Well-designed AP Board Solutions Class 6 Maths Chapter 8 Decimals Exercise 8.4 offers step-by-step explanations to help students understand problem-solving strategies.
Decimals Class 6 Exercise 8.4 Solutions – 6th Class Maths 8.4 Exercise Solutions
Question 1.
Subtract:
a) ₹ 18.25 from ₹ 20.75
Solution:
20.75 – 18.25 = ₹ 2.50
b) 202.54 m from 250 m
Solution:
250.00 – 202.54 = 47.46 m
c) ₹ 5.36 from ₹ 8.40
Solution:
8.40 – 5.36 = ₹ 3.04
d). 2.051 km from 5.206 km
Solution:
5.206 – 2.051 = 3.155 km
e) 0.314 kg from 2.107 kg
Solution:
2.071 – 0.314 = 1.793 kg.
Question 2.
Find the value of:
a) 9.756 – 6.28
Solution:
9.756 – 6.28 = 3.476
b) 21.05 – 15.27
Solution:
21.05 – 15.27 = 5.78
c) 18.5 – 6.79
Solution:
18.5 – 6.79 = 11.71
d) 11.6 – 9.847
Solution:
11.6 – 9.847 = 1,753
Question 3.
Raju bought a book for ₹ 35.65. He gave ₹ 50 to the shopkeeper. How much money did he get back from the shopkeeper?
Solution:
Cost of the book bought by Ravi – ₹ 35.65
Money paid by him to shopkeeper – ₹ 50
∴ Money got back by Ravi = ₹ 50 – ₹ 35.65 = ₹ 14.35
Question 4.
Rani had ₹ 18.50. She bought one icecream for ₹ 11.75. How much money does she have now?
Solution:
Money Rani had = ₹ 18.50
Cost of one ice-cream bought by her = ₹ 11.75
∴ Money left with Rani = ₹ 18.50 – ₹ 11.75 = ₹ 6.75
Question 5.
Tina had 20 m 5 cm long cloth. She cuts 4 m 50 cm length of cloth from this for making a curtain. How much cloth is left with her?
Solution:
Length of cloth had by Tina = 20 m 5 cm 20 m + \(\frac { 5 }{ 100 }\) m = 20 m + 0.05 m = 20.05 m
Length of cloth cut by her = 4 m 50 cm
4 m + \(\frac { 50 }{ 100 }\) m = 4.50 m
∴ Length of cloth left with her = 20.05 m – 4.50 m = 15.55 m
Question 6.
Namita travels 20 km 50 m every day. Out of this she travels 10 km 200 m by bus and the rest by auto. How much distance does she travel by auto?
Solution:
Distance travelled by Namita daily = 20 km 50 m
= 20 km + \(\frac { 50 }{ 1000 }\) km
= 20 km + 0.050 km
[∵ 1000 m = 1 km; 1 m = \(\frac { 1 }{ 1000 }\) km]
= 20.050 km
Distance travelled by her by bus = 10 km 200 m = 10 + \(\frac { 200 }{ 1000 }\) = 10.200 km
Distance travelled by her by auto = 20.050 km – 10.200 km = 9.850 km
Question 7.
Aakash bought vegetables weighing 10 kg. Out of this, 3 kg 500 g is onions, 2 kg 75 g is tomatoes and the rest is potatoes. What is the welght of the potatoes?
Solution:
Weight of vegetables bought by Akash = 10 kg
Weight of onions bought by him = 3 kg 500 g = 3 kg + \(\frac { 500 }{ 1000 }\) kg = 3.500 kg
Weight of tomatoes bought by him = 2 kg 75 g = 2 kg + \(\frac { 75 }{ 1000 }\) kg = 2.075 kg
Total weight of onions and tomatoes = 3.500 + 2.075 = 5.575 kg
Weight of potatoes = weight of vegetables – total weight of onions and tomatoes = 10 – 5.575 = 4.425 kg