Well-designed AP Board Solutions Class 6 Maths Chapter 8 Decimals Exercise 8.3 offers step-by-step explanations to help students understand problem-solving strategies.
Decimals Class 6 Exercise 8.3 Solutions – 6th Class Maths 8.3 Exercise Solutions
Question 1.
Find the sum in each of the following:
a) 0.007 + 8.5 + 30.08
Solution:
0.007 + 8.5 + 30.08 = 38.587
b) 15 + 0.632 + 13.8
Solution:
15 + 0.632 + 13.8 = 29.432
c) 27.076 + 0.55 + 0.004
Solution:
27.076 + 0.55 + 0.004 = 27.630
d) 25.65 + 9.005 + 3.7
Solution:
25.65 + 9.005 + 3.7 = 38.355
e) 0.75 + 10.425 + 2
Solution:
0.75 + 10.425 + 2 = 13.175
f) 280.69 + 25.2 + 38
Solution:
280.69 + 25.2 + 38 = 343.89
Question 2.
Rashid spent ₹ 35.75 for Maths book and ₹ 32.60 for Science book. Find the total amount spent by Rashid.
Solution:
Money spent by Rashid for Maths book = ₹ 35.75
Money spent by Rashid for Science book = ₹ 32.60
∴ Total money spent by Rashid on both Maths and Science books = ₹ 35.75 + ₹ 32.60 = ₹ 68.35
Question 3.
Radhika’s mother gave her ₹ 10.50 and her father gave her ₹ 15.80, find the total amount given to Radhika by the parents.
Solution:
Money given by
Radhika’s mother = ₹ 10.50
Money given by her father =₹ 15.80
∴ Total money given to her parents = ₹ 10.50 + ₹ 15.80 = ₹ 26.30
Question 4.
Nasreen bought 3 m 20 cm cloth for her shirt and 2 m 5 cm cloth for her trouser. Find the total length of cloth bought by her.
Solution:
Length of cloth bought by Nasreen for her sirt = 3 m 20 cm
Length of cloth brought by her for her trouser = 2 m 5 cm
∴ Total length of cloth bought by her = 3.20 m + 2.05 m = 5.25 m
Question 5.
Naresh walked 2 km 35 m in the morning and 1 km 7 m in the the evening, How much distance did he walk in all?
Solution:
Distance walked by Naresh in the morning = 2 km 35 m = \(\left(2+\frac{35}{1000}\right)\) km = 2.035 km
Distance walked by him in the evening = 1 km 7 m = \(\left(1+\frac{7}{1000}\right)\) km = 1.007 km
Total distance walked by Naresh in all = 2.035 km + 1.007 km = 3.042 km
Question 6.
Sunita travelled 15 km 268 m by bus, 7 km 7 m by car and 500 m on foot In order to reach her school. How far is her school from her residence?
Solution:
Distance travelled by Sunitha by bus = 15 km 268 m = \(\left(15+\frac{268}{1000}\right)\) = 15.268 km
Distance travelled by her by car = 7 km 7 m = \(\left(7+\frac{7}{1000}\right)\) = 7.007 km
Distance travelled by her on foot = 500 m = \(\frac { 500 }{ 1000 }\) = 0.500 km
Total distance travelled by Sunita from her residence to school = 15.268 + 7.007 + 0.500 = 22.775 km
Question 7.
Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
Solution:
Weight of rice purchased by Ravi = 5 kg 400 g = 5 + \(\frac { 400 }{ 100 }\) = 5.400 kg
Weight of sugar purchased by him = 2 kg 20 g = 2 + \(\frac { 20 }{ 1000 }\) = 2.020 kg
Weight of flour purchased by him = 10 kg 850 g = 10 + \(\frac { 850 }{ 1000 }\) = 10.850 kg
∴ Total weight of his purchases = 5.400 kg + 2.020 kg + 10.850 kg = 18.270 kg