{"id":16957,"date":"2022-01-29T10:56:40","date_gmt":"2022-01-29T05:26:40","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=16957"},"modified":"2023-03-29T16:13:23","modified_gmt":"2023-03-29T10:43:23","slug":"ap-board-7th-class-maths-solutions-chapter-6-intext-questions-new-syllabus","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-board-7th-class-maths-solutions-chapter-6-intext-questions-new-syllabus\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 6 Data Handling InText Questions"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 6 Data Handling InText Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 6th Lesson Data Handling InText Questions<\/h2>\n

[Page No. 108]<\/span><\/p>\n

Where does the Arithmetic Mean lie?
\nThe marks obtained by Sarala, Bindu, Geeta, and Rekha in Telugu, Hindi, and English are given below.
\n\"AP
\nAnswer:
\nNow, let us calculate the average marks obtained by the students in each subject.<\/p>\n

\"AP
\nAnswer:
\n\"AP<\/p>\n

\"AP<\/p>\n

(i) What do you observe from the above table ?
\nAnswer:
\nMean always lie between the maximum and minimum values\/observations of the data.<\/p>\n

(ii) Does the mean lies between maximum and minimum values in each case ?
\nAnswer:
\nYes, Its always true.
\ni.e., Mean always lies between the maximum and minimum values of the data.<\/p>\n

Check Your Progress [Page No: 109]<\/span><\/p>\n

Question 1.
\nFind the Arithmetic Mean of first three multiples of 5 ?
\nAnswer:
\nGiven, first three multiples of 5 are: 5, 10, 15.
\nSum of observations = 5 + 10 + 15 = 30
\nNumber of observations = 3
\nArithmetic mean =\\(\\frac{\\text { Sum of observations }}{\\text { Number of observations }}\\) = \\(\\frac{30}{3}\\) = 10
\n\u2234 Arithmetic mean of first three multiples of 5 is 10.<\/p>\n

Let’s Explore [Page No. 109]<\/span><\/p>\n

Collect the information about the weights of any ten students of your class in kilograms arid answer the following:
\n\"AP
\nAnswer:<\/p>\n\n\n\n\n\n\n\n\n\n\n\n\n\n
Name of the student<\/td>\nWeight in kilograms<\/td>\n<\/tr>\n
Aditya<\/td>\n38<\/td>\n<\/tr>\n
Kishore<\/td>\n39<\/td>\n<\/tr>\n
Balu<\/td>\n40<\/td>\n<\/tr>\n
Sreeja<\/td>\n36<\/td>\n<\/tr>\n
Sreekari<\/td>\n35<\/td>\n<\/tr>\n
Kairavi<\/td>\n3.7<\/td>\n<\/tr>\n
Swathi<\/td>\n36<\/td>\n<\/tr>\n
Kirshna<\/td>\n41<\/td>\n<\/tr>\n
Ram<\/td>\n39<\/td>\n<\/tr>\n
Prasad<\/td>\n39<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Question 1.
\nWhat are the greatest and smallest weights ?
\nAnswer:
\nKrishna = 41 kg – Greatest weight
\nSreekari = 35 kg – Smallest weight<\/p>\n

\"AP<\/p>\n

Question 2.
\nFind Arithmetic mean of collected data.
\nAnswer:
\nGiven observations: 38, 39, 40, 36, 35, 37, 36, 41, 39, 39.
\nSum of observations = 38 + 39 + 40 + 36 + 35 + 37 + 36 + 41 + 39 + 39 = 380
\nNumber of observations = 10
\nArithmetic Mean = \\(\\frac{\\text { Sum of observations }}{\\text { Number of observations }}\\) = \\(\\frac{380}{10}\\) = 38 kg.
\nNumber of observations 10
\n\u2234 Arithmetic mean weight of 10 students of our class is 38 kg.<\/p>\n

Question 3.
\nVerify whether Arithmetic Mean lies between greatest and smallest observations or not.
\nAnswer:
\nYes, Arithmetic mean 38 kg lies between greatest weight 41 kg and smallest weight 35 kg.<\/p>\n

Check Your Progress [Page No. 110]<\/span><\/p>\n

Question 1.
\nWhat is the range of first ten whole numbers?
\nAnswer:
\nFirst ten wh4\u2019e numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
\nMaximum value = 9
\nMinimum value = 0
\nRange = Maximum Value – Minimum Value = 9 – 0 = 9
\n\u2234 Range = 9<\/p>\n

Check Your Progress [Page No. 111]<\/span><\/p>\n

Find the mode of 10, 9, 12, 10, 8, 7, 6, 10, 9, 7, 8, 5 and 2.
\nAnswer:
\nGiven data : 10, 9, 12, 10, 8, 7, 6, 10, 9, 7, 8, 5 and 2.
\nBy arranging the numbers with same values together.
\n2, 5, 6, 7, 7, 8, 8, 9, 9, 10, 10, 10, 12
\nAs ’10’ occurs more frequently than other observations.
\n\u2234 Mode = 10<\/p>\n

Let’s Explore [Page No. 111]<\/span><\/p>\n

Take a dice, roll it 20 times and record the numbers you got on its top face. Find the ‘Mode’ of resulting numbers.
\nAnswer:
\nA dice rolled 20 times and the numbers are
\n2, 4, 5, 3, 1, 6, 5, 4, 2, 1, 3, 5, 4, 2, 6, 2, 2, 5, 1, 3.
\nBy arranging the numbers with same values together
\n1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 5, 6, 6.
\nAs 2 occurs more frequently than other observations.
\nMode = 2.<\/p>\n

\"AP<\/p>\n

Let’s Think [Page No: 111]<\/span><\/p>\n

The following data shows that the number of hours spent by students for study. Find the mode:
\n\"AP
\nAnswer:
\nIn the given data more number of students spend 1 hour for study.
\nSo, mode of the data = 4.<\/p>\n

Check Your Progress [Page No: 114]<\/p>\n

What is the median of first 7 prime numbers ?
\nAnswer:
\nFirst 7 prime numbers are 2, 3, 5, 7, 11,13, 17.
\nArrange the given observations in ascending order
\n\"AP
\nIn seven observations the 4th observation 7 is the middle most value.
\n\u2234 Median = 7.<\/p>\n

Let’s Explore [Page Mo. 114]<\/span><\/p>\n

Question 1.
\nCollect 10th class pass percentage for last six years of your school (or) your near by school. Find median of the data.
\nAnswer:
\n10th Class pass percentage for last six years of our school are: 100%, 98%, 93%, 95%, 96%, 97%.
\nArrange the given observations in ascending order.
\n\"AP
\nIn six observations the 3rd and 4th observations are 96% and 97%.
\nHere, we have two middle most values 96% and 97%.
\nMedian = Average of two middle most values
\n= \\(\\frac{96+97}{2}\\) = 96.5%
\n\u2234 Median of the data = 96.5%<\/p>\n

\"AP<\/p>\n

Project Work [Page No: 114]<\/span><\/p>\n

Visit any vegetable market along with your parent. Collect the information about the costs of different vegetables. By using this data fill the following table.
\n\"AP
\nAnswer:
\n\"AP<\/p>\n

[Page No. 115]<\/span><\/p>\n

Prasanna wanted to buy a mobile phone. He selected two mobile phones of different companies having same features. Now he would like to know which mobile phone has good performance. He collected the information of star rating from different magazines and news papers.<\/p>\n

\"AP<\/p>\n

Question 1.
\nWhat information is given in the table ?
\nAnswer:
\nThe table is showing information about the mobile phones.<\/p>\n

Question 2.
\nIs the above information being useful to Prasanna ?
\nAnswer:
\nYes.<\/p>\n

\"AP<\/p>\n

Question 3.
\nWhich mobile phone you will suggest to Prasanna ?
\nAnswer:
\nMobile A. (21 + \\(\\frac{1}{2}\\) + \\(\\frac{1}{2}\\) rating)<\/p>\n

Check Your Progress [Page No. 116]<\/span><\/p>\n

Observe the adjacent bar graph and answer the following.<\/p>\n

\"AP<\/p>\n

Question 1.
\nWhich fruit most of the people like ?
\nAnswer:
\nMost of the people liked Apple.<\/p>\n

Question 2.
\nHow many people likes banana?
\nAnswer:
\n10.<\/p>\n

Observe the following graph. [Page No. 116]<\/span><\/p>\n

\"AP<\/p>\n

Observe the above double bar graph and answer the following:<\/p>\n

Question 1.
\nIn which year the sales of both mobile phone companies are equal ?
\nAnswer:
\n2018.<\/p>\n

Question 2.
\nIn 2017, which mobile phone company has more sales ?
\nAnswer:
\nMobile phone – A.<\/p>\n

\"AP<\/p>\n

Examples<\/span><\/p>\n

Question 1.
\nMid Day Meal (MDM) taken by the students in six days are 132, 164, 145, 182, 163 and 114, Find Arithmetic Mean of students who took MDM per day.
\nAnswer:
\nGiven, number of students who took MDM 132, 164, 145, 182, 163, 114.
\nArithmetic Mean = \\(\\frac{\\text { Sum of observations }}{\\text { Number of observations }}\\)
\n= \\(\\frac{132+164+145+182+163+114}{6}\\)
\n= \\(\\frac{900}{6}\\)
\n= 150<\/p>\n

Question 2.
\nAges of students (in years) are 8, 5, 6, 6, 5, 7, 5, 6, 5, 4 7, 6, 7, 6, 5 8 and 6 find the mode of given data.
\nAnswer:
\nGiven, ages of students are 8, 5, 6, 6, 5, 7, 5, 6, 5, 4, 7, 6, 7, 6, 5, 8, 6.
\nBy arranging the numbers with same values together
\n4, 5, 5, 5, 5,5,6, 6,6,6, 6, 6,7,7, 7, 8, 8.
\nAs 6\u2019 occurs more frequently than other observations.
\n\u2234 Mode = 6<\/p>\n

Question 3.
\nFind the mode of the data of Grades A, B, E, A, C, E, B, C, D, A, D, C, F, A and C.
\nAnswer:
\nGiven, A, B, E, A, C, E, B, C, D, A, D, C, F, A, C.
\nBy arranging the letters of same type together
\nA, A, A, A, B, B, C, C, C, C, D, D, E, E, F
\nAs \u2018A\u2019 and \u2018C\u2019 occurs most frequently in the data.
\n\u2234 Mode = A and C<\/p>\n

Question 4.
\nFind the median of data 32, 43, 25, 67, 46, 71 and 182.
\nAnswer:
\nGiven 32, 43, 25, 67, 46, 71, 182
\nArrange the given observations in ascending order.
\n\"AP
\nIn ‘7’ observations the 4th observation is the middle most value.
\n\u2234 Median = 46.<\/p>\n

\"AP<\/p>\n

Question 5.
\nThe monthly incomes of 8 members are \u20b98000, \u20b99000, f8200, \u20b97900, \u20b98500, \u20b98600, \u20b97700 and \u20b960000. Find the median income.
\nAnswer:
\nGiven that, the monthly incomes of 8 members are:
\n\u20b98000, \u20b99000, \u20b98200, \u20b97900, \u20b98500, \u20b98600, \u20b97700, \u20b960000
\nArrange the given observations in ascending order.
\n\"AP
\nHere, we have two middle most values 8200 and 8500.
\nIn this case, Median = Average of two middle most values
\n8200 + 8500 16700
\n= \\(\\frac{8200+8500}{2}\\) = \\(\\frac{16700}{2}\\) = \u20b98,350<\/p>\n

Question 6.
\nThe number of CFL bulbs and LED bulbs by a seller every month from March to August are given below. Draw by vertical double bar graph.<\/p>\n\n\n\n\n\n\n\n\n\n
Month<\/td>\nCFL Bulbs<\/td>\nLED Bulbs<\/td>\n<\/tr>\n
March<\/td>\n70<\/td>\n75<\/td>\n<\/tr>\n
April<\/td>\n35<\/td>\n30<\/td>\n<\/tr>\n
May<\/td>\n65<\/td>\n75<\/td>\n<\/tr>\n
June<\/td>\n90<\/td>\n100<\/td>\n<\/tr>\n
July<\/td>\n22<\/td>\n35<\/td>\n<\/tr>\n
August<\/td>\n50<\/td>\n50<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Answer:
\nSteps in drawing a Double bar graph:<\/p>\n

    \n
  1. Draw X-axis (horizontal line) and Y – axis (vertical line) on the graph paper and mark their intersection point as ‘O’.<\/li>\n
  2. Take ‘months’ on X – axis.<\/li>\n
  3. Take number of CFL and LED bulbs on Y ~ axis.<\/li>\n
  4. Take an appropriate scale on Y-axis so that number of both the bulbs can be shown easily. Here the maximum value to be plotted on Y – axis as 100, so let us take 1 cm =10 bulbs on Y – axis.<\/li>\n
  5. Find the length of each bar by dividing the value by 10 (as scale is 1 cm = 10 bulbs).<\/li>\n<\/ol>\n

    Eg: Length of bar represents 70 CFL bulbs = \\(\\frac{70}{10}\\) = 7 cm
    \nLength of bar represents 75 LED bulbs = \\(\\frac{75}{10}\\) = 7.5 cm<\/p>\n

    \"AP<\/p>\n

    Question 6.
    \nDraw the bars of uniform width representing ‘CFL bulb’ and ‘LED bulb’ side by side of every month.
    \n\"AP<\/p>\n

    Observe the adjacent figure:<\/p>\n

    \"AP<\/p>\n

    Question 1.
    \nLargest portion of the circle is shaded by which colour ?
    \nAnswer:
    \nRed.<\/p>\n

    Question 2.
    \nAre the portions of circle shaded by blue and pink are in same size ?
    \nAnswer:
    \nNo.<\/p>\n

    Question 3.
    \nSmallest portion of the circle is shaded by which colour ?
    \nAnswer:
    \nYellow.<\/p>\n

    \"AP<\/p>\n

    Question 2.
    \nObserve the below picture which shows various expenses of Manasa’s family:
    \n\"AP<\/p>\n

    (i) For which item highest amount spent?
    \nAnswer:
    \nFood.<\/p>\n

    (ii) For which items same amount spent?
    \nAnswer:
    \nCharity and Education.<\/p>\n

    (iii) For which item least amount spent?
    \nAnswer:
    \nOthers.<\/p>\n

    Question 7.
    \nIn a school, there are 100 students in class VII and every student is a member of any one of the club. The following table shows the number of students in various clubs, then Construct the pie chart to following data:<\/p>\n\n\n\n\n\n\n\n\n
    Club<\/td>\nNumber of members<\/td>\n<\/tr>\n
    Mathematics<\/td>\n50<\/td>\n<\/tr>\n
    Science<\/td>\n30<\/td>\n<\/tr>\n
    Social Studies<\/td>\n40<\/td>\n<\/tr>\n
    English<\/td>\n40<\/td>\n<\/tr>\n
    Arts<\/td>\n20<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

    Answer:
    \nThe angle of each sector will depend on the ratio between the number of students in club and total number of students.
    \nAngle of sector = \\(\\frac{\\text { Value of the item }}{\\text { Sum of the values of all items }}\\) \u00d7 360\u00b0<\/p>\n

    \"AP<\/p>\n

    Steps of construction:<\/p>\n

      \n
    1. Draw a circle with any convenient radius and mark it’s centre as ‘O’.<\/li>\n
    2. Mark a point A, somewhere on the circumference and join OA.<\/li>\n
    3. Construct \u2220AOB = 100\u00b0 to represent angle of the sector for Maths club.<\/li>\n
    4. Construct \u2220BOC = 60\u00b0 to represent angle of the sector for Science club.<\/li>\n
    5. Construct \u2220COD = 80\u00b0 to represent angle of the sector for Social Studies club.<\/li>\n
    6. Construct \u2220DOE = 80\u00b0 to represent angle of the sector for English club.<\/li>\n
    7. Now \u2220EOA = 40\u00b0 to represent angle of the sector for Arts club.<\/li>\n<\/ol>\n

      \"AP<\/p>\n

      \"AP<\/p>\n

      Practice Questions [Page No: 124]<\/span><\/p>\n

      In the following alphabetical series, a term (next term) is missing. Choose the missing term from the options.<\/p>\n

      Question 1.
      \nB, F, J, N, R,\u2019V, …..
      \n(a) Z
      \n(b) W
      \n(c) X
      \n(d) Y
      \nAnswer:
      \n(a) Z<\/p>\n

      Explaination:
      \n\"AP
      \nSo, answer is Z.<\/p>\n

      Question 2.
      \nA, C, E, G, I, K, …..
      \n(a) P
      \n(b) O
      \n(c) N
      \n(d) M
      \nAnswer:
      \n(d) M<\/p>\n

      Explaination:
      \n\"AP
      \nSo, answer is M.<\/p>\n

      Question 3.
      \nM, O, R, T, …….
      \n(a) W
      \n(b) U
      \n(c) V
      \n(d) Q
      \nAnswer:
      \n(a) W<\/p>\n

      Explaination:
      \n\"AP
      \nSo, answer is W.<\/p>\n

      \"AP<\/p>\n

      Question 4.
      \nU, S, P, L, …….
      \n(a) F
      \n(b) G
      \n(c) H
      \n(d) I
      \nAnswer:
      \n(b) G<\/p>\n

      Explaination:
      \n\"AP
      \nSo, answer is G.<\/p>\n

      Question 5.
      \nZA, YB, XC, WD,
      \n(a) UE
      \n(b) EV
      \n(c) VE
      \n(d) SH
      \nAnswer:
      \n(c) VE<\/p>\n

      Explaination:
      \n\"AP
      \nSo, answer is VE.<\/p>\n

      Question 6.
      \nAM, BO, CQ, DS, EU, …………
      \n(a) WF
      \n(b) FU
      \n(c) GV
      \n(d) FW
      \nAnswer:
      \n(d) FW<\/p>\n

      Explaination:
      \n\"AP
      \nIn the series next word is FW.<\/p>\n

      \"AP<\/p>\n

      Question 7.
      \nZY, XV, UR, QM, …..
      \n(a) LG
      \n(b) LI
      \n(c) LH
      \n(d) KJ
      \nAnswer:
      \n(a) LG<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is LG.<\/p>\n

      Question 8.
      \nAC, DF, GI, JL, …..
      \n(a) NO
      \n(b) MO
      \n(c) MN
      \n(d) NP
      \nAnswer:
      \n(b) MO<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is MO.<\/p>\n

      Question 9.
      \nDN, EM, FL, GK, HJ, …..
      \n(a) IK
      \n(b) GI
      \n(c) IJ
      \n(d) II
      \nAnswer:
      \n(d) II<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is II.<\/p>\n

      \"AP<\/p>\n

      Question 10.
      \nCBA, STU, FED, VWX,
      \n(a) IHG
      \n(b) GHI
      \n(c) IJK
      \n(d) YZA
      \nAnswer:
      \n(a) IHG<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is IHG.<\/p>\n

      Question 11.
      \nAZC, DYF, GXI, JWL
      \n(a) OVM
      \n(b) UNV
      \n(c) MVO
      \n(d) MNO
      \nAnswer:
      \n(c) MVO<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is MVO.<\/p>\n

      Question 12.
      \nABK, CDL, EFM, GHN,
      \n(a) JIO
      \n(b) IJO
      \n(c) MNO
      \n(d) ONM
      \nAnswer:
      \n(b) IJO<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is IJO.<\/p>\n

      Question 13.
      \nA2C, D5F, G8I, J11L, …..
      \n(a) Ml40
      \n(b) Ml20
      \n(c) N15P
      \n(d) N12P
      \nAnswer:
      \n(a) Ml40<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is M140.<\/p>\n

      \"AP<\/p>\n

      Question 14.
      \nA, CD, HIJ, PQRS, …………..
      \n(a) ZABCD
      \n(b) ZYXW
      \n(c) ABCDE
      \n(d) RSTUV
      \nAnswer:
      \n(c) ABCDE<\/p>\n

      Explaination:
      \n\"AP
      \nSo, in the series next word is ABCDE.<\/p>\n

      Question 15.
      \nA, BC, DEF, GHIJ,
      \n(a) KLMNP
      \n(b) LMNOP
      \n(c) KLMNO
      \n(d) JKLMN
      \nAnswer:
      \n(c) KLMNO<\/p>\n

      Explaination:
      \nA BC DEF GHIJ KLMNO
      \nSo, in the series next word is KLMNO.<\/p>\n","protected":false},"excerpt":{"rendered":"

      SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 6 Data Handling InText Questions and Answers. AP State Syllabus 7th Class Maths Solutions 6th Lesson Data Handling InText Questions [Page No. 108] Where does the Arithmetic Mean lie? The marks obtained by Sarala, Bindu, Geeta, and Rekha in Telugu, Hindi, and English are given below. Answer: Now, … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":37545,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"https:\/\/apboardsolutions.com\/wp-content\/uploads\/2022\/01\/Chapter-6-Data-Handling-InText-Questions.png","_links":{"self":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16957"}],"collection":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/comments?post=16957"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16957\/revisions"}],"predecessor-version":[{"id":16958,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16957\/revisions\/16958"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media\/37545"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media?parent=16957"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/categories?post=16957"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/tags?post=16957"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}