AP State Syllabus AP Board 6th Class Maths Solutions Chapter 4 Integers Ex 4.4 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 4th Lesson Integers Ex 4.4

Question 1.

Find:

i) 40 – (22)

ii) 84 – (98)

iii) (-16) + (-17)

iv) (-20) – (13)

v) (38) – (-6)

vi) (-17) – (-36)

Answer:

i) 40 – (22) = +40 – 22

= +(18 + 22)-22

= 18 +(22-22)

= 18 + 0

∴ 40-(22) = + 18

ii) 84 – (98) = 84 – 98

= + 84 – 84 – 14

= (84 – 84) – 14

= 0 – 14

∴ 84 – (98) = – 14

iii) (-16) + (-17) = -16 – 17 = – 33

∴ (-16) + (-17) = -33

iv) (-20) – (13) = – 20 – 13

= -33

∴ (-20) – (13) = – 33

v) 38 – (-6) = 38 + 6

We know – (-a) = a = + 44

∴ 38 – (-6) = + 44

vi) (-17) – (-36) = -17 + 36

We know – (- a) = a

= -17 + 17 + 19

= (-17+17) + 19

= + 19

∴ (-17) – (-36) = + 19

Question 2.

Fill in the boxes with >, < or = sign:

(i) (-4) + (-5) (-5) – (-4)

(ii) (-16) – (-23) (-6) + (-12)

(iii) 44 – (-10) 47 +(-3)

Answer:

(i) (-4) + (-5) (-5)- (-4)

-4-5 -5 + 4

-9 -1

(ii) (-16) – (-23) (-6) + (-12)

-16 + 23 -6-12 [∵ -(-a) = a]

-16 + 16 + 7 -18

+7 -18

(iii) 44 – (-10) 47 + (-3)

44+10 47-3.

54 44 + 3 – 3

54 44

Question 3.

Fill in the blanks:

i) (-13) + ———– = 0

ii) (-16) + 16 = ———–

iii) (-5) + ———– = -14

iv) ———– + (2 – 16) = – 22

Answer:

i) (-13) + ———– = 0

We know, additive inverse of a is -a (or) – a is a.

Additive inverse of -13 is 13. So, -13 + 13 = 0

ii) (-16) + 16 = ———–

We know, sum of a number and its additive inverse is 0.

i.e., (-a) + a = 0

So, (-16) + (16) = 0

iii) (-5) + ———– = -14

-5 + (-9) = -14

iv) ———– + (2 – 16) = – 22

———– + (-14) = -22

– 8 + (-14) = – 22