# AP Board 6th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 11 Perimeter and Area Ex 11.3 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 11th Lesson Perimeter and Area Ex 11.3 Question 1.
Find the area of the rectangle of measurements 15 cm and 8 cm as length and breadth respectively.
Solution:
Given length of the rectangle l = 15 cm
breadth of the rectangle b = 8 cm
Area of the rectangle A = l x b
= 15 x 8 = 120 sq.cm

Question 2.
Find the area of a square whose perimeter is 64 m.
Solution:
Given perimeter of a square = 4 x side = 64 m
Divide with 4 on both sides,
$$\frac{4 \times \operatorname{side}}{4}=\frac{64}{4}$$
side (s) = 16 m
Area of the square = s.s = 16xl6 = 256 sq.m Question 3.
Perimeters of a rectangle and square are equal. If the length of the rectangle is 14 cm and the perimeter of the square is 44 cm, find the area of the rectangle.
Solution:
Given the length of the rectangle l = 14 cm
breadth of the rectangle b = ?
Perimeter of the square = 44 cm
Given perimeter of the rectangle = Perimeter of the square ‘
2(l + b) = 44
2(14 + b) = 44
Divide with 2 on both sides,
$$\frac{2(14+b)}{2}=\frac{44}{2}$$
14 + b = 22
Subtract 14 on both sides,
14 + b – 14 = 22 – 14
Breadth of the rectangle b = 8 cm
Area of the rectangle = l x b = 14 x 8 = 112 sq. cm

Question 4.
Find the perimeters and areas of the following and answer the questions.
A) A rectangle with length and breadth as 16 cm and 8 cm respectively.
B) A rectangle with length and breadth as 14 cm and 10 cm respectively.
C) A square with side 12 cm.
(i) Which of the above perimeters are equal ?
(ii) Are all these areas equal? If not, which one has the bigger area?
Solution:
A) Given length of the rectangle l =16 cm
– Breadth of the rectangle b = 8 cm
Perimeter of the rectangle P = 2(1 + b)
= 2(16 + 8) = 2×24 = 48 cm
Area of the rectangle A = l x b
= 16 x 8 = 128 sq. cm B) Given length of the rectangle l = 14 cm
Breadth of the rectangle b = 10 cm
Perimeter of the rectangle P = 2(l + b)
= 2(14 + 10) = 2 x 24 = 48 cm
Area of the rectangle A = l x b
= 14 x 10 = 140 sq.cm

C) Given side of the square s = 12 cm
Perimeter of the square P = 4 x s = 4 x 12 = 48 cm
Area of the square A = s x s = 12 x 12 = 144 sq. cm
i) Perimeters of rectangle A and rectangle B and square are equal.
ii) No. Areas are not equal and area of the square is greater than the areas of rectangles.