{"id":16891,"date":"2022-01-28T16:39:16","date_gmt":"2022-01-28T11:09:16","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=16891"},"modified":"2023-03-29T16:10:52","modified_gmt":"2023-03-29T10:40:52","slug":"ap-board-7th-class-maths-solutions-chapter-2-review-exercise","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-board-7th-class-maths-solutions-chapter-2-review-exercise\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 2 Fractions, Decimals and Rational Numbers Review Exercise"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 2 Fractions, Decimals and Rational Numbers Review Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Review Exercise<\/h2>\n

Question 1.
\nWrite the following fractions in ascending order.
\n(i) \\(\\frac{3}{2}, \\frac{5}{2}, \\frac{1}{2}, \\frac{17}{2}, \\frac{9}{2}\\)
\nAnswer:
\nGiven \\(\\frac{3}{2}, \\frac{5}{2}, \\frac{1}{2}, \\frac{17}{2}, \\frac{9}{2}\\)
\nGiven fractions are like fractions.<\/p>\n

So, we should arrange the numerators in ascending order.
\n\\(\\frac{1}{2}<\\frac{3}{2}<\\frac{5}{2}<\\frac{9}{2}<\\frac{17}{2}\\)<\/p>\n

Ascending order: \\(\\frac{1}{2}<\\frac{3}{2}<\\frac{5}{2}<\\frac{9}{2}<\\frac{17}{2}\\)<\/p>\n

(ii) \\(\\frac{6}{5}, \\frac{11}{10}, \\frac{19}{5}, \\frac{7}{10}, \\frac{5}{10}\\)
\nAnswer:
\nGiven \\(\\frac{6}{5}, \\frac{11}{10}, \\frac{19}{5}, \\frac{7}{10}, \\frac{5}{10}\\)
\nGiven fractions are not like fractions. So, first we have to convert them into like fractions.
\n\"AP
\nNow arrange them in ascending order according to their numerators.
\n\\(\\frac{5}{10}<\\frac{7}{10}<\\frac{11}{10}<\\frac{12}{10}<\\frac{38}{10}\\)
\nAscending order: \\(\\frac{5}{10}<\\frac{7}{10}<\\frac{11}{10}<\\frac{12}{10}<\\frac{38}{10}\\)<\/p>\n

(iii) \\(\\frac{8}{3}, \\frac{7}{6}, 3 \\frac{1}{4}, \\frac{5}{3}, \\frac{11}{4}\\)
\nAnswer:
\nGiven \\(\\frac{8}{3}, \\frac{7}{6}, 3 \\frac{1}{4}, \\frac{5}{3}, \\frac{11}{4}\\)
\n\\(\\frac{8}{3}, \\frac{7}{6}, \\frac{13}{4}, \\frac{5}{3}, \\frac{11}{4}\\)
\nWe have to find the LCM of denominators to convert them into equal fraction.<\/p>\n

LCM of numerators is 12
\n\"AP
\nNow arrange the like fractions in ascending order according to their numerators.
\n\\(\\frac{14}{12}<\\frac{20}{12}<\\frac{32}{12}<\\frac{33}{12}<\\frac{39}{12}\\)
\nAscending order :
\n\\(\\frac{14}{12}<\\frac{20}{12}<\\frac{32}{12}<\\frac{33}{12}<\\frac{39}{12}\\)<\/p>\n

\"AP<\/p>\n

Question 2.
\nCalculate the following.
\n(i) \\(\\frac{3}{5}+\\frac{7}{4}\\)
\nAnswer:
\nGiven \\(\\frac{3}{5}+\\frac{7}{4}=\\frac{12+35}{20}=\\frac{47}{20}\\)<\/p>\n

(ii) \\(\\frac{5}{6}+\\frac{7}{12}\\)
\nAnswer:
\nGiven \\(\\frac{5}{6}+\\frac{7}{12}\\)
\n= \\(\\frac{5 \\times 2}{6 \\times 2}+\\frac{7}{12}\\)
\n= \\(\\frac{10}{12}+\\frac{7}{12}\\)
\n= \\(\\frac{10+7}{12}=\\frac{17}{12}=1 \\frac{5}{12}\\)<\/p>\n

(iii) 1\\(\\frac{7}{8}-\\frac{1}{5}\\)
\nAnswer:
\nGiven 1\\(\\frac{7}{8}-\\frac{1}{5}\\)
\n\"AP<\/p>\n

(iv) 4\\(\\frac{1}{2}\\) + 3\\(\\frac{1}{3}\\)
\nAnswer:
\nGiven 4\\(\\frac{1}{2}\\) + 3\\(\\frac{1}{3}\\)
\n\"AP<\/p>\n

Question 3.
\nSimplify the following.
\n(i) \\(\\frac{1}{4}\\) of 3
\nAnswer:
\nGiven \\(\\frac{1}{4}\\) of 3
\n= \\(\\frac{1}{4} \\times \\frac{3}{1}=\\frac{3}{4}\\)<\/p>\n

(ii) \\(\\frac{5}{8}\\) of \\(\\frac{2}{3}\\)
\nAnswer:
\nGiven \\(\\frac{5}{8}\\) of \\(\\frac{2}{3}\\)
\n\"\"<\/p>\n

(iii) \\(\\frac{15}{4} \\times 2 \\frac{1}{7}\\)
\nAnswer:
\n\"AP<\/p>\n

(iv) 3\\(\\frac{1}{3}\\) \u00d7 2\\(\\frac{2}{5}\\)
\nAnswer:
\nGiven 3\\(\\frac{1}{3}\\) \u00d7 2\\(\\frac{2}{5}\\)
\n= \\(\\frac{10}{3} \\times \\frac{12}{5}\\)
\n= \\(\\frac{120}{15}=\\frac{8}{1}\\) = 8<\/p>\n

\"AP<\/p>\n

Question 4.
\nCalculate the following.
\n(i) \\(\\frac{3}{4}\\) \u00f7 3
\nAnswer:
\nGiven \\(\\frac{3}{4}\\) \u00f7 3
\n= \\(\\frac{3}{4}\\) \u00f7 \\(\\frac{3}{1}\\)<\/p>\n

We know reciprocial of \\(\\frac{3}{1}\\) is \\(\\frac{1}{3}\\)
\n= \\(\\frac{3}{4} \\times \\frac{1}{3}\\)
\n= \\(\\frac{3}{12}\\) (or) \\(\\frac{1}{4}\\)<\/p>\n

(ii) 8 \u00f7 2\\(\\frac{1}{7}\\)
\nAnswer:
\nGiven 8 \u00f7 2\\(\\frac{1}{7}\\)
\n= 8 \u00f7 2\\(\\frac{15}{7}\\)<\/p>\n

We know reciprocial of \\(\\frac{15}{7}\\) is \\(\\frac{7}{15}\\)
\n= 8 \u00d7 \\(\\frac{7}{15}\\)
\n= \\(\\frac{8 \\times 7}{15}\\)
\n= \\(\\frac{56}{15}\\) (OR) 3\\(\\frac{11}{15}\\)<\/p>\n

(iii) \\(\\frac{12}{7} \\div \\frac{2}{7}\\)
\nAnswer:
\nGiven \\(\\frac{12}{7} \\div \\frac{2}{7}\\)
\nWe know reciprocial of \\(\\frac{12}{7} \\div \\frac{2}{7}\\)
\n= \\(\\frac{12}{7} \\times \\frac{7}{2}\\)
\n= \\(\\frac{12 \\times 7}{7 \\times 2}=\\frac{84}{14}=\\frac{6}{1}\\) = 6<\/p>\n

(iv) 5\\(\\frac{1}{2}\\) \u00f7 2\\(\\frac{9}{11}\\)
\nAnswer:
\nGiven 5\\(\\frac{1}{2}\\) \u00f7 2\\(\\frac{9}{11}\\)
\n= \\(\\frac{11}{2} \\div \\frac{31}{11}\\)<\/p>\n

We know reciprocial of \\(\\frac{31}{11}\\) is \\(\\frac{11}{31}\\)
\n= \\(\\frac{11}{2} \\times \\frac{11}{31}\\)
\n= \\(\\frac{121}{62}\\) (OR) 1\\(\\frac{59}{62}\\)<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 2 Fractions, Decimals and Rational Numbers Review Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Review Exercise Question 1. Write the following fractions in ascending order. (i) Answer: Given Given fractions are like fractions. So, we should arrange … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":37503,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"https:\/\/apboardsolutions.com\/wp-content\/uploads\/2022\/01\/Chapter-2-Fractions-Decimals-and-Rational-Numbers-Review-Exercise.png","_links":{"self":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16891"}],"collection":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/comments?post=16891"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16891\/revisions"}],"predecessor-version":[{"id":16892,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/16891\/revisions\/16892"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media\/37503"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media?parent=16891"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/categories?post=16891"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/tags?post=16891"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}