# AP Board 6th Class Maths Solutions Chapter 4 Integers Ex 4.4

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 4 Integers Ex 4.4 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 4th Lesson Integers Ex 4.4

Question 1.
Find:
i) 40 – (22)
ii) 84 – (98)
iii) (-16) + (-17)
iv) (-20) – (13)
v) (38) – (-6)
vi) (-17) – (-36)
Answer:
i) 40 – (22) = +40 – 22
= +(18 + 22)-22
= 18 +(22-22)
= 18 + 0
∴ 40-(22) = + 18

ii) 84 – (98) = 84 – 98
= + 84 – 84 – 14
= (84 – 84) – 14
= 0 – 14
∴ 84 – (98) = – 14

iii) (-16) + (-17) = -16 – 17 = – 33
∴ (-16) + (-17) = -33

iv) (-20) – (13) = – 20 – 13
= -33
∴ (-20) – (13) = – 33

v) 38 – (-6) = 38 + 6
We know – (-a) = a = + 44
∴ 38 – (-6) = + 44

vi) (-17) – (-36) = -17 + 36
We know – (- a) = a
= -17 + 17 + 19
= (-17+17) + 19
= + 19
∴ (-17) – (-36) = + 19

Question 2.
Fill in the boxes with >, < or = sign:
(i) (-4) + (-5) (-5) – (-4)
(ii) (-16) – (-23) (-6) + (-12)
(iii) 44 – (-10) 47 +(-3)
Answer:
(i) (-4) + (-5) (-5)- (-4)
-4-5  -5 + 4
-9 -1

(ii) (-16) – (-23) (-6) + (-12)
-16 + 23 -6-12  [∵ -(-a) = a]
-16 + 16 + 7 -18
+7 -18

(iii) 44 – (-10) 47 + (-3)
44+10 47-3.
54 44 + 3 – 3
54 44

Question 3.
Fill in the blanks:
i) (-13) + ———– = 0
ii) (-16) + 16 = ———–
iii) (-5) + ———– = -14
iv) ———– + (2 – 16) = – 22
Answer:
i) (-13) + ———– = 0
We know, additive inverse of a is -a (or) – a is a.
Additive inverse of -13 is 13. So, -13 + 13 = 0

ii) (-16) + 16 = ———–
We know, sum of a number and its additive inverse is 0.
i.e., (-a) + a = 0
So, (-16) + (16) = 0

iii) (-5) + ———– = -14
-5 + (-9) = -14

iv) ———– + (2 – 16) = – 22
———– + (-14) = -22
– 8 + (-14) = – 22