AP State Syllabus AP Board 7th Class Maths Solutions Chapter 2 Fractions, Decimals and Rational Numbers Ex 5 Textbook Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Exercise 5

Question 1.

Which one is greater?

(i) 0.7 or 0.07

(ii) 7 or 8.5

(iii) 1.47or 1.51

(iv) 6 or 0.66

1 cm = 10 mm

1 m = 100cm

1 km = 1000m

1kg =1000gm

Solution:

i) 0.7 or 0.07 = 0.7 is greater

ii) 7 or 8.5= 8.5 is greater

iii) 1.47 or 1.50 = 1.50 is greater

iv) 6 or 0.66 = 6 is greater

Question 2.

Express the following as rupees using decimals.

(i) 9 paise

(ii) 77 rupees 7 paise

(iii) 235 paise

Solution:

(i) 9 paise = \(\frac { 9 }{ 100 }\) = ₹ 0.09

(ii) 77 rupees 7 paise = 77 rupees \(\frac { 7 }{ 100 }\) rupees = ₹ 77.07

(iii) 235 paise = ₹ \(\frac{235}{100}\) = ₹ 2.35

Question 3.

(i) Express 10 cm in metre and kilometre.

(ii) Express 45 mm in centimeter, meter and kilometer.

Solution:

i) 10cm = \(\frac{10}{100}\) m = 0.1 m

1o cm = \(\frac{10}{100 \times 1000}\) km = 0.0001 km

ii) 45 mm = \(\frac{45}{10}\) cm = 4.5 cm

= \(\frac{4.5}{100}\) m = 0.045 m

= \(\frac{0.045}{1000}\) km = 0.000045 km

Question 4.

Express the following in kilograms.

(i) 190g

(ii) 247g

(iii) 44kg 80gm

Solution:

(i) 190g = \(\frac{190}{1000}\) = 0.190 kg

(ii) 247g = \(\frac{247}{1000}\) kg = 0.247 kg

(iii) 44kg 80gm = 44 kg \(\frac{80}{1000}\) kg = 44.080kg

Question 5.

Write the following decimal numbers in expanded form.

(i) 55.5

(ii) 5.55

(iii) 303.03

(iv) 30.303

(v) 1234.56

Solution:

(i) 55.5 = 10 × 5 + 1 × 5 × \(\frac{1}{10}\) × 5 = 50 + 5 + \(\frac{5}{10}\)

(ii) 5.55 = 1 × 5 + \(\frac{1}{10}\) × 5 + \(\frac{1}{100}\) × 5 = 5 + \(\frac{5}{10}+\frac{5}{100}\)

(iii) 303.03 = 100 × 3 + 1 × 3 + \(\frac{1}{100}\) × 3 = 300 + 3 + \(\frac{3}{100}\)

(iv) 30.303 = 10 × 3 + \(\frac{1}{10}\) x 3 + \(\frac{1}{1000}\) x 3 = 30 + \(\frac{3}{10}+\frac{3}{1000}\)

(v) 1234.56 = 1000 × 1 + 100 × 2 + 10 × 3 + 1 × 4 + \(\frac{1}{10}\) × 5 + \(\frac{1}{100}\) × 6 = 1000 + 200 + 30 + 4 + \(\frac{5}{10}+\frac{6}{100}\)

Question 6.

Write the place value of 3 in the following decimal numbers.

(i) 3.46

(ii) 32.46

(iii) 7.43

(iv) 90.30

(v) 794.037

Solution:

i) 3.46 – place value of 3 in 3.46 is 3 × 1 =-3

ii) 32.46- place value of 3 in 32.46 is 3 × 10 = 30

iii) 7.43- place value of 3 in 7.43 is 3 × \(\frac{1}{100}\) = 0.03

iv) 90.30- place value of 3 in 90.30 is 3 × \(\frac{1}{10}\) = 0.3

v) 794.037 – place value of 3 in 794.037 is 3 × \(\frac{1}{100}\) = 0.03

Question 7.

Aruna and Radha start their journey from two different places. A and E. Aruna chose the path from A to B then to km C, while Radha chose the path from E to D then to C. Find who traveled more and by how much?

Solution:

Distance covered by Aruna = AB + BC

= 9.50+2.40 = 11.90km

Distance covered by Rad ha = ED + DC

= 8.25 + 3.75 = 12 km

Radha travelled more by (12.00 – 11.90) = 0.10 km.

Question 8.

Upendra went to the market to buy vegetables. He brought 2 kg 250 gm tomatoes, 2 kg 500gm potatoes, 750gm lady fingers and 125 gm green chillies. How much weight did Upendra cany back to his house?

Upendra carried back a total weight of 5.625 kg