{"id":10216,"date":"2023-12-28T14:53:48","date_gmt":"2023-12-28T09:23:48","guid":{"rendered":"https:\/\/apboardsolutions.com\/?p=10216"},"modified":"2023-12-29T09:29:54","modified_gmt":"2023-12-29T03:59:54","slug":"ap-board-7th-class-maths-solutions-chapter-10-ex-3","status":"publish","type":"post","link":"https:\/\/apboardsolutions.com\/ap-board-7th-class-maths-solutions-chapter-10-ex-3\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 10 Algebraic Expressions Ex 3"},"content":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions<\/a> Chapter 10 Algebraic Expressions Ex 3 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 10th Lesson Algebraic Expressions Exercise 3<\/h2>\n

\"AP<\/p>\n

Question 1.
\nFind the length of the line segment PR in the following figure in terms of \u2019a\u2019.
\n\"AP
\nSolution:
\nThe length of PR = \\(\\overline{\\mathrm{PQ}}+\\overline{\\mathrm{QR}}\\)
\n= 3a + 2a
\n= 5a units<\/p>\n

Question 2.
\n(i) Find the perimeter of the following triangle.
\n\"AP
\n(ii) Find the perimeter of the following rectangle.
\n\"AP
\nSolution:
\ni) The perimeter of the triangle = \\(\\overline{\\mathrm{AB}}+\\overline{\\mathrm{BC}}+\\overline{\\mathrm{CA}}\\)
\n= 2x + 6x + 5x
\n= 13x units
\nii) The perimeter of the rectangle ABCD = \\(\\overline{\\mathrm{AB}}+\\overline{\\mathrm{BC}}+\\overline{\\mathrm{CD}}+\\overline{\\mathrm{DA}}\\)
\nor
\n= 2 (l + b)
\n= 2 (3x + 2x)
\n= 2 \u00d7 5x
\n= 10x units<\/p>\n

\"AP<\/p>\n

Question 3.
\nSubtract the second terni from first term.
\n(i) 8x, 5x
\n(ii) 5p, 11p
\n(iii) 13m2<\/sup>, 2m2<\/sup>
\nSolution:
\ni) 8x – 5x = 3x
\nii) 5p – 11p = -6p
\niii) 13m2<\/sup> – 2m2<\/sup> = 11m2<\/sup><\/p>\n

Question 4.
\nFind the value of following monomials, if x =1.
\n(i) -x
\n(ii) 4x
\n(iii) -2x2<\/sup>
\nSolution:
\n1) If x = 1 \u21d2 – x = – (1)= – 1
\nii) If x = 1 \u21d2 4x = 4 x 1 = 4
\niii) If x= 1 \u21d2 – 2x2<\/sup> = – 2(1)2<\/sup> = – 2 \u00d7 1= – 2<\/p>\n

Question 5.
\nSimplify and find the value of 4x + x – 2x2<\/sup> + x – 1 when x = -1.
\nSolution:
\nGiven expression = 4x + x – 2x2<\/sup> + x – 1
\n= 4x + x + x – 2x2<\/sup> – 1
\n= – 2x2<\/sup> + 6x – 1
\nIf x = – 1 then, the value of – 2x2<\/sup> + 6x – 1 = – 2 (-1)2 + 6( – 1) – 1
\n= – 2(1) – 6 – 1
\n= – 2 – 6 – 1
\n= – 9<\/p>\n

\"AP<\/p>\n

Question 6.
\nWrite the expression 5x2<\/sup> – 4 – 3x2<\/sup> + 6x + 8 + 5x – 13 in its simplified form. Find its value when x = -2
\nSolution:
\nThe given algebraic expression = 5x2<\/sup> – 4 – 3x2<\/sup> + 6x + 8 + 5x – 13.
\n= (5x2<\/sup> – 3x2<\/sup>) (6x + 5x) + (-4 – 13)
\n= 2x2<\/sup> + 11x – 17
\nWhen x = – 2. then the value of 2x2<\/sup>+ 11x – 17 = 2(- 2)2<\/sup> + 11(-2) – 17
\n= 2 \u00d7 4 – 22 – 17
\n= 8 – 39
\n= – 31<\/p>\n

Question 7.
\nIf x = 1; y = 2 find the values of the following expressions
\n(i) 4x – 3y + 5
\n(ii) x2<\/sup> + y2<\/sup>
\n(iii) xy + 3y – 9
\nSolution:
\ni) 4x – 3y+5
\nIf x = 1, y = 2 then the value of 4x – 3y + 5 = 4(1) – 3(2) + 5
\n= 4 – 6 + 5
\n= 9 – 6 = 3<\/p>\n

ii) x2<\/sup> + y2<\/sup>
\nIf x = 1, y = 2, the value of x2<\/sup> + y2<\/sup>= (1)2<\/sup> + (2)2<\/sup>
\n=(1 \u00d7 1) + (2 \u00d7 2)
\n= 5<\/p>\n

iii) xy + 3y – 9
\nIf x = 1; y = 2,the value of xy + 3y – 9 = 1 \u00d7 2 + 3(2) – 9
\n= 2 + 6 – 9
\n= 8 – 9<\/p>\n

\"AP<\/p>\n

Question 8.
\nArea of a rectangle is given by A = l \u00d7 b . If l = 9cm, b = 6cm, find its area?
\nSolution:
\nFormula for area of a rectangle (A) = l \u00d7 b
\nIf l = 9cm, b = 6cm
\nthen the area of the rectangle = l \u00d7 b
\n= 9 \u00d7 6
\n= 54 cm2<\/sup><\/p>\n

Question 9.
\nSimple interest is given by I = \\(\\frac{P T R}{100}\\) . If P = \u20b9 900, T =2 years; and R =5%, find the simple interest.
\nSolution:
\nGiven that the formula for simple interest (I) = \\(\\frac{P T R}{100}\\)
\nP = Rs.900, T = 2years, R = 5%
\n\u2234 The required simple interest (I) = \\(\\frac{\\mathrm{PTR}}{100}=\\frac{900 \\times 2 \\times 5}{100}\\) = 9 x 2 x 5 = Rs. 90<\/p>\n

\"AP<\/p>\n

Question 10.
\nThe relationship between speed (s), distance (d) and time (t) is given by S = – . Find the
\nvalue of s, if d = 135 meters and t = 10 seconds.
\nSolution:
\nGiven that s = \\(\\frac{\\mathrm{d}}{\\mathrm{t}}\\) and d = 135 meters, t = 10 seconds
\n\u2234 The value of s = \\(\\frac{\\mathrm{d}}{\\mathrm{t}}=\\frac{135}{10}\\)
\n\u2234 speed (s) = 13.5 m\/sec.<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions Chapter 10 Algebraic Expressions Ex 3 Textbook Questions and Answers. AP State Syllabus 7th Class Maths Solutions 10th Lesson Algebraic Expressions Exercise 3 Question 1. Find the length of the line segment PR in the following figure in terms of \u2019a\u2019. Solution: The length of PR … Read more<\/a><\/p>\n","protected":false},"author":4,"featured_media":37846,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"https:\/\/apboardsolutions.com\/wp-content\/uploads\/2021\/04\/Chapter-10-Algebraic-Expressions-Ex-3.png","_links":{"self":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/10216"}],"collection":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/comments?post=10216"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/10216\/revisions"}],"predecessor-version":[{"id":37847,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/posts\/10216\/revisions\/37847"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media\/37846"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/media?parent=10216"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/categories?post=10216"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.com\/wp-json\/wp\/v2\/tags?post=10216"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}