Well-designed AP 6th Class Maths Solutions Chapter 1 Knowing Our Numbers Exercise 1.2 offers step-by-step explanations to help students understand problem-solving strategies.
Knowing Our Numbers Class 6 Exercise 1.2 Solutions – 6th Class Maths 1.2 Exercise Solutions
Question 1.
A book exhibition was held for four days In a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094, 1812, 2050 and 2751. Find the total number of tickets sold on all the four days.
Solution:
Question 2.
Shekhar is a famous cricket player. He has so far scored 6980 runs in test matches. He wishes to complete 10,000 runs. How many more runs does he need?
Solution:
Shekhar has far scored 6980 runs
He wishes to complete 10,000 runs.
∴ Total number of runs needed by him. 10,000 – 6980 = 3020 nuns.
Question 3.
In an election, the successful candidate registered 5,77,500 votes and his nearest rival secured 3,48,710 votes. By what margin did the successful candidate win the election?
Solution:
Question 4.
Kirti bookstore sold books worth ₹ 2,85,891 In the first week of June and books worth ₹ 4,00,768 in the second week of the month. How much was the sale for the two weeks together? In which week was the sale greater and by how much?
Solution:
Question 5.
Find the difference between the greatest and the least 5 digit number that can be written using the digits 6, 2, 7, 4,3 each only once.
Solution:
Given digits are 6, 2, 7, 4, 3
Question 6.
A machine, on an average, manufactures 2,823 screws a day. How many screws did it produce In the month of January 2006?
Solution:
Number of screws manufactured in a day = 2.825
Number of days in the month of January = 31
∴ Number of screws manufactured in the month January = 2,825 × 31 = 87,575
Question 7.
A merchant had ₹ 78,592 with her. She placed an order for purchasing 40 radio sets at ₹ 1200 each. How much money will remain with her after the purchase?
Solution:
Amount of money with merchant = ₹ 78,592
Number of radio sets = 40
Price of each radio set = ₹ 1200
∴ Cost of 4o radio sets = 1200 × 40 = ₹48,000
Remaining money with merchant after purchasing 40 radio sets = 78,592 – 48,000 = ₹30,592
Question 8.
A student multiplied 7236 by 65 Instead of multiplying by 56. By how much was his answer greater than the corred answer? (Hint : Do you need to do both the multi plications?)
Solution:
Student has multiplied 7236 by 65 Instead of multiplying by 56.
Hence, the answer greater than the correct answer is 65,124.
Question 9.
To stitch a shirt, 2 m 15 cm cloth is needed. Out of 40 m cloth, how many shirts can be stitched and how much cloth will remain? (Hint : convert data in cm.)
Solution:
Total length of the cloth = 40 m
= 40 × 100 cm = 4000 cm
Cloth needed to stitch a shirt
= 2 m 15 cm = 2 × 100 cm + 15 cm = 215 cm
∴ Number of shirts can be stitched = 4000 ÷ 215
∴ The number of shirts can be stitched = 18
and the remaining cloth = 130 cm = 1 m 30 cm
Question 10.
Medicine is packed in boxes, each weighing 4 kg 500 g. How many such boxes can be loaded in a van which cannot carry beyond 800 kg?
Solution:
Weight of one box = 4 kg 500 g
= 4 × 1000 + 500 = 4500 g
800 kg = 800 × 1000 = 800000 g
∴ Number of boxes can be loaded in a
van = 800000 ÷ 4500
∴ 177 boxes can only be loaded in the van.
Question 11.
The distance between the school and a student’s house is 1 km 875 m. Everyday she walks both ways. Find the total distance covered by her in six days.
Solution:
Distance between school and house = 1km 875 m = 1000 m + 875 m = 1875 m
Distance travelled by the student in both ways = 2 × 1875 = 3750 m
∴ Distance travelled in 6 days = 3750 m × 6 = 22500 m = 22 km 500 m.
Question 12.
A vessel has 4 litres and 500 ml of curd. In how many glasses, each of 25 ml capacity, can it be filled?
Solution:
Quantity of curd in a vessel = 4l 500 ml = 4 × 1000 + 500 = 4500 ml
Capacity of each glass = 25 ml
∴ Number of glasses = \(\frac { 4500 }{ 25 }\) = 180