Well-designed AP 6th Class Maths Guide Chapter 12 Ratio and Proportion Exercise 12.3 offers step-by-step explanations to help students understand problem-solving strategies.
Algebra Class 6 Exercise 12.3 Solutions – 6th Class Maths 12.3 Exercise Solutions
Question 1.
If the cost of 7 m of cloth is ₹ 147, find the cost of 5 m of cloth.
Solution:
Using unitary method, we have cost of 7 m of cloth = ₹ 1470
Cost of 1 m cloth = \(\frac{₹ 1470}{7}\)
Cost of 5 m cloth =
Thus, the required cost = ₹ 1050
Question 2.
Ekta earns ₹ 3000 in 10 days. How much will she earn in 30 days ?
Solution:
Money earned by Ekta in 10 days = ₹ 3000
Money earned by her in 1 day = \(₹\left[\frac{3000}{10}\right]\)
Money earned by Ekta in 30 days = 
Thus, money earned by Ekta in 30 days = ₹ 9000
Question 3.
If it has rained 276 mm in the last 3 days, how mahy cm of rain will fall in one full week (7 days) ? Assume that the rain continues to fall at the same rate.
Solution:
In last 3 days the rain falls = 276 mm
In 1 day the rain falls = \(\frac{276 mm}{3}\)
In 7 days the rain will fall
Question 4.
Cost of 5 kg of wheat is ₹ 91 : 50.
a) What will be the cost of 8 kg of wheat?
Solution:
Cost of 5 kg of wheat = ₹ 91.50
Cost of 1 kg of wheat = \(\frac{₹ 91.50}{5}\)
Cost of 8 kg of wheat = \(₹\left(\frac{91.50}{5} \times 8\right)\) = ₹ 146.40
Thus, the required cost = ₹ 146.40
b) What quantity of wheat can be purchased in ₹ 183 ?
Solution:
The quantity of wheat purchased in ₹ 91.50 = 5 kg
The quantity of wheat purchased in ₹ 1 = \(\frac{5}{91.50}\)
The quantity of wheat purchased in ₹ 183 = \(₹\left(\frac{5}{91.50} \times 183\right)\) = 10 kg
Thus, the required quantity of wheat = 10 kg
Question 5.
The temperature dropped 15 degree celsius in the last 30 days. If the rate of temperature drop. remains the same, how many degrees will the temperature drop in the next ten days?
Solution:
In last 30 days the quantity of drop in temperature = 15 degree celcius
In last 1 day the quantity of drop in temperature = \(\frac{15}{30}\) degree celcius
In last 10 days the quantity of drop in temperature =
= 5 degree celcius
Thus the required drop in temperature in last 10 days = 5 degree celcius.
Question 6.
Shaina pays ₹ 15000 as rent for 3 months. How much does she has to pay for a whole year, if the rent per month remains same ?
Solution:
Amount of rent paid in 3 months = ₹ 15000
Amount of rent paid in 1 month = \(₹\left(\frac{15000}{3}\right)\)
Amount of rent paid in whole year
Thus the amount of rent paid by Shaina whole year = ₹ 60,000
Question 7.
Cost of 4 dozen bananas is ₹ 180. How many bananas can be purchased for ₹ 90 ?
Solution:
1 dozen = 12 units
4 dones = (12 × 4) units = 48 units
4 dozen bananas = 48 bananas
₹ 180 is cost of 4 dozen = 12 × 4 = 48 bananas
₹ 1 is cost of = \(\frac { 48 }{ 180 }\)
Thus, the required number of bananas = 24 bananas.
Question 8.
The weight of 72 books is 97 kg. What is the weight of 40 such books?
Solution:
Weight of 72 books = 9 kg
Weight of 1 book = \(\frac { 9 }{ 72 }\) kg
∴ Weight of 40 books =
Hence, the required weight of 40 such books = 5 kg
Question 9.
A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km ?
Solution:
To cover 594 km. the amount of diesel required – 108 litres.
To cover 1 km, the amiount of diesel will be required = \(\frac { 108 }{ 594 }\) litres.
So, to cover 1650 km , the amount of diesel required = \(\frac { 108 }{ 594 }\) × 1650 = 300 litres.
Question 10.
Raju purchases 10 pens for ₹ 150 and Manish buys 7 pens for ₹ 84. Can you say who got the pens cheaper ?
Solution:
Thus, Manish got the pens cheaper than Raju.
Question 11.
Anish made 42 runs in 6 overs and Anup made 63 runs in 7 overs. Who made more runs per over?
Solution:
Anish:
Number of runs made by Anish in 6 overs = 42
Number of runs made by him in 1 over = \(\frac { 42 }{ 6 }\) = 7 runs
Anup:
Number of runs made by Anup in 7 overs = 63
Number of runs made by him in 1 over = \(\frac { 63 }{ 7 }\) = 9 runs > 7 runs
9 runs > 7 runs
Thus, Anup has made more runs per over.