AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3

AP State Syllabus AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 Textbook Questions and Answers.

AP State Syllabus 6th Class Maths Solutions 10th Lesson Practical Geometry Ex 10.3

AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3

Question 1.
Construct the following angles with the help of a protractor.
i) ∠ABC = 65°
ii) ∠PQR = 136°
iii) ∠Y = 45°
iv) ∠O = 172°
Solution:
i) ∠ABC = 65°
AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 1
Steps of construction :

  1. Draw a ray \(\overrightarrow{\mathrm{BC}}\) of any length.
  2. Place the centre point of the protractor at B and the line be aligned with \(\overrightarrow{\mathrm{BC}}\).
  3. Mark a point A at 65°.
  4. Join BA. ∠ABC = 65° is formed.
    Hence the required angle ∠ABC = 65° is constructed.

ii) ∠PQR = 136°
Steps of construction :

  1. Draw a ray \(\overrightarrow{\mathrm{QR}}\) of any length,
  2. Place the centre point of the protractor at Q and the line be aligned with \(\overrightarrow{\mathrm{QR}}\).
  3. Mark a point P at 136°. ‘
  4. Join PQ. ∠PQR = 136° is formed.
    Hence the required angle ∠PQR = 136° is constructed.

AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 2

AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3

iii) ∠Y = 45°
Steps of construction:

  1. Draw a ray \(\overrightarrow{\mathrm{YZ}}\) of any length.
  2. Place the centre point of the protractor at Y
    and the line be aligned with \(\overrightarrow{\mathrm{YZ}}\).
  3. Mark a point X at 45°.
  4. Join YX. ∠XYZ = 45° is formed.
    Hence the required angle ∠XYZ = 45° is constructed.

AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 3

iv) ∠O = 172°
AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 4
Steps of construction:

  1. Draw a ray \(\overrightarrow{\mathrm{OT}}\) °f any length.
  2. Place the centre point of the protractor at O and the line be aligned with \(\overrightarrow{\mathrm{OT}}\)
  3. Mark a point D at 172°.
  4. Join OD. ∠DOT = 172° is formed.
    Hence the required angle ∠DOT = 172° is constructed.

Question 2.
Copy the following angles in your note book and find their bisectors:
AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 5
Solution:
AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 6

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