)?
Solution:
i) Closure Property under subtraction :
Case (i) : Consider two integers 4, -5 (positive and negative)
Then, difference a – b = 4 – (-5) = 4 + 5 = + 9is also an integer.
Case (ii) : Consider two integers 3, 8 (Both are positive)
Then, difference a – b = 3 – (+8) = 3-8
= +3 – 3 – 5 = 0 – 5 = -5is also an integer.
Case (iii) : Consider two integers -2, -6 (Both are negative) .
Then, difference a – b = -2 – (-6) = -2 + 6
= -2 + 2 + 4 = 0 + 4 = +4 is also an integer.

Case (iv) : Consider two integers -3, 2 (Negative and positive)
Then, difference a – b = -3 – (+2) = -3 -2 = -5 is also an integer.
So, if a and b are any two integers, then their difference a – b is also an integer. Integers are closed under subtraction.

ii) Commutative Property under addition and subtraction :
(a + b = b + a, a-b = b-a)
(A) Case (Q : Consider two integers-3 and 5 (Negative and positive)
Then, a + b = -3 + (+5)
= -3 + 5 = – 3 + 3 + 2 = 0 + 2 = + 2
b + a = +5 + (-3) = +2 + 3- 3 = +2 + 0 = + 2
∴ a + b = b + a

Case (ii) : Consider two integers +4 and +2 (Both are positive)
Then, a + b = +4 + (+2) = +4 + 2 = + 6 ‘b + a = +2 + (+4) = +2 + 4 = + 6
∴ a + b = b + a

Case (iii) Consider two integers -5 and -3 (Both are negative) Then, a + b = -5 + (-3) = -5 – 3 = -8 b + a = -3 + (-5) = – 3 – 5 = -8
∴ a + b = b + a

Case (iv) : Consider two integers +4 and -1 (Positive and negative)
Then, a + b = +4 + (*1) = +4 -1 = +3 + 1 -1 = +3 + 0 = +3 b + a = -1 + (+4) =-l + 4 = -l + l+ 3 = 0 + 3 = + 3
∴ a + b = b + a
So, integers are commutative under addition.

(B) Consider two integers -4 and +6 (Negative and positive)
Then, a – b = -4 – (+6) = -4 – 6 = -10 b-a = + 6-(-4) = +6 +4 = +10 -10*10
a – b ≠ b – a
So, integers are not commutative under subtraction.

iiO Associative property under addition and subtraction :
(a + b) + c = a + (b + c) ; (a – b) – c = a – (b – c)
(A) Case (i) : Consider any three integers 2, 4, -5
(a + b) + c = (2 + 4) + (-5) = 6 – 5 = +1 + 5- 5 = +1 + 0 = +1
a + (b + c) = 2 + (4 + (-5)) = 2 + (4 – 5) = 2 + (4 – 4 -1)
= 2 + (0-1) = + 2 – 1 = + 1 + 1 – 1 = +1 + 0 = +1
∴ (a + b) + c = a + (b + c)

Case (ii) : Consider any three integers +2, -5, +3
Then, (a + b) + c = [2 + (-5)] + 3 = [+2 -5] + 3 = +2 -2 -3 + 3 = 0 + 0 = 0
a + (b + c) = +2 + [( – 5)+3] = +2 + [-2 – 3 + 3] = +2 + (-2 + 0) = +2 -2 = 0
∴ (a + b) + c = a + (b + c)

Case (iii) : Consider any three integers 3, 4, 6
Then, (a + b) + c = [2 + (-5)] + 3 [+2-5] + 3
a + (b + c) = 3 + (4 + 6) = 3 + 10 = + 13
∴ (a + b) + c = a + (b + c)

Case (iv) : Consider any three integers -4, -2, +5
Then, (a + b) + c = [-4 + (-2)] + 5 = [-4 -2] + 5 = -6 + 5
= -1-5 + 5 = – 1 + 0 = – 1
a + (b + c) = -4 + [(-2) + 5] = -4 + [-2 + 5]
= _4 + [_2 + 2 +3] = -4 + 0 + 3 =-1-3+ 3
= -1 + 0 = -1
∴ (a + b) + c = a + (b + c)

Case (v) : Consider any three integers-3, 4, 1
Then, (a + b) + c = (-3 + 4) + 1 = (-3 + 3 + 1) + 1 = 0 + 1 + 1 = + 2
a + (b + c) = -3 + (4 + 1) = -3 + 5 = -3 + 3 + 2 = 0 + 2 = +2
∴ (a + b) + c = a + (b + c)

Case (vi) : Consider any three integers -2, 6, -7
Then, (a + b) + c = (-2 + 6) + (-7) = (-2 + 2 + 4) + (-7) = 0 + 4 – 7
= + 4 – 4 – 3 = 0 – 3 = -3
a + (b + c) = -2 + [6 + (-7)] = -2 + (6 – 7) = -2 + [+6 – 6 -1]
= -2 + (-1) = -2 -1 = -3
∴ (a + b) + c = a + (b + c)

Case (vii) : Consider any three integers +6, -3, -1
Then, (a + b) +c = [+6 + (-3)] + (-1) = (6 – 3) – 1 = (+3 +3 -3) -1
=+3-1 =+2 + 1 – 1 =+2 + 0 = + 2
a + (b + c) = +6 + [-3 + (-1)] = 6 + [-3 – 1] = 6 + (-4) .
= +2 + 4 – 4 = 2 + 0 = + 2
∴ (a + b) + c = a + (b + c)

Case(viii)
Consider any three integers -4, -1, -7
Then, (a + b) + c = [-4 + (-1)] + (-7) = (-4 -1) – 7 = -5 -7 = -12
a + (b + c) = -4 + [(-1) + (-7)] = -4 + [-1 -7] = -4 + (-8)
= -4 – 8 = -12
∴ (a + b) + c = a + (b + c)
From all the above cases we conclude that, integers are associative under addition.

(B) Consider any three integers +5, -4, 1
Then, (a – b) – c = (+5 – (-4)) – (+1) = (5 + 4) – 1 .
= + 9 – 1 = + 8 + 1 – 1 = + 8 + 0 = + 8
a – (b – c) = +5 – [- 4 – (+1)] = + 5 – [-4 – 1]
= + 5 – [ -5] =+ 5 + 5 = + 10
+ 8 ≠ +10
∴ (a – b) – c ≠ a – (b – c)
So, integers are not associative under subtraction.

AP State Syllabus AP Board 7th Class English Textbook Solutions Chapter 2A C.V. Raman, the Pride of India Textbook Questions and Answers.

AP State Syllabus 7th Class English Solutions Chapter 2A C.V. Raman, the Pride of India

7th Class English Chapter 2A C.V. Raman, the Pride of India Textbook Questions and Answers

Look at the pictures and answer the questions that follow.

Question 1.
Can you name these scientists?

Answer:

1. A.P.J. Abdul Kalam
2. C.V. Raman
3. Srinivasa Ramanujan
4. Albert Einstein
5. Isaac Newton
6. Sir Alexander Fleming.

Question 2.
Tell your class what you know about them.
Answer:

1. A.P.J. Abdul Kalam: He was the former President of India. He played a pivotal role in the development of Missile and Nuclear Weapons. He got Hoover medal. He is the recipient of Bharat Ratna award.
2. C.V. Raman: He was the first Indian to receive the Nobel Prize in Physics for his ‘Raman Effect’. He was also the first Asian and the first non-white to receive the Nobel Prize. He discovered the Raman Effect with equipment worth only Rs. 200/- and limited facilities in his laboratory. He was the first Indian scholar who studied wholly in India.
3. Srinivasa Ramanujan: He was a great Indian mathematician. He made extraordinary contributions to mathematical analysis, number theory and infinite series.
4. Albert Einstein: He was a great German physicist. His Theory of Relativity showed that mass and energy are different forms of each other.
5. Isaac Newton: He discovered that sunlight is a mixture of the colours of a rainbow. He built a telescope through which he saw the moons of Jupiter. He discovered the law of gravitational force.
6. Sir Alexander Fleming: Sir Alexander Fleming was a Scottish biologist, pharmacologist and botanist. His best-known discoveries are the enzyme, lysozyme in 1923 and the antibiotic substance penicillin in 1928, for which he shared the Nobel Prize in Physiology or Medicine in 1999. It was a discovery that changed the course of history. The active ingredient in penicillin turned out to be an infection-fighting agent of enormous potency. When it was finally recognized for what it was, the most efficacious life-saving drug in the world, penicillin would alter forever the treatment of bacterial infections.

Question 3.
Are scientists special people? How?
Answer:
Yes, they are special in their attire, appearance and their thoughts. They neither know well of politics nor play them. They spend most of their time in scientific research.

Question 4.
Do you want to be a scientist? Why?
Answer:
Yes, I want to be a scientist. I am very fond of the science subject. I want to do research in physics and discover something new.

Question 5.
How many of them received the Nobel Prize?
Answer:
Of the six scientists shown in the pictures, C.V. Raman, Albert Einstein and Har Gobind Khorana received the Nobel Prize.

Question 6.
Who was the first Indian scientist that received the Nobel Prize?
Talk about him/her and his/her field of science.
Answer:
The first Indian scientist who received the Nobel Prize was C.V.Raman. His full name was Chandrasekhar Venkata Raman. He was born at Tiruchirapalli in Tamil Nadu on November 7,1888. He had only limited facilities and an equipment worth Rs. 200. Yet he worked hard, thought independently and discovered the Raman Effect which says that light changes its nature when passes through transparent medium. He was the first Indian scholar who studied wholly in India. He was the first Asian and also the first non-white to get the Nobel Prize. He was the pride of India.
He passed away in 1970 on November 21.

I. Answer the following questions.

Question 1.
Why was Raman happy when he learnt that Professor Compton had won the Nobel Prize?
Answer:
When Raman learnt that Professor Compton had won the Nobel Prize, he felt very happy because what Prof. Compton wanted to prove, was proved and Raman felt that he would also succeed in his effort.

Question 2.
What does the ‘Compton Effect’ tell us?
Answer:
The ‘Compton Effect’ tells us that the nature of X-rays changes when passed through the matter. The change was dependent on the kind of matter.

Question 3.
What was Raman’s advice to young scientists?
Answer:
C.V. Raman’s advice to young scientists was to look at the world around them and not to confine themselves to their laboratories. He said that the essence of science is independent thinking and hard work but not equipment.

Question 4.
Which paragraph tells about the ill-health of C.V.Raman?
Answer:
Paragraph No-7 in the lesson tells about the ill-health of C.V. Raman.

Question 5.
What was the challenging situation when Raman started his experiment on light?
Answer:
When Raman started his experiment on light, no sophisticate equipment was available in his laboratory. But he was confident he could do the discovery by making some modifications in his experiment. With equipment worth hardly Rs. 200 and limited facilities, Raman made the discovery.

Question 6.
What was the unseen force working behind Raman for reaching great heights?
Answer:
The unseen force working behind Raman for reaching great heights was his confidence, dedication and hard-work in what he tried to discover. His confidence was that he could discover with some modifications in his equipment and using the limited facilities made him very great.

Question 7.
What was ‘Raman Effect’?
Answer:
‘Raman Effect’ was that light changes its nature when passed through a transparent medium. It was his discovery of new radiation (describing the behaviour a beam of light passing through a liquid chemical).

Question 8.
If A.H. Compton had not discovered the ‘Compton Effect’, do you think Raman would have discovered the ‘Raman Effect’? Give your reasons.
Answer:
Yes, even if A.H. Compton had not the ‘Compton Effect’, Raman would have the Raman Effect because Raman was a very optimistic, well-confident and dedicated scientist. He was not a dependent on equipment. He was not confined himself to his laboratory. ,He had independent thinking and was hard-working.

Question 9.
In what way was Raman different from the other Indian scientists? List them and justify your answer.
Answer:
Other Indians want good and sophisticated equipment to carry out their experiment. They confine themselves to their laboratories. But C.V. Raman was not dependent on equipment. He had no sophisticated equipment. He did not confine himself to his laboratory. Unlike others, he was hard-working and confident and had independent thinking and looked at the world around him.

Question 10.
If you were a scientist, what would you like to invent/discover?
Answer:
If I were a scientist, I would like to invent a car that could run with the energy of sunlight but not with diesel or petrol.

II. Say whether the following statements are true or false. Correct the false statements.

1. C.V. Raman was born in Calcutta. ( )
2. The Compton Effect was a discovery made by C.V.Raman. ( )
3. Raman’s mother was a college physics teacher. ( )
4. Raman was an average student at school. ( )
5. Raman studied how the drum could produce music. ( )
6. Raman spent only two hundred rupees to win the Nobel Prize. ( )
7. Raman was only 42 when he won the Nobel Prize. ( )
Answer:
1. False
2. False
3. False
4. False
5. False
6. True
7. True
Correct Statements:
1. C.V. Raman was born in Tiruchirapalli.
2. The Compton Effect was a discovery made by Professor Compton.
3. Raman’s father was a college physics teacher.
4. Raman was a brilliant student at school.
5. Raman studied how the violin, etc. could produce music.

Vocabulary

I. The following sentences are from your lesson. Read them carefully and tick (✓) the correct meaning of the underlined word in each sentence.

1. His parents were keen to send him abroad for higher studies.
(a) particular
(b) eager
(c) worried

2. The world hailed the discovery as the ‘Raman Effect’.
(a) admired
(b) called
(c) thought

3. In his youth Raman was mainly interested in acoustics.
(a) primarily
(b) simply
(c) certainly

4. The British made Raman a knight of the British Empire.
(a) appointed
(b) managed
(c) placed

5. Raman passed awav on November 21, 1970.
(a) was killed
(b) died
(c) left
Answer:
1) b
2) a
3) a
4) a
5) b

II. Read the following sentence.

Raman was equally delighted.
The underlined word ‘delighted’ is a verb and has been used to express a feeling of joy or happiness. Its noun form is ‘delight. ’ Now look at the following verbs and write their corresponding noun forms.

Answer:
2) surprise
3) disappointment
4) worry
5) satisfaction

Now fill in the blanks with the suitable noun forms of the underlined words in each sentence. .
1. He was shocked to see a snake in his room but he recovered from his ——– in no time.
2. He pretended to look relieved but, in fact, he did not have any ——–.
3. I can understand your ——–. But do not be so excited that you have health problems.
4. Raju, an auto driver, was very honest. His ——– was known to everybody when he returned the bag of jewellery a passenger had left in his auto.
Answer:
1) shock
2) relief
3) excitement
4) honesty

III. (1) Read the following sentence and notice the underlined part.

Raman staged in the country to do the M.A. course.
The underlined letters in capitals denote an abbreviation. The full form of this abbreviation is ‘Master of Arts’.
Here is a list of some common abbreviation’s. Write their full forms.


Answer:

Abbreviation	Full form
B.A.	Bachelor of Arts
A.D.	Anno Domini
B.C.	Before Christ
C.M.	Chief Minister
C.D.	Compact Disc
D.V.D.	Digital Versatile Disc/ Digital Video Disc
a.m.	ante meridiem
p.m.	post meridiem

(2) Read the following sentence and notice the underlined word.

He used to spend his hours after office in the lab.
The underlined word “lab is the short form of laboratory,”
Look at the following list of short forms and write their full forms. The first one is done for you. (Use a dictionary)

Answer:

Short form of the word	Full form of the word
plane	aeroplane
kilo	kilogram
para	paragraph
specs	spectacles
photo	photograph
bike	bicycle, motor bike
mike	microphone

IV. In the paragraph 4 you have learnt that ‘optics’ is the study of light. Do you know ‘ the word for the study of living beings? It is ‘biology’. It comes from ‘bio’ (means ‘life’) + ‘logus’ / ‘logy’ (means ‘study of science’). So the suffix ‘-logy’ adds the meaning ‘the study of’.

Guess the meaning of the words under Column A and match them with the phrases under Column B.

Answer:
1) d
2) e
3) a
4) c
5) b

Grammar

I. Read the following sentences from your lesson and observe how the underlined words are used before dates, years and the names of places.

1. Raman was born on November 7,1888. (Para 6)
2. Raman passed away in 1970 on November 21. (Paral 11)
3. Raman did his M.A. course at Presidency College in Madras. (Para 6)
4. In December, on a fine evening in 1927, there was much excitement. (Para 1)
Note: ‘on’, ‘in’ and ‘at’ are prepositions of time and place. In sentence 1 & 2 ‘on’ is used before a date. In sentence 2, 3 & 4 ‘in’ is used before a year (in 1970), before the name of a big city (in Madras) and before the name of a month (In December). In sentence 3 ‘at’ is used before the name of a small place / area.
Now fill in the blanks with ‘in, ‘on’ and ‘at’.
Sarath Chandra and Keerthana are brother and sister. Sarath Chandra was born –1– 25th April –2– 2000. Keerthana was born –3– December 2, 2001. They are with their parents. They live –4– Kondamudusu Palem, a small village –5– Prakasam District. They play games –6– school. It is usually very hot –7– May –8– their village. So they spend their summer –9– Hyderabad –10– their uncle’s house. Mr. Srisailam is their uncle. He resides –11– High Court Colony –12– Hyderabad with his wife, Jagadeeswari and his daughter, Vishnu Priya.
Answer:
1) on
2) in
3) on
4) at
5) in
6) at
7) in
8) in
9) in
10) at
11) at
12) in

II. Revision of ‘Articles’.

1. ’a’ is used before singular common nouns /in nouns phrases beginning with consonant sounds.
2. ‘an’ is used before singular common nouns / in noun phrases beginning with vowel sounds.
3. ‘the’ is used
(a) before words/phrases that indicate unique things (“It was the headquarters of the Indian Association ‘)
(b) in situations where the sentence itself contains a clue to identify of the thing or the person referred to (e.g. His advice to young scientists was also to .look at the world around them)
(c) in social situations where the identity, of the person / object is understood (“But look here, Krishnan,” he said turning to the young man ..”).
d) before the names of musical instruments (“He studied how stringed instruments like the violin “)

III. List 20 phrases from the text that begin with ‘a’/ ‘an’ or ‘the’. Then put 1,2,3(a), 3(b), 3(c), or 3(d) against them depending on how ‘a’ / ‘an’ or ‘the’ is used. One is done for you.

1. an old building                                                                                  2
2. It was the headquarters of the Indian Association.                           3(a), 3(a)
3. Raman said turning to the young man.                                            3(c)
4. His advice to them was to look at the world.                                   3(b)
5. He studied how the violin                                                                3(d)
6. He was the firsts Indian                                                                    3(a)
7. The British Govt.                                                                               3(a)
8. The day on which he discovered.                                                     3(b)
9. Raman had already made an impression.                                        2
10. a British surgeon                                                                            1
11. a college physics teacher                                                               1
12. Raman was able to make a discovery.                                           1
13. On the busy Bowbazaar Street                                                      3(b)
14. Raman stayed in the country.                                                        3(b)
15. passing through a liquid                                                                1
16. the nature of X-rays .                                                                     3(a)
17. passed through a transparent medium                                         1
18. That was the question that Raman asked                                      3(c)
19. Optics, the science of light                                                            3(a)
20. It was a high honour                                                                     1

Now fill in the blanks with ‘a’ ‘an’ or ‘the’.
1. In 1987 M.S. Swaminathan was awarded ——– Ramon Magsaysay Award.
2. We dined yesterday at ——– Maurya Sherton hotel.
3. Tejaswini lent me ——– interesting book.
4. My father is ——– school teacher.
5. M.S.Swaminathan worked at ——– Indian Agricultural Research Institute.
6. Rekha bought ——– long notebook yesterday.
7. Sravani is eating ——– mango now.
8. Ganesh always carries ——– umbrella with him.
9. Rambabu is ——– English teacher in a high school.
10. Manjula and Sruthi play ——– guitar well.
Answer:
1) the
2) the
3) an
4) a
5) the
6) a
7) a
8) an
9) an
10) the

Writing

I. Write a paragraph on J.C. Bose using the hints given below. You must use the right linkers to join the sentences.

J.C. Bose – Indian scientist – born 30-09-1858 – St. Xavier’s School, Calcutta – abroad for higher studies – returned in 1885 – published a monograph, Response in the Living and Non-living – became famous – Fellow of the Royal Society in 1920 – wireless telegraphy in 1895 – the Crescograph – plants have life – the Bose Institute in Calcutta – devoted to the study of plants – died 23-11-1937.
Share your draft with your partner and refine your draft in the light of the suggestions offered by him.
Answer:
Jagadish Chandra Bose (J.C. Bose) was a famous Indian scientist. He was born on 30th September, 1858.
J.C. Bose studied at St. Xavier’s School in Calcutta. Later he went abroad for higher studies. He returned to India in 1885. He published a monograph which was about the response in the living and the non-living. He became famous by being a Fellow of the Royal Society in 1920.
J.C. Bose invented wireless telegraphy in 1895. He proved that plants have life. J.C. Bose invented Crescograph, an instrument with which the growth in plants can be known.
J.C. Bose founded the Bose Institute in Calcutta. He devoted most of his life to the study of plants. J.C. Bose passed away on 23rd November, 1937.

II. The passage given below has some errors in the use of capital letters, verbs, prepositions and articles. Edit the passage by underlining the incorrect parts and writing them correctly over the space available. The first one is done for you.

Raman was borne (born) on November 7, 1888, in tiruchirapalli at tamil nadu. He finishes his m.a. course at Presidency college in chennai. He became member of the indian association for cultivation of science. He took up a administrative job in the finance ministry in Calcutta. He was elected the royal society of London in 1924 and the british government made him a knight of the british empire in 1929. He was first indian scholar who studied wholly in india and received the nobel prize.
Answer:
The incorrect parts in the given passage have been underlined. Given below is the passage with no incorrect parts.

Raman was born on November 7, 1888 at Tiruchirapalli in Tamil Nadu. He finished his M.A. course at Presidency College in Chennai. He became a member of the Indian Association for Cultivation of Science. He took up an administrative job in the Finance Ministry in Calcutta. He was elected to the Royal Society of London in 1924 and the British Government made him a knight of the British Empire in 1929. He was the first Indian scholar who studied wholly in India and received the Nobel Prize.

Study Skills

I. Study the pie charts and answer the questions given below them.

Distribution of Weight in Human Body.

1. Which of the following constitute most of the weight in the human body?
(a) water (b) proteins (c) dry elements (d) bones
Answer:
(a) water

2. Which of the following statements is correct?
(a) Proteins constitute 11 per cent of the human body.
(b) Dry elements constitute 15 per cent of the human body.
(c) Hormones, enzymes and other proteins constitute 2/5 of the human body.
Answer:
(c) Hormones, enzymes and other proteins constitute 2/5 of the human body.

3. If a person’s weight is 100 kilograms, how much do his bones weigh?
Answer:
20 Kgs

4. If the proteins in a person weigh 12 kilograms, what will be his weight?
Answer:
50 Kgs

5. Are the bones in our body heavier than the water in our body? Support your answer.
Answer:
No, they are not. Water constitutes 65 per cent of our weight.

Listening and Speaking

Your teacher will read the passage “The Inventor of Inventors’. Listen carefully and answer the questions given below.

Genius is one percent inspiration and ninety-nine percent perspiration.’ -Thomas Alva Edison

Thomas Alva Edison, the greatest inventor of all times, is the most suitable example of his own saying. This great, outstanding US inventor had the credit of making 1001 inventions. Can you imagine a world without electric light, recorded music, cinema, etc. which are the contributions of this great genius?

Edison was born on February 11, 1847 at Milan, Ohio. His father was in-charge of a light house at Lake Huron. Although he could not continue his studies in his school, he was very inquisitive from his boyhood to learn by understanding. When he was only ten years old, he set up a laboratory in the basement of his father’s work place. He loved to mix liquids and powders to observe the reactions.

At the age of 12, he began selling newspapers and candy in trains. As a very keen observer, he learnt some preliminary techniques of telegraphy from the station master, which led him later to work as a roving telegrapher. During his stint as a supervisor in a Telegraph company, he created a stock printer. With the money received from it, he set up a laboratory for carrying out his experiments and research work. In subsequent years he invented phonograph — the machine for recording and reproducing sound. Edison thus made man’s voice immortal. In 1878. he demonstrated the light bulb — a carbon filament electric bulb.

While experimenting on electric lamp, he discovered an important scientific principle known as ‘Edison Effect’. This discovery led to the invention of electron valves and the modern electronics industry rests on this principle. In 1882, he set up a power generating station which supplied power to a few residents of New York City. Later, he developed the kinetograph which was the first step towards motion picture camera. Cinema houses are here today because of the inventive genius of Edison. His other inventions include the spheres of X-rays, telephone and other electronic items. His inventions made him one of the richest men in America.
This great genius passed away on 18 October, 1931.

I. Say whether the following statements are true or false.

1. When Edison was twelve, he established a school. ( )
2. Edison discovered an important scientific principle known as the Edison Effect. ( )
3. Edison was a poor observer. ( )
4. Edison’s father was a school teacher. ( )
5. Edison loved to mix liquids and powders to observe the reaction. ( )
Answer:
1. False
2. True
3. False
4. False
5. True

Here is a list of inventions. Put a ( ✓)against them if it was invented by Edison.

III. GROUP WORK

1. Thomas Alva Edison invented electric bulb. If there were no electric bulbs, how would be our life?

Mother: What are you doing Ramu?
Ramu: Nothing mom!
Mother: Why aren’t you doing anything my boy? Tomorrow you’ve a terminal exam.
Ramu: How can I read mom? The power has gone.
Mother: Why? You can read under a kerosene lamp or under a candle.
Ramu: Kerosene lamp gives out a lot of smoke. It smells bad. More than that, the smoke may cause irritation to my eyes.
Grandmother: So! You can’t use the oil lamp for at least an hour. That too in emergency! But we’ve struggled all our lives with them.
Ramu: That is your fate ! But today we are all comfortable with electric bulbs.
Mother: If there were no electric bulbs, what would be our lives ?
Ramu: I can’t imagine ! Damn the dark world ! We are not supposed to live in darkness. At night we would be blind and were to grope for everything in darkness. There will be no progress in human life. Life comes to a standstill. We have to go back to the middle ages. Thank God ! Thomas Alwa Edison was born hundred and seventy five years ago and invented the electric bulb.
[Just then power comes and brighten the whole city with its splendid and gorgeous lights.] Thank you Edison ! We are always very much grateful to you. Now mom, I am going to read my lessons.

2. Debate the following proposition :

‘Science has proved to be more a curse than a blessing.’ Divide the groups into two sets. One set of students speak in favour of the motion and the other against it. They may use the words / expressions listed in the box.

Conversation
Answer:
‘A’ – At the outset, I would like to emphasise that it is not science that has proved to be more a curse than a blessing but its use by selfish man that has proved to be a real curse.
‘B’ – May I begin by saying that unless there is something wrong in science itself, it cannot be abused. Hence science is a curse.
‘C’ – I must take strong exception to what ‘B’ has said. Even a very useful product may be abused because of either lack of proper knowledge or malintention.
‘D’ – Whatever may be one’s views, I must add that science is definitely a blessing. But no blessing comes to us with 100% positive uses. We must learn to use the positive side of it and ignore the negative side. That’s how wise people use science.
‘E’ – We may conclude with supporting “D’. We must all work hard to minimize the evil results of science and maximise its good effects. Then there wouldn’t be any scope for sayings like ‘Science is a more a bane than a boon’.

IV. Listen to the conversation between Sindhu and Mary.

Sindhu: Mary, where have you been all the week?
Mary: Um…I had been to Hyderabad.
Sindhu: Hyderabad? Why? Why did you go there?
Mary: You know, my uncle lives there. I went there to visit him.
Sindhu: That’s nice. But did you visit any place?
Mary: Oh!Yes, I visited a museum . It’s wonderful.
Sindhu: Really! What kind of museum is it?
Mary: It’s a science museum.
Sindhu: Science museum? But it should be boring.
Mary: Not a bit. I learnt a lot about many interesting things. You must see it.
Sindhu: Is it that much interesting? Could you tell me something more about it?
Mary: Oh! It takes a long time. Now I am in a hurry. I will talk about it later.

Now work with your partner and ask and answer questions about the science fair that might have been organised in your school or district. Use the following questions too.
1. When did you go to the science fair?
2. What things did you see there?
3. Which was the most interesting thing you noticed there?
Answer:
Vlnod: Hi, Santosh. You haven’t been seen these days;
Santosh: Hi, Vinod. Ya I had been to Khammam.
Vlnod: Why? What is the purpose?
Santosh: Don’t you know that a science fair has been going on there?
Vlnod: A science fair? No, I don’t know about it. When did you go there?
Santosh: Vinod, our science teacher told us about It last Saturday. I went there on Sunday.
Vlnod: Oh! I didn’t come to school on Saturday. Any way, what did you see there?
Santosh: I saw a lot many exhibits. It took two full days for me to just go round the stalls.
Vinod: OK. Then just tell me about the most interesting thing you saw there.
Santosh: The exhibit on conservation of water impressed me a lot. May be because
I am interested in the subject.
Vinod: How long will the science fair be open, Santosh? I too feel like visiting it.
Santosh: It will be open, till the day after tomorrow.
Vinoid: Then I will start for Khammam today itself. Bye Santosh!

C.V. Raman, the Pride of India Summary in English

Chandrasekhar Venkata Raman was an eminent Indian Scientist. He was the first scholar who studied wholly in India. He was the first Indian Scientist to receive the Nobel Prize in Physics. He was also the first Asian as well as the first non-white to receive the Nobel Prize.

C. V. Raman was born at Tiruchirapalli in Tamil Nadu on November 7, 1888. His father was a college physics teacher. Right from the start, Raman was a brilliant student. So, when Raman passed his matriculation, his parents wanted to send him abroad for higher studies. But a British surgeon told them not to send him abroad as he was not healthy enough. Raman did his M.A. course at Presidency College in Madras (now called Chennai).

Raman was fond of the Science subject. When he was 19, he became a member of the Indian Association for Cultivation of Science. The headquarters of it was an old building on the busy Bowbazaar Street in Calcutta. Meanwhile Raman took up an administrative job in the Finance Ministry in Calcutta so as to respect the wishes of his parents.

In his youth, Raman was mainly interested in acoustics, the science of sound. He studied how stringed instruments like the sitar and the violin could produce harmonious music. He became a knight of the British Empire in 1929.

With equipment worth only Rs. 200 and limited facilities available in his laboratory, Raman was able to make a discovery known as the Raman Effect, which won him the Nobel Prize in physics in 1930. Earlier, in 1927, Professor A.H. Compton had won the Nobel Prize for the Compton Effect. Compton Effect says that the nature of X-rays changes when passes through the matter. Raman Effect says that the nature of light changes when passes through transparent medium. Raman’s advice to the young scientists was to look at the world around them and not to confine themselves to their laboratories. Raman passed away in 1970 on November 21.

C.V. Raman, the Pride of India Glossary

lost in thought: giving all your attention to something so that you do not notice what is happening around you

transparent (adj): allowing you to see through it

sophisticated (adj): advanced and capable

equipment (n): the things that are needed for a particular activity

modification(n): change

discovery (n): the process of finding something that was not known about before

red-letter day (Idiom): an important day

surgeon (n): a doctor who is trained to perform surgery

abroad (adv): in or to a foreign country

flag (v): decline, become less

stringed Instrument (n): any musical instrument with strings (eg. the violin, the sitar etc.)

harmonious (adj): very pleasant

knight (n): a man of high social rank a person with the title

confine (v): to restrict

received (v): got

passed away (v): died

remarkable (ad)): memorable

mainly (adv): primarily

keen (adj): eager

hailed (v): admired

made (v): placed

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 3 HCF and LCM InText Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 3rd Lesson HCF and LCM InText Questions

(Page No. 35)

Question 1.
How does the Sieve of Eratosthenes work ?
Solution:
The following example illustrates how the Sieve of Eratosthenes, can be used to find all the prime numbers that are less than 100. .
Step 1: Write the numbers from 1. to 100 in ten rows as shown below.
Step 2: Cross out 1 as 1 is neither a prime nor a composite number.
Step 3: Circle 2 and cross out all the multiples of 2. (2, 4, 6, 8, 10, 12, ………… )
Step 4: Circle 3 and cross out all the multiples of 3. (3, 6, 9, 12, 15, 18,………….)
Step 5: Circle 5 and cross out all the multiples of 5. (5, 10. 15, 20, 25……………… )
Step 6: Circle 7 and cross out all multiples of 7. (7, 14, 21. 28, 35, ………………….. )

Circle all the numbers that are not crossed out and they are the required prime numbers less than 100.

First arrange the numbers ffom 1 to 100 in a table as shown above.
Enter 6 numbers in each row until the last number 100 is reached.
First we select a number and we strike off all the multiples of it.
Start with 2 which is greater than 1.
Round off number 2 and strike off entire column until the end.
Similarly strike off 4th column and 6th column as they are divisible by 2.
Now round off next number 3 and strike off entire column until end.
The number 4 is already gone.

Now round off next number 5 and strike off numbers in inclined fashion as shown in the figure (they are all divisible by 5). When striking off ends in some row, start again striking off with number in another end which is divisible by 5. New striking off line should be parallel to previous strike off line as. shown in the figure.
The number 6 is already gone.
Now round off number 7 and strike off numbers as we did in case of number 5.
8,9,10 are also gone. .
Stop at this point.
Count all remaining numbers. Answer will be 25.

Prime numbers :
There are 25 prime numbers less than 100.
These are:

What if we go above 100 ? Around 400 BC the Greek mathematician. Euclid, proved that there are infinitely many prime numbers.

Co-primes: Two numbers are said to be co-prime if they have no factors in common. Example: (2, 9), (25, 28)
Any two consecutive numbers always form a pair of co-prime numbers.

Example:
Co-prime numbers are also called relatively prime number to one another.
Example: 3, 5, 8, 47 are relatively prime to one another/co-prime to each other.

Twin primes: Two prime numbers are said to be twin primes, if they differ by 2.
Example: (3, 5), (5, 7), (11, 13), …etc.

Prime factorization: The process of expressing the given number as the product of prime numbers is called prime factorization.
Example: Prime factorization of 24 is
24 = 2 x 12
= 2 x 2 x 6
= 2 x 2 x 2 x 3, this way is unique.

Every number can be expressed as product of primes in a unique manner. We can factorize a given number in to product of primes in two methods. They are
a) Division method
b) Factor tree method

Common factors: The set of all factors which divides all the given numbers are called their common factors.
Example: Common factors to 24, 36 & 48 are 1, 2, 3, 4, 6 & 12
Factors of 24 = 1, 2, 3, 4, 6, 8, 12 & 24
Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18 & 36
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24 & 48
Common factors to 24, 36 & 48 are 1, 2, 3, 4, 6 & 12
We can see that among their common factors 12 is the highest common factor. It is called H.C.F. of the given numbers. So H.C.F. of 24, 36 & 48 is 12.

H.C.F./G.C.D : The highest common factor or the greatest common divisor of given numbers is the greatest of their common factors.
H.C.F. of given two or more numbers can be found in two ways.
a) By prime factorization
b) By continued division
H.C.F. of any two consecutive numbers is always 1.
H.C.F. of relatively prime/co-prime numbers is always 1.
H.C.F. of any two consecutive even numbers is always 2.
H.C.F. of any two consecutive odd numbers is always 1.

Common multiples:
Multiples of 8: 8, 16, 24, 32, 40, 48,
Multiples of 12: 12, 24, 36, 48, … .
Multiples.common to 8 & 12: 24, 48; 72, 96, …
Least among the common multiple is 24. This is called L.C.M. of 8 & 12. The number of common multiples of given two or more numbers is infinite, as such greatest common multiple cannot be determined.

L.C.M.: The least common multiple of two or more numbers is the smallest natural number among their common multiples.
L.C.M. of given numbers can be found by the
a) Method of prime factorization.
b) Division method.
L.C.M. of any two consecutive numbers is always equal to their product.
L.C.M. of 8 &9 is 8 x 9 = 72
L.C.M. of co-prime numbers is always equal to their product.
L.C.M. of 8 & 15 is 8 x 15 = 120

Relation between the L.C.M. & H.C.F:
For a given two numbers Nj & N2 , the product of the numbers is equal to the product of their L.C.M.(L) & H.C.F.(H)
N₁ x N₂ = L x H

Check Your Progress (Page No. 29)

Question 1.
Are the numbers 900, 452, 9534, 788 divisible by 2? Why?
Solution:
Yes. Because these numbers have 0, 2, 4 and 8 in their ones place. The numbers having 0, 2, 4, 6 and 8 in their ones place are divisible by 2.

Question 2.
Are the numbers 953, 457, 781, 325, 269 divisible by 2? Why?
Solution:
No. Because, these numbers have 3, 7, 1, 5 and 9 in their ones place. The numbers having 0, 2,
4, 6 and 8 in their ones place are only divisible by 2. So, these are not divisible by 2.

Question 3.
Are the numbers 452, 673, 259, 356 divisible by 2? Verify.
Solution:
452 and 356 have 2 and 6 in their ones place respectively.
So, they are divisible by 2.
673 and 259 have 3 and 9 in their ones place respectively.
So, they are not divisible by 2.

Question 4.
Check whether the following numbers are divisible by 3 (using rule). Verify by actual division.
(i) 12345 (ii) 61392 (iii)8747
Solution:
i)12345
1 + 2 + 3 + 4 + 5=15 is a multiple of 3.
If the sum of the digits of a number is the multiple of 3, then the number is divisible by 3.
So, 12345 is divisible by 3.

ii) 61392
6 + 1 + 3 + 9 + 2 = 21is a multiple,of 3.
If the sum of the digits of a number is a multiple of 3, then the number is divisible
by 3.

So, 61392 is divisible by 3.

iii) 8747
8 + 7 + 4 + 7 = 26is not a multiple of 3.
If the sum of the digits of a number is a multiple of 3, then the numbei is divisible by 3. So, 8747 is not divisible by 3.

So, 8747 is not divisible by 3.

Let’s Explore (Page No. 29)

Question 1.
Is 8430 divisible by 6? Why?
Given number is 8430.
The given number has zero in the ones place.
So, 8430 is divisible by 2. –
And the unit sum is8 + 4 + 3 + 0 = 15 is a multiple of 3.
So, 8430 is divisible by 3.
If a number is divisible by both 2 and 3, then only it is divisible by 6.
8430 is divisible by both 2 and 3.
Therefore 8430 is divisible by 6.

Question 2.
Take any three 4 digit numbers and check whether they are divisible by 6.
Solution:
Consider: i) 5632, ii) 6855, iii) 9600 are three 4 digit numbers.
i) 5632 has 2 in its ones place. So, 5632 is divisible by 2.
The unit sum is
5 + 6 + 3 + 2 = 16 is not a multiple of 3. So, 5632 is not divisible by 3.
If a number is divisible by both 2 and 3, then only it is divisible by 6.
5632 is qnly divisible by 2, but not divisible by 3.
So, 5632 is not divisible by 6.

ii) 6855 has 5 in the ones place. So, 6855 is not divisible by 2.
6 + 8 + 5 + 5 = 24 is a multiple of 3.
So, 6855 is divisible by 3.
If a number is divisible by both 2 and 3, then only it is divisible by 6.
6855 is not divisible by 2, but it is divisible by 3.
So, 6855 is not divisible by 6.

iii) 9600 has ‘0’ in the ones place. So, 9600 is divisible by 2.
9 + 6 + 0 + 0 = 15 is a multiple of 3.
So, 9600 is divisible by 3. .
If a number is divisible by both 2 and 3, then only it is divisible by 6, 9600 is divisible by 1 both 2 and 3.
So, 9600 is divisible by 6.

Question 3.
Can you give an example of a number which is divisible by 6 but not by 2 and 3? Why?
Solution:
No. We can’t give any example, because if any number is divisible by both 2 and 3, then only it is divisible by 6. Otherwise it is not possible.

Check Your Progress (Page No. 30 & 31))

Question 1.
Test whether 6669 is divisible by 9. ,
Solution:
Given number is 6669.
Sum of the digits = 6 + 6 + 6 + 9 = 27 is divisible by 9
If the sum of the digits of a number is divisible by 9 then, it is divisible by 9. ” 27 is divisible by 9. So, 6669 is divisible by 9.

Question 2.
Without actual division, find whether 8989794 is divisible by 9.
Solution:
Given number is 8989794.
Sum of the digits =8+9+8+9+7+9+4=54 – 1
If the sum of the digits of a number is divisible by 9.
Then, it is divisible by 9.
54 is divisible by 9. So, 8989794 is divisible by 9.

Question 3.
Are the numbers 28570, 90875 divisible by 5? Verify by actual division also.
Solution:
a) Given number be 28570.
The numbers with zero or five at ones place are divisible by 5
28570 has zero in its ones place. So, 28570 is divisible by 5.
Actual division :

So, 28570 is completely divisible by 5.

b) Given number is 90875
In 90875, ones place digit is 5. So, 90875 is divisible by 5.
Actual division :

In the given number 90875 the digit in the units place is 5,
‘ So, it is divisible by 5.
So, 90875 is divisible by 5.

Question 4.
Check whether the number 598, 864, 4782 and 8976 are divisible by 4. Use divisibility rule and verify by actual division.
Solution:
a) Given number is 598.
The number formed by the digits in tens and ones places of 598 is 98.
If the number formed by last two digits (Ones and Tens) of the number is divisible
by 4, then the number is divisible by 4.
98 is not divisible by 4. So, 598 is not divisible by 4.

b) Given number is 864.
The number formed by tens and ones places of 864 is 64.
If the number formed by last two digits (ones and tens)
of the number is divisible by 4, then the number is divisible by 4.
64 is divisible by 4. So, 864 is divisible by 4.

c) Given number is 4782.
The number formed by ones and tens places of 4782 is 82.
If the number formed by last two digits (ones and tens) of the number is divisible by 4, then the number is divisible by 4. 82 is not divisible by 4.

d) Given number is 8976.
The number formed by the digits in tens and ones places of 8976 is 76.
If the number formed by last two digits
(Tens and ones) of the number is divisible by 4. Then the number is divisible by 4.
76 is divisible by 4. So, 8976 is divisible by 4.

Question 1.
Fill the blanks and complete the table. (Page No. 32)
Solution:

Lets Explore (Page No.33)

Question 1.
1221 is a polindrome number, which on reversing its digits gives the same number. Thus, every polindrome number with even number of digits is always divisible by 11. Write polindrome number of 6 – digits.
Solution:

There are some polindrome number of 6 – difits.

Check Your Progress (Page No.34)

Question 1.
Find the factors of 60.
Solution:
60 = 1 x 60
60 = 2 x 30
60 = 3 x 20
60 = 4 x 15
60 = 5 x 12
60 = 6 x 10
∴ The factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.

Question 2.
Do all the factors of a given number divide the number exactly? Find the factors of 30 and verify by division.
30 = 1 x 30
30 = 3 x 10
30 = 2 x 15
30 = 5 x 6
The factors of 30 are 1, 2, 3, 5, 6,10, 15 and 30.

Yes, the factors of a given numbers are divide the number exactly.

Question 3.
3 is a factor of 15 and 24. Is 3 a factor of their difference also?
Solution:
Difference = 24 – 15 = 9 is the multiple of 3.
Yes, 3 is a factor of difference of 15 and 24.

Let’s Explore (Page No. 35)

Question 1.
What is the smallest prime number?
Solution:
2

Question 2.
What is the smallest composite number?
Solution:
4

Question 3.
What is the smallest odd prime number?
Solution:
3

Question 4.
What is the smallest odd composite number?
Solution:
9

Question 5.
Write 10 odd and 10 even composite numbers.
Solution:
Odd composite numbers are 9, 15, 21, 25, 27, 33, 35, 39, 45, 49.
Even composite numbers are 4, 6, 8, 10, 12, 14, 16, 18, 20, 22.
Except 2, every even number is a composite number.

Let’s Explore (Page No. 36)

Question 1.
Can you guess a prime number which when on reversing its digits, gives another prime number? (Hint a 2 digit prime number)
Solution:
13 and 31; 17 and 71, 37 and 73 79 and 97.

Question 2.
311 is a prime number. Can you find the other two prime numbers just by rearrang-ing the digits?
Solution:
113, 131

Check Your Progress (Page No. 36)

Question 1.
From the following numbers identify different pairs of co-primes. 2, 3,4, 5,6,7, 8, 9 and 10.
Solution:
The numbers which have only 1 as the common factor are called co-primes, (or) Numbers having no common factors, other than 1 are called co-primes.
2,3; 2, 5; 2, 7; 2, 9; 3,4; 3, 5; 3, 7; 3, 8; 3,10; 4,5; 4, 7; 4, 9; 5, 6; 5, 7; 5,8; 5, 9; 6, 7; 8, 9 and 9,10. These are the different pairs of co-primes with 2, 3, 4, 5, 6, 7, 8, 9 and 10.
1) Any two primes always forms a pair of co-primes.
2) Any two consecutive numbers always form a pair of co-primes.
3) Any two primes cilways form a pair of co-primes. .

Question 2.
Write the pairs of twin primes less than 50.
Solution:
Two prime numbers are said to be twin primes, if they differ each other by 2.
Twin primes less than 50 are (3, 5); (5, 7); (11,13); (17, 19); (29, 31) and (41, 43).

(Page No. 36)

Question 1.
Find the HCF of 12, 16 and 28
Solution:

Thus 12 = 2 x 2 x 3
16 = 2 x 2 x 2 x 2
28 = 2 x 2 x 7
The common factor of 12, 16 and 28 ¡s 2 x 2 = 4.
Hence, H.C.F of 12, 16 and 28 is 4.

Let’s Explore (Page No. 40)

What is the HCF of any two
i) Consecutive numbers ?
ii) Consecutive even numbers ?
iii) Consecutive odd numbers? What do you observe? Discuss with your Mends.
Solution:
Consider the two consecutive number are 5, 6 and 9, 10.

We observed that HCF of any two consecutive numbers is always 1.

ii) Consider two consecutive even numbers are 8, 10 and 20, 22.

We observed that HCF of any two consecutive even numbers is always 2.

iii)Consider the consecutive odd numbers are 7, 9 and 13, 15.

We observed that HCF of any two consecutive odd numbers is always 1.

(Page No. 42)

Question 1.
Find LCM of (i) 3, 4 (ii) 10, 11 (iii) 10, 30 (iv) 12, 24 (v) 3, 12 by prime factorization method.
Solution:
i) Given numbers are 3, 4
Factors of 3 = 1 x 3
Factors of 4 = 2 x 2
LCM of 3, 4 = 1 x 3 x 2 x 2 = 12

ii) Given numbers are 10, 11
Factors of 10 = 2 x 5
Factors of 11 = 1 x 11
LCM of 10, 11 = 2 x 5 x 11 = 110

iii) Given numbers are 10, 30
Factors of 10 = 2×5
Factors of 30 = 2x3x5
LCM of 10, 30 = 2 x 3 x 5 = 30

iv) Given numbers are 12, 24
Factors of 12 = 2x2x3 ,
Factors of 24 =. 2 x 2 x 2 x 3
LCM of 12, 24 = 2 x 2 x 2 x 3 = 24

v) Given numbers are 3,12 Factors of 3 = 1×3
Factors of 12 =2 x 2 x 3,
LCM of 3, 12 = 3 x 2 x 2 = 12

(Page No. 43)

Question 1.
What is the LCM and HCF of twin prime numbers ?
Solution:
LCM = Product of the taken twin primes and HCF = 1

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 5 Fractions and Decimals Ex 5.1 Textbook Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 5th Lesson Fractions and Decimals Ex 5.1

Question 1.
Classify the fractions as proper, improper and mixed.
\(\frac{3}{4}\), \(\frac{6}{5}\), \(\frac{3}{2}\),\(\frac{4}{1}\), \(\frac{2}{3}\), \(\frac{1}{4}\), \(\frac{18}{13}\), 1\(\frac{5}{7}\),\(\frac{1}{3}\), 11\(\frac{1}{2}\)
Answer:
If in a fraction numerator is less than the denominator, then it is called a proper fraction.
Proper fractions are \(\frac{3}{4}\), \(\frac{2}{3}\), \(\frac{1}{4}\), \(\frac{1}{3}\)
If in a fraction numerator is greater than the denominator, then it is called an improper fraction.
Improper fractions are \(\frac{6}{5}\), \(\frac{3}{2}\), \(\frac{4}{1}\), \(\frac{18}{13}\)
A combination of a whole number and a proper fraction is called a mixed fraction.
Mixed fractions are 1\(\frac{5}{7}\), 11\(\frac{1}{2}\)

Question 2.
Write the following fractions in an ascending order.
i) \(\frac{3}{4}\), \(\frac{3}{2}\), \(\frac{2}{3}\), \(\frac{1}{5}\), \(\frac{18}{7}\)
ii) \(\frac{2}{7}\), \(\frac{3}{8}\), \(\frac{3}{4}\), \(\frac{5}{7}\), \(\frac{4}{9}\)
Answer:
Given fractions are \(\frac{3}{4}\), \(\frac{3}{2}\), \(\frac{2}{3}\), \(\frac{1}{5}\), \(\frac{18}{7}\)
These are unlike fractions.
To arrange the unlike fractions in ascending order / descending order first we have to convert them into equivalent fractions with LCM of their denominators, then compare the like fractions (i.e.,) we convert them to like fractions.
LCM of Denominators = 2 × 2 × 3 × 5 × 7 = 420

\(\frac{315}{420}\), \(\frac{630}{420}\), \(\frac{280}{420}\), \(\frac{84}{420}\), \(\frac{1080}{420}\)
These are like fractions. Now, we can compare them.
\(\frac{84}{420}\)< \(\frac{280}{420}\) < \(\frac{315}{420}\) < \(\frac{630}{420}\) < \(\frac{1080}{420}\)
i.e, \(\frac{1}{5}\) < \(\frac{2}{3}\) < \(\frac{3}{4}\) < \(\frac{3}{2}\) < \(\frac{18}{7}\)
∴ Ascending order: \(\frac{1}{5}\), \(\frac{2}{3}\), \(\frac{3}{4}\), \(\frac{3}{2}\), \(\frac{18}{7}\)
Descending order: \(\frac{18}{7}\), \(\frac{3}{2}\), \(\frac{3}{4}\), \(\frac{2}{3}\), \(\frac{1}{5}\)

ii) \(\frac{2}{7}\), \(\frac{3}{8}\), \(\frac{3}{4}\), \(\frac{5}{7}\), \(\frac{4}{9}\)
These are unlike fractions.
To arrange the unlike fractions in ascending order / descending order first we have to convert them into equivalent fractions with LCM of their denominators. Then compare the like fractions (i.e.,) we convert them to like fractions.
LCM of denominators = 2 × 2 × 2 × 3 × 3 × 7 = 504

\(\frac{144}{504}\), \(\frac{189}{504}\), \(\frac{378}{504}\), \(\frac{360}{504}\), \(\frac{224}{504}\)
These are like fractions. Now, we can compare them.
\(\frac{144}{504}\) < \(\frac{189}{504}\) < \(\frac{224}{504}\) < \(\frac{360}{504}\) < \(\frac{1080}{420}\)
i.e, \(\frac{2}{7}\) < \(\frac{3}{8}\) < \(\frac{4}{9}\) < \(\frac{5}{7}\) < \(\frac{3}{4}\)
∴ Ascending order: \(\frac{2}{7}\), \(\frac{3}{8}\), \(\frac{4}{9}\), \(\frac{5}{7}\), \(\frac{3}{4}\)
Descending order: \(\frac{3}{4}\), \(\frac{5}{7}\), \(\frac{4}{9}\), \(\frac{3}{8}\), \(\frac{2}{7}\)

Question 3.
Without doing calculation, find the result \(\frac{2}{3}\) + 1\(\frac{3}{4}\) + \(\frac{1}{3}\) – \(\frac{1}{4}\)
Answer:
Given \(\frac{2}{3}\) + 1\(\frac{3}{4}\) + \(\frac{1}{3}\) – \(\frac{1}{4}\)

Question 4.
Neha bought a cake. She ate \(\frac{7}{15}\) th of the cake immediately add in the afternoon she ate the remaining part. How much part die ate in the afternoon ?
Answer:
Whole cake = 1 = \(\frac{15}{15}\)
Neha divided the cake into 15 parts.
Part of a cake eaten by Neha = \(\frac{7}{15}\)
Remaining part of cake = Whole – eaten part immediately
= \(\frac{1}{1}\) – \(\frac{7}{15}\)
= \(\frac{15}{15}\) – \(\frac{7}{15}\)
= \(\frac{15-7}{15}\)
= \(\frac{8}{15}\)
∴ Part of a cake eaten by Neha in the afternoon = \(\frac{8}{15}\)

Question 5.
Simplify:
i) \(\frac{2}{5}\) + \(\frac{1}{3}\)
ii) \(\frac{5}{7}\) + \(\frac{2}{3}\)
iii) \(\frac{3}{5}\) – \(\frac{7}{20}\)
iv) \(\frac{17}{20}\) – \(\frac{13}{25}\)
Answer:
i) \(\frac{2}{5}\) + \(\frac{1}{3}\)
LCM of denominators = 3 × 5 = 15

ii) \(\frac{5}{7}\) + \(\frac{2}{3}\)
LCM of denominators = 7 × 3 = 21

iii) \(\frac{3}{5}\) – \(\frac{7}{20}\)
LCM of denominators = 2 × 2 × 5 = 20

iv) \(\frac{17}{20}\) – \(\frac{13}{25}\)
LCM of denominators = 2 × 2 × 5 × 5 = 100

Question 6.
Represent \(\frac{16}{5}\) pictorially
Answer:
Given fraction is \(\frac{16}{5}\) (Improper fraction)
\(\frac{16}{5}\) = Mixed fraction is 3\(\frac{1}{5}\)

3 + \(\frac{1}{5}\) = 3\(\frac{1}{5}\)

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 1 Numbers All Around us Ex 1.3 Textbook Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 1st Lesson Numbers All Around us Exercise 1.3

Question 1.
Write each of the following numbers in digits by using International place value chart. Also write them in expanded form.
i) Nine million seven hundred thousand and six hundred five.
Answer:
9,700,605: 9,000,000 + 700,000 + 600 + 5

ii) Seven hundred million eight hundred seventy two thousand and four hundred seven.
Answer:
700,872,407: 700,000,000 + 800, 000 + 70,000 + 2000 + 400 + 7

Question 2.
Rewrite each of the following numerals with proper commas in the International system of numeration and write the numbers in word form.
i) 717858
ii) 3250672
iii) 75623562
iv) 956237676
Answer:
i) 717,858: Seven hundred seventeen thousand eight hundred and fifty eight.
ii) 3,250,672: Three million two hundred fifty thousand six hundred and seventy two.
iii) 75,623,562: Seventy five million six hundred twenty three thousand five hundred and sixty two.
iv) 956,237,676: Nine hundred fifty six million two hundred thirty seven thousand six hundred and seventy six.

Question 3.
Write the following number names in both Indian and International systems.
i) 6756327
ii) 45607087
iii) 8560707236
Answer:
i) 6756327
Indian system:
67,56,327: Sixty seven lakh fifty six thousand three hundred and twenty seven.
International system:
6,756,327: Six million seven hundred fifty six thousand three hundred and twenty seven.

ii) 45607087 Indian system:
4,56,07,087: Four crores fifty six lakhs seven thousand eighty seven.
International system:
45,607,087: Forty five million six hundred seven thousand and eighty seven.

iii) 8560707236 Indian system:
856,07,07,236: Eight hundred fifty six crores seven lakh seven thousand two hundred and thirty six.
International system:
8,560,707,236: Eight billion five hundred sixty million seven hundred seven thousand two hundred and thirty six.

Question 4.
Express the following numbers in other system.

S.No.	Indian	International
1.	42,56,876
2.		800,000,000
3.	956,76,72,345
4.		6,303,448,433

Answer:

S.No.	Indian	International
1.	42,56,876	4,256,876
2.	80,00,00,000	800,000,000
3.	956,76,72,345	9,567,672,345
4.	630,34,48,433	6,303,448,433

Question 5.
Write the following numbers in International system (Word Form).
i) Twenty Nine crore thirty five lakh forty six thousand seven hundred and fifty three.
Answer:
293,546,753
Word form: Two hundred ninety three million five hundred forty six thousand seven hundred and fifty three.

ii) Thousand crore ninety nine lakh and forty three.
Answer:
10,009,900,043
Word form: Ten billions nine million nine hundred thousand and forty three.

Question 6.
Write following numbers in Indian system (Word Form).
i) Nine billion twenty four million fifty thousand and seventy two.
Answer:
902,40,50,072
Word form: Nine hundred two crores forty lakhs fifty thousand and seventy two.

ii) Seven hundred billions six millions four thousand seven hundred and five.
Answer:
70000,60,04,705
Word form: Seventy thousand crores sixty lakhs four thousand seven hundred and five.

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 1 Numbers All Around us Ex 1.2 Textbook Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 1st Lesson Numbers All Around us Exercise 1.2

Question 1.
Write each of the following in numeral form.
i) Sixty crores seventy five lakhs ninety two thousands five hundred and two.
Answer:
60, 75, 92, 502

ii) Nine hundred forty four crores six lakhs fifty five thousand four hundred and eighty six.
Answer:
944, 06, 55, 486

iii) Ten crores ten thousand and ten.
Answer:
10,00,10,010

Question 2.
Insert commas in the correct positions to separate periods and write the following numbers in words.
i) 57657560
ii) 70560762
iii) 97256775613
Answer:
i) 5,76,57,560: Five crores seventy six lakhs fifty seven thousands five hundred and sixty.
ii) 7,05,60,762: Seven crores five lakhs sixty thousands seven hundred and sixty two.
iii) 9725,67,75,613: Nine thousand seven hundred and twenty five crores sixty seven lakhs seventy five thousand six hundred and thirteen.

Question 3.
Write the following in expanded form.
i) 756723
ii) 60567234
iii) 8500756762
Answer:
i) 756723
Expanded form: 7 × 1,00,000 + 5 × 10,000 + 6 × 1,000 + 7 × 100 + 2 × 10 + 3 × 1
: 7 lakhs + 5 ten thousands + 6 thousands + 7 hundreds + 2 tens + 3 ones
Word form: Seven lakh fifty six thousand seven hundred and twenty three.

ii) 60567234
Expanded form: 6 × 1,00,00,000 + 5 × 1,00,000 + 6 × 10,000 + 7 × 1,000 + 2 × 100 + 3 × 10 + 4 × 1
: 6 crores + 5 lakhs + 6 ten thousands + 7 thousands + 2 hundreds + 3 tens + 4 ones
Word form: Six crore five lakh sixty seven thousand two hundred and thirty four.

iii) 8500756762
Expanded form: 8 × 1,00,00,00,000 + 5 × 10,00,00,000 + 7 × 1,00,000 + 5 × 10,000 + 6 × 1000 + 7 × 100 + 6 × 10 + 2 × 1
: 8 hundred crores + 5 ten crores + 7 lakhs & 5 ten thousands + 6 thousands + 7 hundreds + 6 tens + 2 ones
Word form: Eight hundred and fifty crore seven lakh fifty six thousand seven hundred and sixty two.

Question 4.
Determine the difference between the place value and the face value of 6 in 86456792.
Answer:
Given number is 86456792. By putting commas to separate periods the given number can be written as 8,64,56,792.
i) Place value of ‘6’ in thousand place = 6 x 1000 = 6,000
Face value of 6 = 6
Difference = 6,000 – 6 = 5,994
ii) Place value of ‘6’ in ten lakhs palce = 6 x 10,00,000 = 60,00,000
Face value of 6 = 6
Difference = 60,00,000 – 6 = 59,99,994