AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 7 Coordinate Geometry Ex 7.4 Textbook Questions and Answers.

## AP State Syllabus SSC 10th Class Maths Solutions 7th Lesson Coordinate Geometry Exercise 7.4

### 10th Class Maths 7th Lesson Coordinate Geometry Ex 7.4 Textbook Questions and Answers

Question 1.

Find the slope of the line joining the two given points.

i) (4,-8) and (5,-2).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{-2+8}{5-4}\)

= 6

ii) (0, 0) and (√3, 3)

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{3-0}{\sqrt{3}-0}\)

= \(\frac{3}{\sqrt{3}}\)

= \(\frac{\sqrt{3} \times \sqrt{3}}{\sqrt{3}}\)

= √3

iii) (2a, 3b) and (a, -b).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{-b-3b}{a-2a}\)

= \(\frac{-4b}{-a}\)

= \(\frac{4b}{a}\)

iv) (a, 0) and (0, b).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{b-0}{0-a}\)

= \(\frac{-b}{a}\)

v) A (-1.4, -3.7), B (-2.4, 1.3).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{1.3+3.7}{-2.4+1.4}\)

= \(\frac{5.0}{-1}\)

= -5

vi) A (3, -2), B (-6, -2).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{-2+2}{-6-3}\)

= 0

vii) A (-3\(\frac{1}{2}\), 3), B (-7, 2\(\frac{1}{2}\)).

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{2 \frac{1}{2}-3}{-7+3 \frac{1}{2}}\)

= \(\frac{-\frac{1}{2}}{-3 \frac{1}{2}}\)

= \(\frac{1}{2}\) × \(\frac{2}{7}\)

= \(\frac{1}{7}\)

viii) A(0, 4), B(4, 0)

Answer:

Slope = \(\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

= \(\frac{0-4}{4-0}\)

= \(\frac{-4}{4}\)

= -1