{"id":16980,"date":"2022-01-29T14:39:08","date_gmt":"2022-01-29T09:09:08","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=16980"},"modified":"2023-03-29T16:18:45","modified_gmt":"2023-03-29T10:48:45","slug":"ap-board-7th-class-maths-solutions-chapter-7-unit-exercise","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-board-7th-class-maths-solutions-chapter-7-unit-exercise\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 7 Ratio and Proportion Unit Exercise"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 7 Ratio and Proportion Unit Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 7th Lesson\u00a0Ratio and Proportion Unit Exercise<\/h2>\n

Question 1.
\nIf the cost of 7 toys is \u20b9 1575, then what would be the cost of 6 such toys?
\nAnswer:
\nWe know that the number of toys decreases, the cost also decreases such that the ratio of the number of toys and the ratio of their costs will remain the same. That means here number of toys and the cost are in direct proportion.
\nLet the cost of 6 toys be x.
\nThen 7 : 1575 = 6 : x
\nIf the ratios are equal, the product of extremes = Product of means
\n\u21d2 7 \u00d7 x = 1575 x 6
\n\"AP
\n\u21d2 x = \u20b9 1350
\n\u2234 Cost of 6 toys is \u20b9 1350.<\/p>\n

\"AP<\/p>\n

Question 2.
\nA boy went to a hotel and wants to buy 5 plates of Idly worth \u20b9 24 each. After, going to Hotel he observed that rates of Idly were increased to \u20b9 30. Now if the boy wants to buy idlies, how many plates of idlies he can buy with the same amount?
\nAnswer:
\nIf the cost of idly increases number of plates decreases.
\nSo, cost of idly and number of plates are in inverse proportion.
\nLet number of plates at \u20b9 30 for the same amount is x.<\/p>\n\n\n\n\n\n
Cost of each Idly Plate<\/td>\nNumber of Plates<\/td>\n<\/tr>\n
24<\/td>\n5<\/td>\n<\/tr>\n
30<\/td>\nx<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

By taking inverse proportion, 24 : 30 = x : 5
\nThen, Product of means = Product of extremes
\n\"AP
\nNumber of Plates at \u20b9 30 for the same amount is 4.<\/p>\n

Question 3.
\nRaju covers a distance of 28 kilometers in 2 hours. Find the time taken by him to cover a distance of 56 km with the same speed.
\nAnswer:
\nWe know that as number of kilometers (distance) increases the time taken also increases with the same speed. That means distance and the time taken are in direct proportion.<\/p>\n

Let the time taken to cover the 56 km distance is x hours.
\nThen 28 : 2 = 56 : x<\/p>\n

If the ratios are equal, the product of extremes = the product of means
\n\"AP
\nThe time taken to cover the 56 km distance is 4 hours.<\/p>\n

Question 4.
\n24 men working at 8 hours per day can do a piece of work in 15 days. In how many days 20 men working 9 hours per day do the same work?
\nAnswer:
\nHere, we have three quantities number of workers, number of hours and number of days.<\/p>\n\n\n\n\n\n
Number of Men<\/td>\nHours<\/td>\nNumber of Days<\/td>\n<\/tr>\n
24<\/td>\n8<\/td>\n15<\/td>\n<\/tr>\n
20<\/td>\n9<\/td>\nx<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Here the number of worker’s inversely proportional to number of hours perday.
\nHere the number of workers inversely proportional to number of days.<\/p>\n

Let the number of days be ‘x’.
\nSince number of workers depends on both number of hours and number of days, we will take compound ratio of
\n24 : 20 and 8 : 9 is 24 \u00d7 8 : 20 \u00d7 9<\/p>\n

Since the ratios are equal,
\nThe product of means = The product of extemes
\n\"AP
\n\u2234 Number of days required to complete 20 men at 9 hours per day is 16.<\/p>\n

Question 5.
\nOut of 15000 voters in a constituency, 60% of the voters voted. Find the number of people not voted in the constituency.
\nAnswer:
\nGiven number of voters in the constituency = 15000 Percentage of voters voted = 60 %
\nNumber of people voted = 60% of 15000
\n\"AP
\nNumber of people voted in the constituency = 9000
\nNumber of people not voted = 15000 – 9000
\n\u2234 Number of people not voted = 6000<\/p>\n

\"AP<\/p>\n

Question 6.
\nA shopkeeper bought a suitcase for \u20b9 950 and sold it for \u20b9 1200. Find its profit or loss percentage.
\nAnswer:
\nGiven cost price of suitcase = \u20b9 950
\nSelling price of suitcase = \u20b9 1200
\nS.P > C.P
\nSo, shopkeeper got profit.
\nProfit = S.P – C.P = 1200 – 950 = \u20b9 250
\n\"AP
\n\u2234 Profit percent = 26\\(\\frac{6}{19}\\)%.<\/p>\n

Question 7.
\nOn selling a mobile for \u20b9 4500, the shopkeeper losses 10%. For what amount should be selling it to gain 15%?
\nAnswer:
\nMethod 1 :
\nGiven selling of mobile = \u20b9 4500
\nLoss = 10%
\n\"AP
\nS.P = C.P – Loss
\n\"AP
\n\u2234 x = 5000<\/p>\n

Method 2:
\nLet the C.P of mobile = 100%
\nS.P at a loss of 10% = (100 – 10)%
\n= \u20b9 4500
\n90% of C.P = \u20b9 450O
\nS.P at a gain of 15% = (100 + 15)%.
\n= 115%
\nSo, if 90% of CP = \u20b9 4500
\n115% of CP = ?
\ns.p= \\(\\frac{115}{90}\\) \u00d7 4500= \u20b9 5750
\n\u2234 Cost price of mobile = \u20b9 5000
\nIf he gain 15%.<\/p>\n

Gain = 15% of 5000
\n\"AP
\nS.P = C.P + Gain = 5000 + 750
\n\u2234 Selling price of Mobile = \u20b9 5750<\/p>\n

Question 8.
\nA carpenter allows 15% discount on his goods. Find the markedprice of a chair which is sold by him for \u20b9 680.
\nAnswer:
\nGiven selling price = \u20b9 680
\nDiscount percent = 15%
\nLet marked price = x
\n\"AP
\nNote:
\n85% of M.P = \u20b9 680
\n100% of M.P = \\(\\frac{100}{85}\\) \u00d7 680
\n= \u20b9 800.<\/p>\n

\"AP<\/p>\n

Question 9.
\nWhat Is the simple Interest accrued on asum of \u20b9 75000 at the rate of 11% for 3 years? Find the total amount.
\nAnswer:
\nGiven Principle = \u20b9 7500
\nRate of Interest = 11%
\nTime = 3 years
\n\"AP
\nTotal amount = Principle + Interest = \u20b9 75000 + \u20b9 24750
\n\u2234 Total amount = \u20b9 99,150<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 7 Ratio and Proportion Unit Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 7th Lesson\u00a0Ratio and Proportion Unit Exercise Question 1. If the cost of 7 toys is \u20b9 1575, then what would be the cost of 6 such toys? Answer: We know that the … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":37555,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"https:\/\/apboardsolutions.com\/wp-content\/uploads\/2022\/01\/Chapter-7-Ratio-and-Proportion-Unit-Exercise.png","_links":{"self":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16980"}],"collection":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/comments?post=16980"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16980\/revisions"}],"predecessor-version":[{"id":16981,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16980\/revisions\/16981"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media\/37555"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media?parent=16980"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/categories?post=16980"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/tags?post=16980"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}