AP 6th Class Maths 8th Chapter Decimals InText Questions

Well-designed AP Board Solutions Class 6 Maths Chapter 8 Decimals InText Questions offers step-by-step explanations to help students understand problem-solving strategies.

AP 7th Class Maths 8th Chapter Decimals InText Questions

Try these (Page No : 64)

i) Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.
Solution:
100 paise = ₹ 1
1 paise = ₹\(\frac { 1 }{ 100 }\); 5 paise = ₹\(\frac { 5 }{ 100 }\)
So, 2 rupees 5 paise = ₹ 2 + 5 paise
=₹2 + ₹\(\frac { 5 }{ 100 }\)
=₹ 2 + ₹ 0.05
= ₹ 2.05
50 paise = ₹\(\frac { 50 }{ 100 }\)
So 2 rupees 50 paise = ₹ 2 + 50 paise
= ₹2 + ₹\(\frac { 50 }{ 100 }\)
= ₹ 2.50

ii) Write 20 rupees 7 paise and 21 rupees 75 paise in decimals ?
Solution:
20 rupees 7 paise = ₹ 20 + 7 paise
= ₹ 20 + ₹\(\frac { 7 }{ 100 }\)
= ₹ 20.07
21 rupees 75 paise = ₹ 21 + 75 paise.
₹ 21 + ₹ 0.75 = ₹ 21.75

AP 6th Class Maths 8th Chapter Decimals InText Questions

Try these (Page No: 66)

Question 1.
Cati you write 4 mm in ‘cm’ using decimals ?
Solution:
Yes, we can write 4 mm in ‘cm’ using decimals.
10 mm = 1 cm; 1 mm = \(\frac { 1 }{ 10 }\) cm
∴ 4 mm = \(\frac { 4 }{ 10 }\) cm = 0.4 cm
Hence 4 mm = 0.4 cm.

Question 2.
How will you write 7 cm 5 mm in ‘cm’ using decimals ?
Solution:
We know that 1 cm = 10 mm
Also 1 mm = \(\frac { 1 }{ 10 }\) cm
For converting pm into cm , we have to multiply the given values in mm by \(\frac { 1 }{ 10 }\)
7 cm 5 mm = 7 + 5 × \(\frac { 1 }{ 10 }\) cm
= 7 + \(\frac { 5 }{ 10 }\) cm
= 7 + 0.5 cm = 7.5 cm
∴ 7 cm 5 mm = 7.5 cm

Question 3.
Can you now write 52 m as ‘km’ using decimals? How will you write 340 m as ‘km’ using decimals? How will you write 2008 m in ‘km’ ?
Solution:
1000 m = 1 km
1 m = \(\frac { 1 }{ 1000 }\) km
52 m = \(\frac { 52 }{ 1000 }\) km = 0.052 km.
Hence we can write 52 m as 0.052 km .
340 m = \(\frac { 340 }{ 1000 }\)km = 0.340 km = 0.34 km
2008 m = \(\frac { 2008 }{ 1000 }\)km = 2.008 km.

Try these (Page No: 66)

Question 1.
Can you now write 456 g as ‘kg’ using decimals?
Solution:
Yes, we can write 456 g as kg using decimals.
We know thag 1000 g = 1 kg
1 g = \(\frac { 1 }{ 1000 }\) kg
∴ 456 g = \(\frac { 456 }{ 1000 }\)kg = 0.456 kg

Question 2.
How will you write 2 kg 9g in ‘kg ‘ using decimals ?
Solution:
2 kg + 9 g
= 2kg + 9g
= 2kg + \(\frac { 9 }{ 1000 }\)kg (1g = \(\frac { 1 }{ 1000 }\) kg)
= 2 kg + 0.009 kg
= 2.009 kg
Hence, 2kg 9 g = 2.009 kg.

Try These (Page No: 70)

Question 1.
i) 0.29 + 0.36
Solution:
0.29 + 0.36 = 0.65

ii) 0.7 + 0.08
Solution:
0.7 + 0.08 = 0.78

iii) 1.54 + 1.80
Solution:
1.54 + 1.80 = 3.34

iv) 2.66 + 1.85
Solution:
2.66 + 1.85 = 4.51

AP 6th Class Maths 8th Chapter Decimals InText Questions

Try these (Page No: 74)

Question 1.
Subtract 1.85 from 5.46.
Solution:
5.46 – 1.85 = 3.61

Question 2.
Subtract 5.25 from 8.28.
Solution:
8.28 – 5.25 = 3.03

Question 3.
Subtract 0.95 from 2.29.
Solution:
2.29 – 0.95 = 1.34

Question 4.
Subtract 2.25 from 5.68.
Solution:
5.68 – 2.25 = 3.43

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