AP State Syllabus AP Board 6th Class Maths Solutions Chapter 10 Practical Geometry Ex 10.3 Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 10th Lesson Practical Geometry Ex 10.3

Question 1.

Construct the following angles with the help of a protractor.

i) ∠ABC = 65°

ii) ∠PQR = 136°

iii) ∠Y = 45°

iv) ∠O = 172°

Solution:

i) ∠ABC = 65°

Steps of construction :

- Draw a ray \(\overrightarrow{\mathrm{BC}}\) of any length.
- Place the centre point of the protractor at B and the line be aligned with \(\overrightarrow{\mathrm{BC}}\).
- Mark a point A at 65°.
- Join BA. ∠ABC = 65° is formed.

Hence the required angle ∠ABC = 65° is constructed.

ii) ∠PQR = 136°

Steps of construction :

- Draw a ray \(\overrightarrow{\mathrm{QR}}\) of any length,
- Place the centre point of the protractor at Q and the line be aligned with \(\overrightarrow{\mathrm{QR}}\).
- Mark a point P at 136°. ‘
- Join PQ. ∠PQR = 136° is formed.

Hence the required angle ∠PQR = 136° is constructed.

iii) ∠Y = 45°

Steps of construction:

- Draw a ray \(\overrightarrow{\mathrm{YZ}}\) of any length.
- Place the centre point of the protractor at Y

and the line be aligned with \(\overrightarrow{\mathrm{YZ}}\). - Mark a point X at 45°.
- Join YX. ∠XYZ = 45° is formed.

Hence the required angle ∠XYZ = 45° is constructed.

iv) ∠O = 172°

Steps of construction:

- Draw a ray \(\overrightarrow{\mathrm{OT}}\) °f any length.
- Place the centre point of the protractor at O and the line be aligned with \(\overrightarrow{\mathrm{OT}}\)
- Mark a point D at 172°.
- Join OD. ∠DOT = 172° is formed.

Hence the required angle ∠DOT = 172° is constructed.

Question 2.

Copy the following angles in your note book and find their bisectors:

Solution: