{"id":23672,"date":"2022-09-03T11:48:50","date_gmt":"2022-09-03T06:18:50","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=23672"},"modified":"2022-09-03T11:48:50","modified_gmt":"2022-09-03T06:18:50","slug":"ap-inter-2nd-year-chemistry-important-questions-chapter-13","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-inter-2nd-year-chemistry-important-questions-chapter-13\/","title":{"rendered":"AP Inter 2nd Year Chemistry Important Questions Chapter 13 Organic Compounds Containing Nitrogen"},"content":{"rendered":"

Students get through AP Inter 2nd Year Chemistry Important Questions<\/a> 13th Lesson Organic Compounds Containing Nitrogen which are most likely to be asked in the exam.<\/p>\n

AP Inter 2nd Year Chemistry Important Questions 13th Lesson Organic Compounds Containing Nitrogen<\/h2>\n

Very Short Answer Questions<\/span><\/p>\n

Question 1.
\nGabriel Phthalimide synthesis exclusively forms primary amines only. Explain.
\nAnswer:
\nGabriel Phthalimide synthesis exclusively forms primary amines only.
\nReason: In this reaction primary amines are formed without the traces of 2\u00b0 (or) 3\u00b0 amines.<\/p>\n

Questions 2.
\nWrite equations for carbylamine reaction of any one aliphatic amine.
\nAnswer:
\nWhen Ethyl amine (1\u00b0 – amine) reacts with chloroform in presence of alkali to form ethyl isocyanide.
\nCH3<\/sub> – CH2<\/sub> – NH2<\/sub> + CHCl3<\/sub> + 3KOH A \"AP CH3<\/sub> – CH2<\/sub> – NC + 3KCl + 3H2<\/sub>O<\/p>\n

\"AP<\/p>\n

Question 3.
\nWhy aniline does not undergo Friedel \u2014 Crafts reaction?
\nAnswer:
\nAniline is a lewis base and AlCl3<\/sub> is a Lewis acid. In Friedel.Craft\u2019s reaction both of these combined to form a complex.
\n\"AP
\nDue to formation of complex the electrophilic substitution tendency decreases in aniline and it does not undergo this reaction.<\/p>\n

Question 4.
\nGive structures of A, B and C in the following reactIons. [T.S. Mar. 17] [A.P. & T.S. Mar. 16]
\n\"AP
\nAnswer:
\n\"AP
\nA – Phenyl Cyanide B – Benzoic acid C – Benzarnide<\/p>\n

Question 5.
\nWhy cannot aromatic primary amines be prepared by Gabriel phthalimide synthesis?
\nAnswer:
\nAromatic 1\u00b0 – amines cannot be prepared by Gabriel phthalinide synthesis because aryl halides do not undergo nucleophilic substitution with an ion formed by phthalinide.<\/p>\n

Question 6.
\nAccomplish the following conversions. [Mar. 14]
\ni) Benzolc acid to benzamide
\nii) Aniline to p – bromoanlline.
\nAns:
\nConversion of benzoic acid to benzamide
\n\"AP
\nii) Conversion of Aniline to p – bromoanlline.
\n\"AP<\/p>\n

Question 7.
\nHow are Amines prepared by Hoffmann bromamide degradation method.
\nAnswer:
\nHoffmann bromamide degradation method: In this method amides are directly converted into amines. When amides are treated with Br5<\/sub> in NaOH gives amine.
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 8.
\nWhat is Diazotisation reaction ? Give equation. [IPE 16, 14 (T.S.)]
\nAnswer:
\nDiazotisation reaction: Aromatic primary amines react with nitrous acid at low temperatures to form diazonium salts.
\n\"AP<\/p>\n

Question 9.
\nWhat is sulphonation ? Give equation.
\nAnswer:
\nSulphonation : Aniline reacts with cone H2<\/sub>SO4<\/sub> and forms anilinium hydrogen sulphate which on heating gives P – amino benzene sulphonic acid (sulphanilic acid) which exists as Zwitter ion.
\n\"AP
\nAniline does not undergo Friedel crafts reactiondue to salt formation with AlCl3<\/sub>.<\/p>\n

Question 10.
\nArrange the following bases in increasing order of their basic strength. Aniline, P – nitroaniline and P – toluidine.
\nAnswer:
\nThe increasing order of basic strength of given compounds is
\nP – nitroaniline < aniline < P – toluidine
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 11.
\nHow is benz ene diazonium chloride prepared? Give equation.
\nAnswer:
\nPreparation: Benzene diazomum chloride is prepared by the reaction of aniline with nitrous acid at 273 – 278K. The conversion of primary aromatic amine into diazonium chloride is called Diazotisation.
\n\"AP<\/p>\n

Question 12.
\nArrange the following bases in decreasing order of pHb<\/sub>, values. C2<\/sub>H5<\/sub>NH2<\/sub>, C6<\/sub>H5<\/sub>NHCH3<\/sub>, (C2<\/sub>H5<\/sub>)2<\/sub> NH and C6<\/sub>H5<\/sub>NH2<\/sub>.
\nAnswer:
\nThe decreasing order of pKb values of given amines is
\nC6<\/sub>H5<\/sub>NH2<\/sub> > C6<\/sub>H5<\/sub>NHCH3<\/sub> > C6<\/sub>H5<\/sub>NH2<\/sub> > (C2<\/sub>H5<\/sub>)2<\/sub> NH<\/p>\n

Question 13.
\nWhat is a coupling reaction ? Give equation. .
\nAnswer:
\nCoupling reactions : The azoproducts obtained when diazonium slats react with aromatic compounds have extended conjugated system through N = N. This reaction is called coupling reaction and the prodocuts formed are coloured.
\na) Reaction with Phenol
\n\"AP<\/p>\n

Question 14.
\nHow do you convert aniline to parabromo aniline. [IPE 2014]
\nAnswer:
\nAniline is first acylated to give acetaniiyde which on bromination gives parabromo derivative. This bromo derivative on hydrolysis gives parabromo aniline.
\n\"AP<\/p>\n

Question 15.
\nHow is Aniline prepared. [IPE 2016 (TS)]
\nAnswer:
\nAniline is prepared by reduction of nitro benzene in acid medium.
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 16.
\nExplain why ethylamine is more soluble in water where as aniline is not soluble.
\nAnswer:
\nEthyl amine is a primary amine, due to intermolecular hydrogen bonding with water molecules it is soluble in water. Though Aniline has – NH2<\/sub> group, due to hydrophobic aryl group it is not soluble in water.<\/p>\n

Short Answer Questions<\/span><\/p>\n

Question 1.
\nExplain with a suitable example how benzene sulphonylchloride can distinguish primary, secondary and tertiary amines.
\nAnswer:
\nBenzene sulphonyl chloride is called Hinsberg’s reagent. This is used to distinguish the 1\u00b0, 2\u00b0, 3\u00b0 – amines.<\/p>\n