Well-designed AP Board Solutions Class 6 Maths Chapter 7 Fractions InText Questions offers step-by-step explanations to help students understand problem-solving strategies.
AP 7th Class Maths 7th Chapter Fractions InText Questions
Try these (Page No: 10)
Question 1.
Show \(\frac { 3 }{ 5 }\) on a number line.
Solution:
Question 2.
Show \(\frac { 1 }{ 10 }\), \(\frac { 0 }{ 10 }\), \(\frac { 5 }{ 10 }\) and \(\frac { 10 }{ 10 }\) on a number line.
Solution:
Question 3.
Can you show any other fraction between 0 and 1 ?
Write five more fractions that you can show and depict them on the number line.
Solution:
Yes, we can show any number of factons between 0 and 1.
Five more fractions between 0 and 1 that can be shown on number line are \(\frac { 1 }{ 8 }\), \(\frac { 2 }{ 8 }\), \(\frac { 5 }{ 8 }\), \(\frac { 6 }{ 8 }\), \(\frac { 7 }{ 8 }\)
Question 4.
How many fractions lie between 0 and 1 ? Think, discuss and write your answer.
Solution:
An infinite number of fractions can be found between 0 and 1.
Try these (Page No: 12)
Question 1.
Give a proper fraction :
a) whose numerator is 5 and denominator is 7 .
b) whose denominator is 9 and numerator is 5 .
c) whose numerator and denominator add up to 10 . How many fractions of this kind can you make ?
d) whose denominator is 4 more than the numerator.
(Give any five. How many more can you make?)
Solution:
a) \(\frac { 5 }{ 7 }\)
b) \(\frac { 5 }{ 9 }\)
c) The fractions whose numerator and denominator add unto 10 are
\(\frac { 0 }{ 10 }\), \(\frac { 1 }{ 9 }\), \(\frac { 2 }{ 8 }\), \(\frac { 3 }{ 7 }\), \(\frac { 4 }{ 6 }\)
We can make 5 fractions.
d) Five fractions whose denominator is 4 more than the numerator are.
\(\frac { 1 }{ 5 }\), \(\frac { 2 }{ 6 }\), \(\frac { 5 }{ 9 }\), \(\frac { 7 }{ 11 }\), \(\frac { 10 }{ 14 }\), …………..
We can find an infinite number of fractions whose denominator is 4 more than the numerator.
Question 2.
A fraction is given.
How will you decide, by just looking at it, whether, the fraction is
a) less than 1 ?
b) equal to 1 ?
Solution:
a) If the numerator is less than the de-nominator, then the fraction histes than 1.
For example: \(\frac { 2 }{ 5 }\), \(\frac { 3 }{ 6 }\), \(\frac { 1 }{ 2 }\), \(\frac { 10 }{ 25 }\), etc.
b) If the numerator is equal to the denominator, then the fraction is equal to 1 :
For example: \(\frac { 2 }{ 2 }\), \(\frac { 3 }{ 3 }\), \(\frac { 1 }{ 1 }\), \(\frac { 10 }{ 10 }\), etc.
Question 3.
Fill up using one of these: ‘>’,'<‘ or ‘=’
a) \(\frac { 1 }{ 2 }\) _____ 1
b) \(\frac { 3 }{ 5 }\) _____ 1
c) 1 _____ \(\frac { 7 }{ 8 }\)
d) \(\frac { 4 }{ 4 }\) _____ 1
e) \(\frac { 1 }{ 2 }\) _____ 1
Solution:
a) \(\frac { 1 }{ 2 }\) < 1
b) \(\frac { 3 }{ 5 }\) < 1
c) 1 > \(\frac { 7 }{ 8 }\)
d) \(\frac { 4 }{ 4 }\) = 1
e) \(\frac { 1 }{ 2 }\) = 1
Try these (Page No: 20)
Question 1.
Are \(\frac { 1 }{ 3 }\) and \(\frac { 2 }{ 7 }\); \(\frac { 2 }{ 5 }\) and \(\frac { 2 }{ 7 }\); \(\frac { 2 }{ 9 }\) and \(\frac { 6 }{ 27 }\) equivalent? Give reason.
Solution:
\(\frac { 1 }{ 3 }\) and \(\frac { 2 }{ 7 }\) are not equivalent fractions.
∴ \(\frac{1 \times 2}{3 \times 2}\) = \(\frac { 2 }{ 6 }\) ≠ \(\frac { 2 }{ 7 }\)
\(\frac { 2 }{ 5 }\) and \(\frac { 2 }{ 7 }\) are also not equivalent fractions.
∴ \(\frac{2 \times 1}{5 \times 1}\) = \(\frac { 2 }{ 5 }\) ≠ \(\frac { 2 }{ 7 }\)
\(\frac { 2 }{ 9 }\) and \(\frac { 6 }{ 27 }\) are equivalent fractions.
∴ \(\frac{2 \times 3}{9 \times 3}\) = \(\frac { 6 }{ 27 }\)
Question 2.
Give example of four equivalent fractions.
Solution:
Four examples for equivalent fractions:
i) \(\frac { 1 }{ 2 }\) and \(\frac { 2 }{ 4 }\)
ii) \(\frac { 2 }{ 3 }\) and \(\frac { 6 }{ 9 }\)
iii) \(\frac { 4 }{ 5 }\) and \(\frac { 8 }{ 10 }\)
iv) \(\frac { 4 }{ 6 }\) and \(\frac { 2 }{ 3 }\)
Question 3.
Identify the fractions in each. Are these fractions equivalent?
Solution:
a) \(\frac { 6 }{ 8 }\) (or) \(\frac { 3 }{ 4 }\)
b) \(\frac { 9 }{ 12 }\) (or) \(\frac { 3 }{ 4 }\)
c) \(\frac { 12 }{ 16 }\) (or) \(\frac { 3 }{ 4 }\)
d) \(\frac { 15 }{ 20 }\) (or) \(\frac { 3 }{ 4 }\)
Yes, they are equivalent fractions.
Try these (Page No: 22)
Question 1.
Find five equivalent fractions of each of the following :
i) \(\frac { 2 }{ 3 }\)
ii) \(\frac {1 }{ 5 }\)
iii) \(\frac { 3 }{ 5 }\)
iv) \(\frac { 5 }{ 9 }\)
Solution:
i) \(\frac { 2 }{ 3 }\) = \(\frac{2 \times 2}{3 \times 2}\) = \(\frac { 4 }{ 6 }\); \(\frac { 2 }{ 3 }\) = \(\frac{2 \times 3}{3 \times 3}\) = \(\frac { 6 }{ 9 }\)
\(\frac { 2 }{ 3 }\) = \(\frac{2 \times 4}{3 \times 4}\) = \(\frac { 8 }{ 12 }\); \(\frac { 2 }{ 3 }\) = \(\frac{2 \times 5}{3 \times 5}\) = \(\frac { 10 }{ 15 }\)
\(\frac { 2 }{ 3 }\) = \(\frac{2 \times 6}{3 \times 6}\) = \(\frac { 12 }{ 18 }\)
So, \(\frac { 2 }{ 3 }\), \(\frac { 4 }{ 6 }\), \(\frac { 6 }{ 9 }\), \(\frac { 8 }{ 12 }\), \(\frac { 10 }{ 15 }\) and \(\frac { 12 }{ 18 }\) are equivalent fractions.
ii) \(\frac { 1 }{ 5 }\) = \(\frac{1 \times 2}{5 \times 2}\) = \(\frac { 2 }{ 10 }\); \(\frac { 1 }{ 5 }\) = \(\frac{1 \times 3}{5 \times 3}\) = \(\frac { 3 }{ 15 }\)
\(\frac { 1 }{ 5 }\) = \(\frac{1 \times 4}{5 \times 4}\) = \(\frac { 4 }{ 20 }\); \(\frac { 1 }{ 5 }\) = \(\frac{1 \times 5}{5 \times 5}\) = \(\frac { 5 }{ 25 }\)
\(\frac { 1 }{ 5 }\) = \(\frac{1 \times 6}{5 \times 6}\) = \(\frac { 6 }{ 30 }\)
So, \(\frac { 1 }{ 5 }\), \(\frac { 2 }{ 10 }\), \(\frac { 3 }{ 15 }\), \(\frac { 4 }{ 20 }\), \(\frac { 5 }{ 25 }\) and \(\frac { 6 }{ 30 }\), are equivalent fractions.
iii) \(\frac { 3 }{ 5 }\) = \(\frac{3 \times 2}{5 \times 2}\) = \(\frac { 6 }{ 10 }\); \(\frac { 3 }{ 5 }\) = \(\frac{3 \times 3}{5 \times 3}\) = \(\frac { 9 }{ 15 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 4}{5 \times 4}\) = \(\frac { 12 }{ 20 }\); \(\frac { 3 }{ 5 }\) = \(\frac{3 \times 5}{5 \times 5}\) = \(\frac { 15 }{ 25 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 6}{5 \times 6}\) = \(\frac { 18 }{ 30 }\);
So, \(\frac { 3 }{ 5 }\), \(\frac { 6 }{ 10 }\), \(\frac { 9 }{ 15 }\), \(\frac { 12 }{ 20 }\), \(\frac { 15 }{ 25 }\) and \(\frac { 18 }{ 30 }\), are equivalent fractions.
iv) \(\frac { 5 }{ 9 }\) = \(\frac{5 \times 2}{9 \times 2}\) = \(\frac { 10 }{ 18 }\); \(\frac { 5 }{ 9 }\) = \(\frac{5 \times 3}{9 \times 3}\) = \(\frac { 15 }{ 27 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 4}{9 \times 4}\) = \(\frac { 20 }{ 36 }\); \(\frac { 5 }{ 9 }\) = \(\frac{5 \times 5}{9 \times 5}\) = \(\frac { 25 }{ 45 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 10}{9 \times 10}\) = \(\frac { 50 }{ 90 }\);
So, \(\frac { 5 }{ 9 }\), \(\frac { 10 }{ 18 }\), \(\frac { 15 }{ 27 }\), \(\frac { 20 }{ 36 }\), \(\frac { 25 }{ 45 }\) and \(\frac { 50 }{ 90 }\), are equivalent fractions.
Try these (Page No: 28)
Question 1.
Write the simplest form of:
i) \(\frac { 15 }{ 75 }\)
ii) \(\frac { 16 }{ 72 }\)
iii) \(\frac { 17 }{ 51 }\)
iv) \(\frac { 42 }{ 28 }\)
v) \(\frac { 80 }{ 24 }\)
Solution:
\(\frac { 15 }{ 75 }\) = \(\frac{15 \div 15}{75 \div 15}=\frac{1}{5}\) = \(\frac { 1 }{ 5 }\) [HCF of 15 and 75 is 15]
∴ The simplest form of \(\frac { 15 }{ 75 }\) = \(\frac { 1 }{ 5 }\)
ii) \(\frac { 16 }{ 72 }\) = \(\frac{16 \div 8}{72 \div 8}=\frac{2}{9}\) [HCF of 16 and 72 is 8]
∴ The simplest form of \(\frac { 16 }{ 72 }\) = \(\frac { 2 }{ 9 }\)
iii) \(\frac { 3 }{ 5 }\) = \(\frac{3 \times 2}{5 \times 2}\) = \(\frac { 6 }{ 10 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 3}{5 \times 3}\) = \(\frac { 9 }{ 15 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 4}{5 \times 4}\) = \(\frac { 12 }{ 20 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 5}{5 \times 5}\) = \(\frac { 15 }{ 25 }\)
\(\frac { 3 }{ 5 }\) = \(\frac{3 \times 6}{5 \times 6}\) = \(\frac { 18 }{ 30 }\)
So, \(\frac { 3 }{ 5 }\), \(\frac { 6 }{ 10 }\), \(\frac { 9 }{ 15 }\), \(\frac { 12 }{ 20}\), \(\frac { 15 }{ 25 }\) and \(\frac { 18 }{ 30 }\) are equivalent fractions.
iv) \(\frac { 5 }{ 9 }\) = \(\frac{5 \times 2}{9 \times 2}\) = \(\frac { 10 }{ 18 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 3}{9 \times 3}\) = \(\frac { 15 }{ 27 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 4}{9 \times 4}\) = \(\frac { 20 }{ 36 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 5}{9 \times 5}\) = \(\frac { 25 }{ 45 }\)
\(\frac { 5 }{ 9 }\) = \(\frac{5 \times 10}{9 \times 10}\) = \(\frac { 50 }{ 90 }\)
So, \(\frac { 5 }{ 9 }\), \(\frac { 10 }{ 18 }\), \(\frac { 15 }{ 27 }\), \(\frac { 20 }{ 36}\), \(\frac { 25 }{ 45 }\) and \(\frac { 50 }{ 90 }\) are equivalent fractions.
Try these (Page No: 28)
Question 1.
Write the simplest form of :
i) \(\frac {15 }{ 75 }\)
ii) \(\frac { 16 }{ 72 }\)
iii) \(\frac { 17 }{ 51 }\)
iv) \(\frac { 42 }{ 28 }\)
v) \(\frac { 80 }{ 24 }\)
Solution:
i) \(\frac {15 }{ 75 }\) = \(\frac{15 \div 15}{75 \div 15}\) = \(\frac {1 }{ 5 }\) [HCF of 15 and 75 is 15 ]
∴ The simplest form of \(\frac {15 }{ 75 }\) = \(\frac {1 }{5 }\)
ii) \(\frac {16 }{ 72 }\) = \(\frac{16 \div 8}{72 \div 8}\) = \(\frac {2 }{ 9 }\) [HCF of 16 and 72 is 8 ]
∴ The simplest form of \(\frac {16 }{ 72 }\) = \(\frac {2 }{ 9 }\)
iii) \(\frac {17 }{ 51 }\) = \(\frac{17 \div 17}{51 \div 17}\) = \(\frac {1 }{ 3 }\) [HCF of 17 and 51 is 17 ]
∴ The simplest form of \(\frac {17 }{ 51 }\) = \(\frac {1 }{3 }\)
vi) \(\frac {42 }{ 28 }\) = \(\frac{42 \div 14}{28 \div 14}\) = \(\frac { 3 }{ 2 }\) [HCF of 42 and 28 is 14 ]
∴ The simplest form of \(\frac { 42 }{ 28 }\) = \(\frac { 3 }{ 2 }\)
v) \(\frac { 80 }{ 24 }\) = \(\frac{80 \div 8}{24 \div 8}\) = \(\frac { 10 }{ 3 }\) [HCF of 80 and 24 is 8 ]
∴ The simplest form of \(\frac { 80 }{ 24 }\) = \(\frac { 10 }{ 3 }\)
Question 2.
Is \(\frac { 49 }{ 64 }\) in its simplest form?
Solution:
Yes, it is in simplest form.
Because, HCF of 49 and 64 is 1.
Try these (Page No : 32)
Question 1.
You get one-fifth of a bottle of juice and your sister gets one-third of the same size of a bottle of juice. Who gets more?
Solution:
Let us divide a rectangle into five equal parts and shade of them.
A person gets one-fifth \(\left(\frac{1}{5}\right)\) of a bottle juice.
For his sister divide the same rectangle into three equal parts and shade one of them.
We get one-third \(\left(\frac{1}{3}\right)\) part of the bottle of juice.
So, by comparing the two rectangles, his sister gets more.
Try these (Page No: 34)
Question 1.
Which is the larger fraction?
i) \(\frac { 7 }{ 10 }\) or \(\frac { 8 }{ 10 }\)
ii) \(\frac { 11 }{ 24 }\) or \(\frac { 13 }{ 24 }\)
iii) \(\frac { 17 }{ 102 }\) or \(\frac { 12 }{ 102 }\)
Why are these comparisons easy to make?
Solution:
i) \(\frac { 7 }{ 10 }\) or \(\frac { 8 }{ 10 }\)
Here, denominators of two fractions are same and 7 < 8.
∴ \(\frac { 8 }{ 10 }\) is larger than \(\frac { 7 }{ 10 }\).
ii) \(\frac { 11}{ 24 }\) or \(\frac { 13 }{ 24 }\)
Here, denominators of two fractions are same and 11 < 13 . ∴ \(\frac { 13 }{ 24 }\) is larger than \(\frac { 11}{ 24 }\). iii) \(\frac { 17}{ 102 }\) or \(\frac { 12}{ 102 }\) Here, denominators of two fractions are same and 17 > 12.
∴ \(\frac { 17}{ 102 }\) is larger than \(\frac { 12}{ 102 }\).
These comparisons are easy to make as the denominators of each pair of fraction is same.
Question 2.
Write these in ascending and also in descending order.
a) \(\frac { 1}{ 8 }\), \(\frac { 5 }{ 8 }\), \(\frac { 3 }{ 8 }\)
Solution:
Given that, \(\frac { 1}{ 8 }\), \(\frac { 5 }{ 8 }\), \(\frac { 3 }{ 8 }\)
Here, the denominator of each fraction is same and 1,3,5 are in ascending order.
∴ \(\frac { 1}{ 8 }\), \(\frac { 3 }{ 8 }\), \(\frac { 5 }{ 8 }\) are in ascending order.
\(\frac { 5}{ 8 }\), \(\frac { 3 }{ 8 }\), \(\frac { 1 }{ 8 }\) are in descending order.
b) \(\frac { 1}{ 5 }\), \(\frac { 11 }{ 5 }\), \(\frac { 4 }{ 5 }\), \(\frac { 3}{ 5 }\), \(\frac { 7 }{ 5 }\)
Solution:
Given that, \(\frac { 1}{ 5 }\), \(\frac { 11 }{ 5 }\), \(\frac { 4 }{ 5 }\), \(\frac { 3}{ 5 }\), \(\frac { 7 }{ 5 }\)
Here, the denominator of each fraction is same and 1, 3, 4, 7 and 11 are in ascending order.
∴ \(\frac { 1}{ 5 }\), \(\frac { 3}{ 5 }\), \(\frac { 4}{ 5 }\), \(\frac { 7}{ 5 }\), \(\frac { 11}{ 5 }\)are in ascending order.
\(\frac { 11}{ 5 }\), \(\frac { 7}{ 5 }\), \(\frac { 4}{ 5 }\), \(\frac { 3}{ 5 }\), \(\frac { 1}{ 5 }\) are in descending order.
c) \(\frac { 1}{ 7 }\), \(\frac { 3 }{7 }\), \(\frac { 13 }{ 7 }\), \(\frac { 11}{ 7 }\), \(\frac { 7}{ 7 }\)
Solution:
Given that, \(\frac { 1}{ 7 }\), \(\frac { 3 }{7 }\), \(\frac { 13 }{ 7 }\), \(\frac { 11}{ 7 }\), \(\frac { 7}{ 7 }\)
Here, the denominator of each fraction is same and.1,3, 7, 11 and 13 are in ascending order.
∴ \(\frac { 1}{ 7 }\), \(\frac { 3 }{7 }\), \(\frac { 7 }{ 7 }\), \(\frac { 11}{ 7 }\), \(\frac { 13}{ 7 }\) are in ascending order.
\(\frac { 13 }{ 7 }\), \(\frac { 11 }{7 }\), \(\frac { 7 }{ 7 }\), \(\frac { 3 }{ 7 }\), \(\frac { 1 }{ 7 }\) are in descending
Try these (Page No: 46)
Question 1.
My mother divided an apple into 4 equal parts. She gave me two parts and my brother one part. How much apple did she give to both of us together?
Solution:
Apple was divided into 4 equal parts. 1 got 2 parts.
My fraction = \(\frac { 2 }{ 4 }\).
My brother got 1 part.
My brother’s fraction = \(\frac { 1 }{ 4 }\)
∴ Fraction got by both together
= \(\frac { 2 }{ 4 }\) + \(\frac { 1 }{ 4 }\) = \(\frac { 2 + 1 }{ 4 }\) = \(\frac { 3 }{ 4 }\)
Hence both of got \(\frac { 3 }{ 4 }\)th part of the apple.
Question 2.
Mother asked Neelu and her brother to pick stones from the wheat. Neelu picked one fourth of the total stones in it and her brother also picked up one fourth of the stones. What fraction of the stones did both pick up together?
Solution:
Neelu picked up \(\frac { 1 }{ 4 }\)th the stones.
Her brother picked up \(\frac { 1 }{ 4 }\)th of the stones.
Fraction of stones picked up both
Hence, the stones picked up by both =\(\frac { 1 }{ 2 }\) of the stones.
Question 3.
Sohan was putting covers on his note books. He put one fourth of the covers on Monday. He put another one fourth on Tuesday and the remaining on Wednesday. What fraction of the covers did he put on Wednesday?
Solution:
Sohan put \(\frac { 1 }{ 4 }\)th of the covers on Monday. He put another \(\frac { 1 }{ 4 }\)th of the covers on Tuesday.
He put the remaining covers on Wednesday.
Remaining covers
Try these (Page No: 48)
Question 1.
Add with the help of a diagram.
Question 2.
Add \(\frac { 1 }{ 12 }\) + \(\frac { 1 }{ 12 }\). How will we show this pictorially? using paper folding?
Solution:
\(\frac { 1 }{ 12 }\) + \(\frac { 1 }{ 12 }\) = \(\frac { 2 }{ 12 }\) + \(\frac { 1 }{ 6 }\)
To show \(\frac { 1 }{ 12 }\) + \(\frac { 1 }{ 12 }\) by pictograph, we get
Paper folding is an activity. Students will do it themselves.
Question 3.
Make 5 more examples of problems given in 1 and 2 above. Solve them with your friends.
Solution:
Example (1): Add \(\frac { 1 }{ 5 }\) + \(\frac { 2 }{ 5 }\) with the help of diagram.
Example (2): Add \(\frac { 1 }{ 4 }\) + \(\frac { 1 }{ 4 }\) + \(\frac { 2 }{ 4 }\) with the help of diagram.
Example (3): Add \(\frac { 3 }{ 8 }\) + \(\frac { 1 }{ 8 }\). How will you show this pictorially? Using paper folding?
\(\frac { 3 }{ 8 }\) + \(\frac { 1 }{ 8 }\) = \(\frac { 4 }{ 8 }\)
Paper folding is an activity. Students will do themselves.
Example (4) : Add \(\frac { 1 }{ 3 }\) + \(\frac { 2 }{ 3 }\). How will you show this pictorially? Using paper folding?
Example (5): Add \(\frac { 2 }{ 5 }\) + \(\frac { 3 }{ 5 }\) + \(\frac { 1 }{ 5 }\). How will you show this pictorially? Using paper folding?
Solve the above examples 4 and 5 with your friends.
Try these (Page No: 50)
Question 1.
Find the difference between \(\frac { 7 }{ 8 }\) and \(\frac { 3 }{ 8 }\).
Solution:
\(\frac { 7 }{ 8 }\) – \(\frac { 3 }{ 8 }\) = \(\frac { 7-3 }{ 8 }\) = \(\frac { 4 }{ 8 }\) = \(\frac { 1 }{ 2 }\)
Question 2.
Mother made a gud patti in a round shape. She divided it into 5 parts. Seema ate one piece from it. If I eat another piece, then how much would be left ?
Solution:
Total number of equal parts of gud patti = 5
Number of parts eaten by Seema = 1
∴ Fraction of eaten part = \(\frac { 1 }{ 5 }\)
Number of parts eaten by me = 1
∴ Fraction of eaten part = \(\frac { 1 }{ 5 }\)
∴ Fraction of gud patti eaten by Seema and me = \(\frac { 1 }{ 5 }\) + \(\frac { 1 }{ 5 }\) = \(\frac { 1 + 1}{ 5 }\) = \(\frac { 2 }{ 5 }\)
∴ Fraction of gud patti left = 1 – \(\frac { 2 }{ 5 }\) = \(\frac { 5 – 2 }{ 5 }\) = \(\frac { 3 }{ 5 }\)
Hence, the left fraction = \(\frac { 3 }{ 5 }\)
Question 3.
My elder sister divided the watermelon into 16 parts. Iate 7 out of them. My friend ate 4. How much did we eat between us? How much more of the watermelon did I eat than my friend? What portion of the watermelon remained ?
Solution:
Total number of parts of watermelon = 16
Number of parts eaten by me = 7
∴ Fraction of watermelon eaten by me = \(\frac { 7 }{ 16 }\)
Number of parts eaten by my friend = 4
∴ Fraction of watermelon eaten by my friend = \(\frac { 4 }{ 16 }\)
Fraction of watermelon eaten by me and my friend = \(\frac { 7 }{ 16 }\) + \(\frac { 4 }{ 16 }\) = \(\frac { 7 + 4 }{ 16 }\) = \(\frac { 11 }{ 16 }\)
∴ Fraction of watermelon eaten by both of us = \(\frac { 11 }{ 16 }\)
(Fraction of watermelon eaten by me)
– (Fraction of watermelon eaten by my friend)
= \(\frac { 7 }{ 16 }\) – \(\frac { 4 }{ 16 }\) = \(\frac { 7-4 }{ 16 }\) = \(\frac { 3 }{ 16 }\)
So, I ate \(\frac { 3 }{ 16 }\) part more than my friend.
Portion of watermelon left now
= 1 – \(\frac { 11 }{ 16 }\) = \(\frac { 16-11 }{ 16 }\) = \(\frac { 5 }{ 16 }\)
Hence, the left part of the watermelon = \(\frac { 5 }{ 16 }\)
Question 4.
Make five problems of this type and solve them with your friends.
Solution:
Try yourself with the help of Q.No. 1 and 2 with your friends.
in each of the following by the correct number:
