Well-designed AP 6th Class Maths Solutions Chapter 3 Playing with Numbers Exercise 3.1 offers step-by-step explanations to help students understand problem-solving strategies.
Playing with Numbers Class 6 Exercise 3.1 Solutions – 6th Class Maths 3.1 Exercise Solutions
Question 1.
Write all the factors of the following numbers:
a) 24
Solution:
Factors of 24 are
24 = 1 × 24
24 = 2 × 12
24 = 3 × 8
24 = 4 × 6
Hence, all factors of 24 are 1, 2, 3, 4, 6, 8,12, 24.
b) 15
Solution:
Factors of 15 are:
15 = 1 × 15
15 = 3 × 5
Hence, all factors of 15 are 1,3,5,15.
c) 21
Solution:
Factors of 21 are :
21 = 1 × 21
21 = 3 × 7
Hence, all factors of 21 are 1, 3, 7, 21.
d) 27
Solution:
Factors of 27 are:
27 = 1 × 27
27 = 3 × 9
Hence, all the factors of 27 are 1,3 , 9, 27.
e) 12
Solution:
Factors of 12 are:
12 = 1 × 12
12 = 2 × 6
12 = 3 × 4
Hence, all the factors of 12 are 1,2,3,4,6,12.
f) 20
Solution:
Factors of 20 are:
20 = 1 × 20
20 = 2 × 10
20 = 4 × 5
Hence, all the factors of 20 are 1,2,4,5,10,20.
g) 18
Solution:
Factors of 18 are:
18 = 1 × 18
18 = 2 × 9
18 = 3 × 6
Hence, all the factors of 18 are 1,2,3,6,9,18.
h) 23
Solution:
Factors of 23 are: 23 = 1 × 23
Hence, all the factors of 23 are 1 and 23.
i) 36
Solution:
Factors of 36 are:
36 = 1 × 36
36 = 2 × 18
36 = 3 × 12
36 = 4 × 9
36 = 6 × 6
Hence, all the factors of 36 are 1,2,3,4,6,9,12,18,36.
Question 2.
Write first five multiples of :
a) 5
Solution:
First five multiples of 5 are :
5 × 1 = 5
5 × 2 = 10
5 × 3 = 15
5 × 4 = 20
5 × 5 = 25
Hence, the required multiples of 5 are 5,10,15,20,25
b) 8
Solution:
First five multiples of 8 are :
8 × 1 = 8
8 × 2 = 16
8 × 3 = 24
8 × 4 = 32
8 × 5 = 40
Hence, the required multiples of 8 are 8,16,24,32,40.
c) 9
Solution:
First five multiples of 9 are:
9 × 1 = 9
9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
Hence, the required multiples of 9 are 9,18,27,36,45.
Question 3.
Match the items in column 1 with the items in column 2.
Column 1 | Column 2 |
i) 35 | a) Multiple of 8 |
ii) 15 | b) Multiple of 7 |
iii) 16 | c) Multiple of 70 |
iv) 20 | d) Factor of 30 |
v) 25 | e) Factor of 50 |
f) Factor of 20 |
Solution:
i) – (b) (∵ 7 × 5 = 35)
ii) – (d) (∵ 15 × 2 = 30)
iii) – (a) (∵ 8 × 2 = 16)
iv) – (f) (∵ 20 × 1 = 20)
v) – (e) (∵ 25 × 2 = 50)
Question 4.
Find all the multiples of 9 upto 100.
Solution:
9 × 1 = 9
9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
9 × 6 = 54
9 × 7 = 63
9 × 8 = 72
9 × 9 = 81
9 × 10 = 90
9 × 11 = 99
Hence, all the multiples of 9 upto 100 are : 9,18,27,36,45,54,63,72,81,90,99.