SCERT AP 7th Class Maths Solutions Pdf Chapter 2 Fractions, Decimals and Rational Numbers Unit Exercise Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Unit Exercise

Question 1.

Choose the correct answer,

(i) The set of integers are denoted by [ ]

(A) N

(B) W

(C) Z

(D) Q

Answer:

(C) Z

(ii) Number of decimal places in the product of 48.23 × 0.2 [ ]

(A) 2

(B) 3

(C) 1

(D)5

Answer:

(B) 3

(iii) Number of decimal places to the quotient of 537.1 + 10 [ ]

(A) 1

(B) 2

(C) 4

(D) 3

Answer:

(B) 2

(iv) An integer can be ____________

(A) negative

(B) positive

(C) zero

(D) all the above

Answer:

(D) all the above

Question 2.

Fill in the blanks:

(i) The numbers written in the form of \(\frac{p}{q}\), where p. q are integers and q ≠ 0 are __________ numbers

Answer:

(ii) 0.11 × 0.11 = __________

Answer:

0.11 × 0.11

= \(\frac{11}{100} \times \frac{11}{100}\)

= \(\frac{121}{10000}\) = 0.0121

(iii) Standard form of – \(\frac{15}{6}\) = ______

Answer:

Standard form of – \(\frac{15}{6}\)

(iv) Equivalent fraction to –\(\frac{2}{3}\) = __________

Answer:

Equivalent fraction to –\(\frac{2}{3}\)

Question 3.

Find the product:

(i) 2.1 × 6.3

Answer:

2.1 × 6.3

= \(\frac{21}{10} \times \frac{63}{10}\)

= \(\frac{1323}{100}\) = 13.23

∴ 2.1 × 6.3 = 13.23

(ii) 43.205 × 1.27

Answer:

43.205 × 1.27

= \(\frac{43205}{1000} \times \frac{127}{100}\)

= \(\frac{43205 \times 127}{1000 \times 100}\)

= \(\frac{5487035}{100000}\)

∴ 43.205 × 1.27 = 54.87035

(iii) 7.641 × 3.5

Answer:

7.64 1 × 3.5

= \(\frac{7641}{1000} \times \frac{35}{10}\)

= \(\frac{7641 \times 35}{1000 \times 10}\)

= \(\frac{267435}{10000}\)

∴ 7.641 × 3.5 = 26.7435.

(iv) 5.24 × 0.99

Answer:

5.24 × 0.99

= \(\frac{524}{100} \times \frac{99}{100}\)

= \(\frac{524 \times 99}{100 \times 100}\)

= \(\frac{51876}{10000}\)

∴ 5.24 × 0.99 = 5.1876

Question 4.

Solve the following :

(i) 61.24 ÷ 0.4

Answer:

61.24 ÷ 0.4

∴ 61.24 ÷ 0.4 = 153.1

(ii) 23.45 ÷ 1.5

Answer:

23.45 ÷ 1.5

∴ 23.45 ÷ 1.5 = 15.633….

(iii) 0.312 ÷ – 0.6

Answer:

0.312 ÷ – 0.6

∴ 0.312 ÷ – 0.6 = -0.52

(iv) 32.2 ÷ 2.2

Answer:

32,2 ÷ 2.2

∴ 32.2 ÷ 2.2 = 14.6363….,

Question 5.

Multiply 0.04 by – \(\frac{1}{2}\)

Answer:

Given multiply 0.04 by –\(\frac{1}{2}\)

Question 6.

Find standard form of – \(\frac{15}{35}\)

Answer:

Question 7.

A bus travelled 300 km In 7 \(\frac{1}{2}\)hours with uniform speed. Find how many km, it travelled in 1 hour.

Answer:

Given distance travelled by bus in 7\(\frac{1}{2}\)

hours = 300 km

Distance travelled by bus in 1 hour

= 300 ÷ 7\(\frac{1}{2}\)

Question 8.

Suvarna had 300. She spent \(\frac{1}{3}\) of her money on notebooks and \(\frac{1}{4}\) of the remaining on stationery items. How much money is left with ber?

Answer:

Total money Suvarna had = ₹ 300

Money spent on notebooks

= \(\frac{1}{3}\) of ₹ 300

Remaining amount

= Total money – spent on books

= 300 – 100 = ₹ 200

Money spent on stationery

= \(\frac{1}{4}\) of remaining amount

Money left with Suvarna

= Total money – spent on books – spent on stationery

= 300 – 100 – 50

= 300 – 150

∴ Money left with Suvarna = ₹ 150

Question 9.

One litre of diesel costs ₹ 84.65. What is the cost of 12.5 liters of diesel?

Answer:

Given cost of one litre diesel = ₹ 84.65

Cost of 12.5 liters diesel = 84.65 × 12.5

= \(\frac{8465}{100} \times \frac{125}{10}\)

= \(\frac{1058125}{1000}\) = ₹ 1058.125

∴ Cost of 12.5 litres diesel = ₹ 1058.125

Question 10.

Represent \(\frac{-2}{5}, \frac{-3}{5}, \frac{-1}{5}, \frac{3}{5}\) on same number line.

Answer:

Given fractions are \(\frac{-2}{5}, \frac{-3}{5}, \frac{-1}{5}, \frac{3}{5}\)

Ascending order: \(\frac{-3}{5}, \frac{-2}{5}, \frac{-1}{5}, \frac{3}{5}\)