{"id":11674,"date":"2024-02-04T10:40:50","date_gmt":"2024-02-04T05:10:50","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=11674"},"modified":"2024-02-05T09:10:01","modified_gmt":"2024-02-05T03:40:01","slug":"ap-board-6th-class-maths-solutions-chapter-10-ex-10-3","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-board-6th-class-maths-solutions-chapter-10-ex-10-3\/","title":{"rendered":"AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3"},"content":{"rendered":"

AP State Syllabus AP Board 6th Class Maths Solutions<\/a> Chapter 10 Practical Geometry Ex 10.3 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 6th Class Maths Solutions 10th Lesson Practical Geometry Ex 10.3<\/h2>\n

\"AP<\/p>\n

Question 1.
\nConstruct the following angles with the help of a protractor.
\ni) \u2220ABC = 65\u00b0
\nii) \u2220PQR = 136\u00b0
\niii) \u2220Y = 45\u00b0
\niv) \u2220O = 172\u00b0
\nSolution:
\ni) \u2220ABC = 65\u00b0
\n\"AP
\nSteps of construction :<\/p>\n

    \n
  1. Draw a ray \\(\\overrightarrow{\\mathrm{BC}}\\) of any length.<\/li>\n
  2. Place the centre point of the protractor at B and the line be aligned with \\(\\overrightarrow{\\mathrm{BC}}\\).<\/li>\n
  3. Mark a point A at 65\u00b0.<\/li>\n
  4. Join BA. \u2220ABC = 65\u00b0 is formed.
    \nHence the required angle \u2220ABC = 65\u00b0 is constructed.<\/li>\n<\/ol>\n

    ii) \u2220PQR = 136\u00b0
    \nSteps of construction :<\/p>\n

      \n
    1. Draw a ray \\(\\overrightarrow{\\mathrm{QR}}\\) of any length,<\/li>\n
    2. Place the centre point of the protractor at Q and the line be aligned with \\(\\overrightarrow{\\mathrm{QR}}\\).<\/li>\n
    3. Mark a point P at 136\u00b0. ‘<\/li>\n
    4. Join PQ. \u2220PQR = 136\u00b0 is formed.
      \nHence the required angle \u2220PQR = 136\u00b0 is constructed.<\/li>\n<\/ol>\n

      \"AP<\/p>\n

      \"AP<\/p>\n

      iii) \u2220Y = 45\u00b0
      \nSteps of construction:<\/p>\n

        \n
      1. Draw a ray \\(\\overrightarrow{\\mathrm{YZ}}\\) of any length.<\/li>\n
      2. Place the centre point of the protractor at Y
        \nand the line be aligned with \\(\\overrightarrow{\\mathrm{YZ}}\\).<\/li>\n
      3. Mark a point X at 45\u00b0.<\/li>\n
      4. Join YX. \u2220XYZ = 45\u00b0 is formed.
        \nHence the required angle \u2220XYZ = 45\u00b0 is constructed.<\/li>\n<\/ol>\n

        \"AP<\/p>\n

        iv) \u2220O = 172\u00b0
        \n\"AP
        \nSteps of construction:<\/p>\n

          \n
        1. Draw a ray \\(\\overrightarrow{\\mathrm{OT}}\\) \u00b0f any length.<\/li>\n
        2. Place the centre point of the protractor at O and the line be aligned with \\(\\overrightarrow{\\mathrm{OT}}\\)<\/li>\n
        3. Mark a point D at 172\u00b0.<\/li>\n
        4. Join OD. \u2220DOT = 172\u00b0 is formed.
          \nHence the required angle \u2220DOT = 172\u00b0 is constructed.<\/li>\n<\/ol>\n

          Question 2.
          \nCopy the following angles in your note book and find their bisectors:
          \n\"AP
          \nSolution:
          \n\"AP<\/p>\n","protected":false},"excerpt":{"rendered":"

          AP State Syllabus AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 Textbook Questions and Answers. AP State Syllabus 6th Class Maths Solutions 10th Lesson Practical Geometry Ex 10.3 Question 1. Construct the following angles with the help of a protractor. i) \u2220ABC = 65\u00b0 ii) \u2220PQR = 136\u00b0 iii) \u2220Y = … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":38638,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[10],"tags":[],"jetpack_featured_media_url":"https:\/\/apboardsolutions.com\/wp-content\/uploads\/2021\/04\/Chapter-10-Practical-Geometry-Ex-10.3.png","_links":{"self":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/11674"}],"collection":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/comments?post=11674"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/11674\/revisions"}],"predecessor-version":[{"id":38639,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/11674\/revisions\/38639"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media\/38638"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media?parent=11674"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/categories?post=11674"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/tags?post=11674"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}