AP Inter 1st Year Physics Notes Chapter 4 Motion in a Plane

Students can go through AP Inter 1st Year Physics Notes 4th Lesson Motion in a Plane will help students in revising the entire concepts quickly.

AP Inter 1st Year Physics Notes 4th Lesson Motion in a Plane

→ A physical quantity having only magnitude but no direction is called a scalar.

→ A physical quantity having magnitude as well as direction and obeys law of addition of vectors is called a vector.

→ A vector of zero magnitude is called null vector for) zero vector.

→ Vectors situated in the same plane are called coplanar vectors.

→ A vector with magnitude one is called unit vector.

→ A vector ‘a1 can be represented in unit vector form as a = axi + ayj + azk. The magnitude of
$$|\vec{a}|=\sqrt{a_x^2+a_y^2+a_z^2}$$

→ Resultant of any two vectors is determined by parallelogram law of vectors.
R = $$\sqrt{\mathrm{P}^2+\mathrm{Q}^2+2 \mathrm{PQ} \cos \theta}$$, tan α = $$\frac{Q \sin \theta}{P+Q \cos \theta}$$
→ Relative velocity is defined as the velocity of one body w.r. to other body.

→ Relative velocity of A w.r. to B = | VA – VB|

→ Relative velocity of B w.r. to A = | VB – VA|

→ Dot product of two vectors is given by $$\vec{a} \cdot \vec{b}$$ = ab cos θ

→ Cross product of two vectors $$\vec{p}$$ and $$\vec{Q}$$ is given by $$\overrightarrow{\mathrm{P}} \times \overrightarrow{\mathrm{Q}}=\mathrm{PQ} \sin \theta \hat{\mathrm{n}}$$
∴ $$|\vec{P} \times \vec{Q}|=\left|\begin{array}{ccc} i & 1 & k \\ P_x & P_y & P_z \\ Q_x & Q_y & Q_z \end{array}\right|$$

→ Two vectors A and B are said to be equal if and only if, they have the same magnitude and the same direction.

→ The equation of motion for a projectile is given by y = (tan θ0)x – $$\frac{\mathrm{g}}{2\left(\mathrm{v}_0 \cos \theta_0\right)^2}$$ x2 After t seconds (v0) remains the same and final velocity is given by v0 = sin θ – gt

→ The time taken by the projectile to reach the maximum height is given by ta = $$\frac{v_0 \sin \theta}{g}$$
The time of descent is equal to the time of ascent time of flight is given by T = $$\frac{2 v_0 \sin \theta}{g}$$

→ Maximum height reached by the projectile (H) = $$\frac{\left(v_0 \sin \theta_0\right)^2}{2 g}$$

→ For angles of projection (45° + α) and (45° – α) the range is the same for a given initial velocity.

→ Horizontal range is given by R = $$\frac{v_0^2 \sin 2 \theta_0}{g}$$

→ Maximum Range (Rmax) = $$\frac{v_0^2}{g}$$

→ The velocity of the projectile at any instant t is given by v = $$\sqrt{v_x^2+v_y^2}$$ where vx = υ0 cos θ, vy = v0 sin θ – gt

→ The resultant acceleration of an object in circular motion is towards the centre only if the speed is constant.

→ The shape of the trajectory of the motion of an object is not determined by the acceleration alone but also depends on the initial conditions of motion.

→ The position vector of an object in x – y plane is given by