Well-designed AP 6th Class Maths Textbook Solutions Chapter 6 Integers Exercise 6.3 offers step-by-step explanations to help students understand problem-solving strategies.
Integers Class 6 Exercise 6.3 Solutions – 6th Class Maths 6.3 Exercise Solutions
Question 1.
Find:
a) 35 – (20)
Solution:
35 – (20)
35 + (-20) = 15
b) 72 – (90)
Solution:
72 – (90)
72 + (-90) = -18
c) (-15) – (-18)
Solution:
(-15) – (-18)
(-15) + 18 = 3
d) (-20) – (13)
Solution:
(-20) – (13)
(-20) + (-13) = -33
e) 23 – (-12)
Solution:
23 – (-12)
23 + (12) = 35
f) (-32) – (-40)
Solution:
(-32) – (-40)
(-32) + 40 = 8
Question 2.
Fill in the blanks with >, < or = sign.
a) (-3) + (-6) _____ (-3) – (-6)
Solution:
(-3) + (-6) _____(-3) – (-6).
[∵ -9 < (-3) + 6 = 3]
b) (-21) – (-10) _____(-31) + (-11)
Solution: (-21) – (-10) _____(-31) + (-11)
[∵ -21 + 10 = -11 > -42]
c) 45 – (-11)_____57 + (-4)
Solution:
45 – (-11)_____57 + (-4)
[∵ 45 + 11 = 56 > 53]
d) (-25) – (-42)_____(-42) – (-25)
Solution:
(-25) – (-42)_____(-42) – (-25)
[∵ (-25) + 42 = 17 > (-42) + 25 = -17]
Question 3.
Fill in the blanks.
a) (-8) + _____ = 0
Solution:
(-8) + 8 = 0
b) 13 +_____ = 0
Solution:
13 + (-13) = 0
c) 12 + (-12) = _____
Solution:
12 + (-12) = 0
d) (-4) + = -12
Solution:
(-4) + (-8) = -12
e) -15 = -10
Solution:
5 – 15 = -10
Question 4.
Find :
a) (-7) – 8 – (-25)
Solution:
(-7) – 8 – (-25)
= (-7) + (-8) + (25)
= (-15) + 25 = 10
b) (-13) + 32 – 8 – 1
Solution:
(-13) + 32 – 8 – 1
= (-13) + 32 + (-8) + (-1)
= (-22) + 32 = 10
c) (-7) + (-8) + (-90)
Solution:
(-7) + (-8) + (-90) = -105
d) 50 – (-40) – (-2)
Solution:
50 – (-40) – (-2)
= 50 + 40 + 2 = 92