Well-designed AP Board Solutions Class 7 Maths Chapter 3 Data Handling InText Questions offers step-by-step explanations to help students understand problem-solving strategies.

## AP 7th Class Maths 3rd Chapter Data Handling InText Questions

Try These (page No. 90)

Question 1.

How would you find the average of your study hours for the whole week ?

Solution:

To find the average of study hours for the whole week, we should record the study hours for the whole week. Then, find the sum of all the observations and divide it by the number of observations, i.e., 7 (in this case), which gives us the required average.

Think discuss and write (Page No. 92)

Question 1.

Consider the data in the above examples and think on the following :

i) Is the mean bigger than each of the observations?

Solution:

Hence, mean the observations can be lesser than each of the observations is a false statement.

ii) Is it smaller than each observation?

Solution:

No, the Arithmetic mean is not smaller than each of the observation.

Try These (Page No. 92)

Question 1.

Find the mean of your sleeping hours during one week.

Solution:

Let the sleeping hours during one week be 8 hours, 8 hours, 7 hours, 7.5 hours, 7.5 hours, 9 hours, and 9 hours.

Sum of the sleeping hours of one week = (8+8+7+7.5+7.5+9+9) hours = 56 hours Number of days = 7

∴ Mean of sleeping hours = \(\left(\frac{56}{7}\right)\) hours = 8 hours

Question 2.

Find atleast 5 numbers between \(\frac{1}{2}\) and \(\frac{1}{3}\).

Solution:

1. 0.6

2. 0.7

3. 0.8

4. 0.9

5. 0.55

Try These (page No. 98)

Question 1.

Find the mode of

i) 2,6,5,3,0,3,4,3,2,4,5,2,4

Solution:

Most repeated values = 2 and 3

Mode = 2 and 3

ii) 2,14,16,12,14,14,16,14,10,14,18,14

Solution:

Most repeated value = 14

Mode = 14

Think discuss and write

Question 1.

Can a set of numbers have more than one mode?

Solution:

A set of numbers can have more than one mode (this is known as bimodal if there are two modes) if there are multiple numbers that occur with equal frequency, and more times than the others in the set.

Try These (page No. 100)

Question 1.

Find the mode of the following data :

12,14,12,16,15,13,14,18,19,12,14,15,16,15,16,16,15,17,13,16,16,15,15,13,15,17,15,14,15,13,15,14

Solution:

Question 2.

Heights (in cm) of 25 children are given below :

168,165,163,160,163,161,162,164,163,162,164,163,160,163,160,165,163,162,163,164,163,160,165,163,162

What is the mode of their heights ? What do we understand by mode here?

Solution:

163 is repeated 9 times, so it is the mode.

Try These (Page No: 102)

Question 1.

Discuss with your friends and give

a) Two situations where mean would be an appropriate representative value to use, and

b) Two situations where mode would be an appropriate representative value to use.

Solution:

Class Room Activity.

Try These (Page No: 104)

Question 1.

Your friend found the median and the mode of a given data. Describe and correct your friends error if any :

35,32,35,42,38,32,34

Median = 42, Mode = 32

Solution:

Given observations 35,32,35,42,38,32,34

Ascending order : 32,32,34,35,35,38,42

Median = 35

Most repeated values = 32 and 35

Median = 32 and 35

Try These (Page No. 112)

Question 1.

The bar graph (Fig.) shows the result of a survey to test water resistant watches made by different companies. Each of these companies claimed that their watches were water resistant. After a test the above results were revealed.

a) Can you work out a fraction of the num-ber of watches that leaked to the number tested for each company?

Solution:

Fraction of the number of watches that leaked to the number tested for company A = \(\frac { 20 }{ 40 }\) = \(\frac { 1 }{ 2 }\) = 0.50

Fraction of the number of watches that leaked to the number tested for company B = \(\frac { 10 }{ 40 }\) = \(\frac { 1 }{ 4 }\) = 0.25

Fraction of the number of watches that leaked to the number tested for company C =\(\frac { 15 }{ 40 }\) = \(\frac { 3 }{ 8 }\) = 0.375

Fraction of the number of watches that leaked to the number tested for company D =\(\frac { 25 }{ 40 }\) = \(\frac { 5 }{ 8 }\) = 0.62

b) Could you tell on this basis which company has better watches?

Solution:

Company B has better watches.

Question 2.

Sale of English and Hindi books in the years 1995, 1996, 1997 and 1998 are given below :

Draw a double bar graph and answer the following questions :

a) In which year was the difference in the sale of the two language books least?

b) Can you say that the demand-for English books rose faster? Justify.

Solution:

a) In 1995 , difference between English & Hindi Books = 500 – 350 = 150

1996, difference between English & Hindi Books = 525 – 400 = 125

1997, difference between English & Hindi Books = 600 – 450 = 150

1998, difference between English & Hindi Books = 650 – 620 = 30

In 1998 the difference in the sale of two language books least.

b) Yes. the demand for sale of English books rose faster.

Between 1997 – 1998 English books selling is 170 more then compared to other years.